Draw a six-carbon alkyne that can exist as diastereomers.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n A six-carbon alkyne that can exist as diastereomers<\/strong> is 3-hexene-1-yne<\/strong> with two different substituents on the double bond, but to truly have diastereomers, a better example is 3,4-hexadiene<\/strong> or 3,4-hexadiyne<\/strong>, but involving substituents<\/strong>.<\/p>\n\n\n\n However, a simpler correct answer for a six-carbon alkyne<\/strong> is 3-hexyn-2-ol<\/strong> or 4-hexyn-2-ol<\/strong>, because adding a chiral center allows for diastereomerism.<\/p>\n\n\n\n Thus, 4-hexyn-2-ol<\/strong> fits best:<\/p>\n\n\n\n This molecule can have two stereoisomers (R and S configurations at the chiral center at carbon 2), and those two stereoisomers are enantiomers<\/strong>. If you had two chiral centers<\/strong>, then different combinations (R,R), (R,S), etc., could give diastereomers<\/strong>.<\/p>\n\n\n\n To understand why 4-hexyn-2-ol<\/strong> can exist as diastereomers, you must first know what diastereomers<\/strong> are. Diastereomers are stereoisomers<\/strong> (same connectivity but different 3D arrangements) that are not mirror images<\/strong> of each other. This typically requires two or more chiral centers<\/strong>.<\/p>\n\n\n\n In a simple straight-chain alkyne<\/strong>, like hex-1-yne<\/strong> (CH\u2261C\u2013CH\u2082\u2013CH\u2082\u2013CH\u2082\u2013CH\u2083), there are no chiral centers \u2014 so no diastereomers. Therefore, to create diastereomers, the molecule must have at least one chiral center<\/strong> (and ideally more than one).<\/p>\n\n\n\n In 4-hexyn-2-ol<\/strong>, the hydroxyl group (-OH) is attached to the second carbon. This carbon is bonded to:<\/p>\n\n\n\n Since it is attached to four different groups, it is a chiral center<\/strong>. If you introduce another chiral center elsewhere (say, by adding different substituents along the chain), the molecule can form diastereomers<\/strong>.<\/p>\n\n\n\n Diastereomers<\/strong> differ in physical properties like boiling point, melting point, and solubility \u2014 unlike enantiomers<\/strong>, which only differ in the way they rotate plane-polarized light.<\/p>\n\n\n\n Thus, by designing a six-carbon alkyne like 4-hexyn-2-ol<\/strong>, we achieve a structure that has the potential for stereoisomerism. If further substitution occurs creating a second chiral center, true diastereomeric pairs can form.<\/p>\n\n\n\n Draw a six-carbon alkyne that can exist as diastereomers. The correct answer and explanation is : Correct Answer: A six-carbon alkyne that can exist as diastereomers is 3-hexene-1-yne with two different substituents on the double bond, but to truly have diastereomers, a better example is 3,4-hexadiene or 3,4-hexadiyne, but involving substituents. However, a simpler correct […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-208751","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/208751","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=208751"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/208751\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=208751"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=208751"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=208751"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Correct Answer:<\/h3>\n\n\n\n
CH\u2261C\u2013CH\u2082\u2013C(OH)\u2013CH\u2082\u2013CH\u2083<\/code><\/pre>\n\n\n\n
\n\n\n\nExplanation (about 300 words):<\/h3>\n\n\n\n
\n
\n","protected":false},"excerpt":{"rendered":"