{"id":209661,"date":"2025-04-29T09:32:54","date_gmt":"2025-04-29T09:32:54","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=209661"},"modified":"2025-04-29T09:32:56","modified_gmt":"2025-04-29T09:32:56","slug":"determine-whether-the-conversion-of-iodide-ion-to-iodine-is-an-oxidation-or-a-reduction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/29\/determine-whether-the-conversion-of-iodide-ion-to-iodine-is-an-oxidation-or-a-reduction\/","title":{"rendered":"Determine whether the conversion of iodide ion to iodine is an oxidation or a reduction"},"content":{"rendered":"\n<p>Determine whether the conversion of iodide ion to iodine is an oxidation or a reduction.\u00a0<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><br>The conversion of iodide ion (I\u207b) to iodine (I\u2082) is an <strong>oxidation<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300+ words):<\/strong><\/h3>\n\n\n\n<p>In chemistry, <strong>oxidation<\/strong> and <strong>reduction<\/strong> are complementary processes that involve the transfer of electrons between substances. These processes are collectively referred to as <strong>redox reactions<\/strong>. Understanding whether a reaction is an oxidation or a reduction depends on changes in <strong>oxidation numbers<\/strong> (states) and the <strong>gain or loss of electrons<\/strong>.<\/p>\n\n\n\n<p>Let&#8217;s analyze the conversion of <strong>iodide ion (I\u207b)<\/strong> to <strong>iodine molecule (I\u2082)<\/strong>:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Iodide ion (I\u207b)<\/strong> is a negatively charged ion, meaning each iodide ion has gained <strong>one extra electron<\/strong>, giving it an oxidation number of <strong>-1<\/strong>.<\/li>\n\n\n\n<li>In contrast, elemental <strong>iodine (I\u2082)<\/strong> is a <strong>neutral diatomic molecule<\/strong>, and since it is in its elemental form, each iodine atom in I\u2082 has an oxidation number of <strong>0<\/strong>.<\/li>\n<\/ol>\n\n\n\n<p>To go from I\u207b to I\u2082, two iodide ions must lose electrons and combine:<br>[<br>2I\u207b \\rightarrow I\u2082 + 2e\u207b<br>]<\/p>\n\n\n\n<p>This equation shows that <strong>each iodide ion loses one electron<\/strong>, and two iodide ions come together to form one iodine molecule (I\u2082) by <strong>losing a total of two electrons<\/strong>.<\/p>\n\n\n\n<p>According to the definition of oxidation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Oxidation is the loss of electrons.<\/strong><\/li>\n\n\n\n<li><strong>Reduction is the gain of electrons.<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Since iodide ions <strong>lose electrons<\/strong> during the conversion to iodine, this is a clear example of <strong>oxidation<\/strong>. The electrons that are lost can then be gained by another species in the reaction, which undergoes <strong>reduction<\/strong> \u2014 hence the coupling of oxidation and reduction in redox reactions.<\/p>\n\n\n\n<p>This concept is critical in various fields, including <strong>electrochemistry<\/strong>, <strong>biochemistry<\/strong>, and <strong>industrial chemistry<\/strong>. For example, in the iodine clock reaction, iodide ions are oxidized to iodine, which reacts with starch to produce a blue color \u2014 a classic demonstration in many labs.<\/p>\n\n\n\n<p><strong>Summary:<\/strong><br>The conversion of I\u207b to I\u2082 involves <strong>electron loss<\/strong>, and any process involving the <strong>loss of electrons<\/strong> is an <strong>oxidation<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Determine whether the conversion of iodide ion to iodine is an oxidation or a reduction.\u00a0 The correct answer and explanation is : Correct Answer:The conversion of iodide ion (I\u207b) to iodine (I\u2082) is an oxidation. Explanation (300+ words): In chemistry, oxidation and reduction are complementary processes that involve the transfer of electrons between substances. These [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-209661","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/209661","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=209661"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/209661\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=209661"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=209661"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=209661"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}