{"id":210105,"date":"2025-04-29T18:12:36","date_gmt":"2025-04-29T18:12:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=210105"},"modified":"2025-04-29T18:12:38","modified_gmt":"2025-04-29T18:12:38","slug":"calculate-the-density-of-mercury-13-6-gem-in-units-of-kg-m","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/29\/calculate-the-density-of-mercury-13-6-gem-in-units-of-kg-m\/","title":{"rendered":"Calculate the density of mercury (13.6 g&#8217;em&#8217;) in units of kg\/m"},"content":{"rendered":"\n<p>Calculate the density of mercury (13.6 g&#8217;em&#8217;) in units of kg\/m<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To calculate the <strong>density of mercury<\/strong> in <strong>kg\/m\u00b3<\/strong>, we start with the given value in <strong>g\/cm\u00b3<\/strong>:<\/p>\n\n\n\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\">\n<p><strong>Given:<\/strong><br>Density of mercury = <strong>13.6 g\/cm\u00b3<\/strong><\/p>\n<\/blockquote>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Understand Unit Conversion<\/strong><\/h3>\n\n\n\n<p>We are converting from <strong>grams per cubic centimeter (g\/cm\u00b3)<\/strong> to <strong>kilograms per cubic meter (kg\/m\u00b3)<\/strong>.<\/p>\n\n\n\n<p>Let\u2019s break it down:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>1 kilogram = <strong>1,000 grams<\/strong><\/li>\n\n\n\n<li>1 meter = <strong>100 centimeters<\/strong><\/li>\n\n\n\n<li>So, 1 m\u00b3 = (100 cm)\u00b3 = <strong>1,000,000 cm\u00b3<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This gives us the conversion factor:<\/p>\n\n\n\n<p>[<br>1 \\text{ g\/cm}^3 = \\frac{1,000 \\text{ g}}{1 \\text{ kg}} \\times \\frac{1,000,000 \\text{ cm}^3}{1 \\text{ m}^3} = 1000 \\text{ kg\/m}^3<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Apply the Conversion<\/strong><\/h3>\n\n\n\n<p>[<br>13.6 \\text{ g\/cm}^3 \\times 1000 = 13,600 \\text{ kg\/m}^3<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>[<br>\\boxed{13,600 \\text{ kg\/m}^3}<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udd0d <strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p>Density is a fundamental physical property defined as the <strong>mass per unit volume<\/strong> of a substance. It tells us how tightly matter is packed together in a given space. The SI unit of density is <strong>kilograms per cubic meter (kg\/m\u00b3)<\/strong>, while in laboratory settings, it is often expressed in <strong>grams per cubic centimeter (g\/cm\u00b3)<\/strong>.<\/p>\n\n\n\n<p>In this problem, mercury&#8217;s density is given as <strong>13.6 g\/cm\u00b3<\/strong>, a relatively high value, reflecting its heaviness even in small volumes\u2014this is why mercury feels much heavier than water for the same volume.<\/p>\n\n\n\n<p>To convert between g\/cm\u00b3 and kg\/m\u00b3, we need to understand the relationship between the units:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since 1 kg = 1,000 g, and<\/li>\n\n\n\n<li>1 m\u00b3 = 1,000,000 cm\u00b3,<br>we can conclude that:<\/li>\n\n\n\n<li>1 g\/cm\u00b3 = 1,000 kg\/m\u00b3<\/li>\n<\/ul>\n\n\n\n<p>Thus, when we multiply the given density of mercury (13.6 g\/cm\u00b3) by 1,000, we get <strong>13,600 kg\/m\u00b3<\/strong>.<\/p>\n\n\n\n<p>This high density makes mercury useful in instruments like barometers and thermometers. Because it is so dense, even small volumes can exert noticeable pressure, making it ideal for measuring atmospheric pressure or temperature changes with precision.<\/p>\n\n\n\n<p>Understanding unit conversion is critical in science and engineering, as different fields use different measurement systems. Converting correctly ensures accurate communication of data and avoids errors in calculation or design.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the density of mercury (13.6 g&#8217;em&#8217;) in units of kg\/m The correct answer and explanation is : To calculate the density of mercury in kg\/m\u00b3, we start with the given value in g\/cm\u00b3: Given:Density of mercury = 13.6 g\/cm\u00b3 Step 1: Understand Unit Conversion We are converting from grams per cubic centimeter (g\/cm\u00b3) to [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-210105","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210105","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=210105"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210105\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=210105"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=210105"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=210105"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}