{"id":209499,"date":"2025-04-29T07:27:02","date_gmt":"2025-04-29T07:27:02","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=209499"},"modified":"2025-04-29T07:27:04","modified_gmt":"2025-04-29T07:27:04","slug":"choose-the-best-lewis-structure-for-xei2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/29\/choose-the-best-lewis-structure-for-xei2\/","title":{"rendered":"Choose the best Lewis structure for XeI2."},"content":{"rendered":"\n<p>Choose the best Lewis structure for XeI2.<\/p>\n\n\n\n<p>A)<br>B)<br>C)<br>D)<br>E)<\/p>\n\n\n\n<p>A): Xe\u2014I<\/p>\n\n\n\n<p>B): I=X=I<\/p>\n\n\n\n<p>C): I\u2014Xe\u2014I<\/p>\n\n\n\n<p>D): Xe<\/p>\n\n\n\n<p>E): I=Xe=I<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is:<br><strong>C) I\u2014Xe\u2014I<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300+ words):<\/strong><\/h3>\n\n\n\n<p>To determine the best Lewis structure for <strong>XeI\u2082 (xenon diiodide)<\/strong>, we need to follow standard steps for drawing Lewis structures and understanding the molecular geometry:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Count Valence Electrons:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Xenon (Xe):<\/strong> Group 18, has <strong>8 valence electrons<\/strong>.<\/li>\n\n\n\n<li><strong>Iodine (I):<\/strong> Group 17, has <strong>7 valence electrons<\/strong>, and there are <strong>2 iodine atoms<\/strong>.<br>\u2192 Total from Iodine: 7 \u00d7 2 = <strong>14 electrons<\/strong><\/li>\n\n\n\n<li><strong>Total valence electrons:<\/strong> 8 (Xe) + 14 (2 I) = <strong>22 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Determine the Skeleton:<\/strong><\/h3>\n\n\n\n<p>Since <strong>xenon<\/strong> is the least electronegative and can <strong>expand its octet<\/strong> (due to available d-orbitals), it will be the <strong>central atom<\/strong>.<\/p>\n\n\n\n<p>\u2192 Skeleton: <strong>I \u2014 Xe \u2014 I<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. Distribute Electrons:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Start by connecting the atoms with single bonds: I\u2014Xe\u2014I<\/li>\n\n\n\n<li>Each single bond uses 2 electrons \u00d7 2 bonds = <strong>4 electrons<\/strong><\/li>\n\n\n\n<li>Remaining electrons: 22 \u2212 4 = <strong>18 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Now, complete octets of the <strong>outer atoms (iodine)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each iodine needs 6 more electrons (3 lone pairs) to complete its octet.<\/li>\n\n\n\n<li>6 \u00d7 2 = 12 electrons for the iodines.<\/li>\n\n\n\n<li>Remaining electrons: 18 \u2212 12 = <strong>6 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Place the remaining <strong>6 electrons<\/strong> (3 lone pairs) on the <strong>central Xe atom<\/strong>.<\/p>\n\n\n\n<p>\u2192 Xe now has 2 bonding pairs + 3 lone pairs = <strong>10 electrons<\/strong> (which is acceptable since Xe can exceed the octet rule)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>4. Molecular Shape and Stability:<\/strong><\/h3>\n\n\n\n<p>The final Lewis structure is:<\/p>\n\n\n\n<p>\u2003\u2003\u2003\u2003I \u2014 Xe \u2014 I<br>\u2003\u2003\u2003\u2003\u2003\u2002..\u2003\u2002..<br>\u2003\u2003\u2003\u2003\u2002.. Xe ..<br>\u2003\u2003\u2003\u2003\u2003\u2002..\u2003\u2002..<\/p>\n\n\n\n<p>This gives <strong>5 electron domains<\/strong> around xenon (2 bonding, 3 lone pairs), which corresponds to a <strong>linear molecular geometry<\/strong> (AX\u2082E\u2083) according to VSEPR theory.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Why the Other Options Are Incorrect:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A)<\/strong>: Just Xe\u2014I (incomplete, missing one I)<\/li>\n\n\n\n<li><strong>B)<\/strong>: I=X=I suggests <strong>double bonds<\/strong>, which are incorrect and violate iodine&#8217;s typical bonding pattern<\/li>\n\n\n\n<li><strong>D)<\/strong>: Just Xe (no bonding shown)<\/li>\n\n\n\n<li><strong>E)<\/strong>: I=Xe=I suggests double bonds again, which is incorrect<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<p><strong>Option C (I\u2014Xe\u2014I)<\/strong> is the best Lewis structure for XeI\u2082, showing proper bonding, lone pairs, and satisfying octet\/expanded octet rules.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Choose the best Lewis structure for XeI2. A)B)C)D)E) A): Xe\u2014I B): I=X=I C): I\u2014Xe\u2014I D): Xe E): I=Xe=I The Correct Answer and Explanation is: The correct answer is:C) I\u2014Xe\u2014I Explanation (300+ words): To determine the best Lewis structure for XeI\u2082 (xenon diiodide), we need to follow standard steps for drawing Lewis structures and understanding the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-209499","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/209499","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=209499"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/209499\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=209499"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=209499"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=209499"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}