{"id":209447,"date":"2025-04-29T05:55:26","date_gmt":"2025-04-29T05:55:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=209447"},"modified":"2025-04-29T05:55:27","modified_gmt":"2025-04-29T05:55:27","slug":"enter-the-formula-for-each-ionic-compounds","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/29\/enter-the-formula-for-each-ionic-compounds\/","title":{"rendered":"Enter the formula for each ionic compounds"},"content":{"rendered":"\n<p>Enter the formula for each ionic compounds. express your answer as a chemical formula.<\/p>\n\n\n\n<p>Lead(II) chromate<br>Iron (III) fluoride<br>Iron(II) phosphate<br>Potassium hydroxide<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s break down the chemical formulas for each of these ionic compounds, keeping in mind the charges of the ions involved.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Lead(II) Chromate:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula:<\/strong> PbCrO\u2084<\/li>\n<\/ul>\n\n\n\n<p><strong>Explanation:<\/strong><br>Lead(II) chromate is made up of lead ions with a +2 charge and chromate ions with a -2 charge. Lead(II) is denoted as Pb\u00b2\u207a, and chromate is represented by CrO\u2084\u00b2\u207b. Since both the lead ion and chromate ion have equal and opposite charges, they combine in a 1:1 ratio to form PbCrO\u2084.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Iron (III) Fluoride:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula:<\/strong> FeF\u2083<\/li>\n<\/ul>\n\n\n\n<p><strong>Explanation:<\/strong><br>Iron (III) fluoride is composed of iron(III) ions and fluoride ions. The iron(III) ion has a +3 charge (Fe\u00b3\u207a), and the fluoride ion has a -1 charge (F\u207b). To balance the charges, three fluoride ions are needed for every iron(III) ion. Therefore, the formula for iron (III) fluoride is FeF\u2083.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Iron (II) Phosphate:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula:<\/strong> Fe\u2083(PO\u2084)\u2082<\/li>\n<\/ul>\n\n\n\n<p><strong>Explanation:<\/strong><br>Iron(II) phosphate consists of iron(II) ions and phosphate ions. The iron(II) ion has a +2 charge (Fe\u00b2\u207a), and the phosphate ion has a -3 charge (PO\u2084\u00b3\u207b). To balance the charges, three iron(II) ions are needed to combine with two phosphate ions, resulting in the formula Fe\u2083(PO\u2084)\u2082.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">4. <strong>Potassium Hydroxide:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula:<\/strong> KOH<\/li>\n<\/ul>\n\n\n\n<p><strong>Explanation:<\/strong><br>Potassium hydroxide is made up of potassium ions (K\u207a) and hydroxide ions (OH\u207b). The potassium ion has a +1 charge, and the hydroxide ion has a -1 charge. Since the charges of the two ions are equal in magnitude but opposite in sign, they combine in a 1:1 ratio to form the formula KOH.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lead(II) Chromate:<\/strong> PbCrO\u2084<\/li>\n\n\n\n<li><strong>Iron(III) Fluoride:<\/strong> FeF\u2083<\/li>\n\n\n\n<li><strong>Iron(II) Phosphate:<\/strong> Fe\u2083(PO\u2084)\u2082<\/li>\n\n\n\n<li><strong>Potassium Hydroxide:<\/strong> KOH<\/li>\n<\/ul>\n\n\n\n<p>Each formula is determined by balancing the positive and negative charges of the ions involved, ensuring that the compound is electrically neutral.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Enter the formula for each ionic compounds. express your answer as a chemical formula. Lead(II) chromateIron (III) fluorideIron(II) phosphatePotassium hydroxide The correct answer and explanation is : Let&#8217;s break down the chemical formulas for each of these ionic compounds, keeping in mind the charges of the ions involved. 1. Lead(II) Chromate: Explanation:Lead(II) chromate is made [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-209447","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/209447","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=209447"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/209447\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=209447"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=209447"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=209447"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}