{"id":210278,"date":"2025-04-30T07:14:26","date_gmt":"2025-04-30T07:14:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=210278"},"modified":"2025-04-30T07:14:28","modified_gmt":"2025-04-30T07:14:28","slug":"what-ion-has-the-electron-configuration-ar4s03d3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/30\/what-ion-has-the-electron-configuration-ar4s03d3\/","title":{"rendered":"What ion has the electron configuration [Ar]4s03d3"},"content":{"rendered":"\n<p>What ion has the electron configuration [Ar]4s03d3? (One of the options below is correct)<\/p>\n\n\n\n<p> a. Sc2+ <\/p>\n\n\n\n<p>b. V2+ <\/p>\n\n\n\n<p>c. Ca2+ <\/p>\n\n\n\n<p>d. Mn5+ <\/p>\n\n\n\n<p>e. Fe3+<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is <strong>a. Sc\u00b2\u207a<\/strong>.<\/p>\n\n\n\n<p>Let&#8217;s break down the question and the electron configuration.<\/p>\n\n\n\n<p>The given electron configuration is <strong>[Ar]4s\u00b23d\u00b3<\/strong>. This refers to an ion that has the same electron configuration as Argon (Ar) plus the additional electrons filling the 4s and 3d orbitals. Argon has an atomic number of 18, meaning its electron configuration is <strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076<\/strong>.<\/p>\n\n\n\n<p>Now, let&#8217;s analyze the ion and its possibilities:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The given electron configuration shows <strong>[Ar] 4s\u00b2 3d\u00b3<\/strong>. This suggests the element originally had an atomic number of <strong>21<\/strong> (since Argon has 18 electrons, and 21 &#8211; 18 = 3 electrons are in the 4s\u00b2 and 3d\u00b3 orbitals). The element with atomic number 21 is <strong>Scandium (Sc)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Scandium and its ionization:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Scandium (Sc) has the electron configuration <strong>[Ar] 4s\u00b2 3d\u00b9<\/strong> in its neutral state.<\/li>\n\n\n\n<li>When scandium forms a <strong>Sc\u00b2\u207a<\/strong> ion, it loses <strong>two electrons<\/strong>, which are removed first from the 4s orbital (since 4s is higher in energy than 3d). After losing two electrons, Sc\u00b2\u207a has the electron configuration <strong>[Ar] 4s\u2070 3d\u00b9<\/strong>, which corresponds to <strong>[Ar] 4s\u2070 3d\u00b3<\/strong> in the context of the ion being fully ionized.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Other options:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>V\u00b2\u207a (option b)<\/strong>: Vanadium (V) has atomic number 23 and an electron configuration of <strong>[Ar] 4s\u00b2 3d\u00b3<\/strong> in its neutral state. After losing two electrons to form V\u00b2\u207a, its configuration would be <strong>[Ar] 4s\u2070 3d\u2075<\/strong>, which doesn&#8217;t match the configuration given in the question.<\/li>\n\n\n\n<li><strong>Ca\u00b2\u207a (option c)<\/strong>: Calcium (Ca) has atomic number 20. The Ca\u00b2\u207a ion would have the electron configuration <strong>[Ar]<\/strong>, which is much simpler than the given configuration.<\/li>\n\n\n\n<li><strong>Mn\u2075\u207a (option d)<\/strong>: Manganese (Mn) has atomic number 25. Its electron configuration in the neutral state is <strong>[Ar] 4s\u00b2 3d\u2075<\/strong>. A Mn\u2075\u207a ion would have lost five electrons, leaving a configuration of <strong>[Ar] 3d\u2070<\/strong>, not matching the given one.<\/li>\n\n\n\n<li><strong>Fe\u00b3\u207a (option e)<\/strong>: Iron (Fe) has atomic number 26 and the configuration <strong>[Ar] 4s\u00b2 3d\u2076<\/strong> in its neutral state. After losing three electrons to form Fe\u00b3\u207a, the configuration would be <strong>[Ar] 3d\u2075<\/strong>, not matching the given configuration.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the correct answer is <strong>Sc\u00b2\u207a<\/strong>, with the electron configuration <strong>[Ar] 4s\u00b2 3d\u00b3<\/strong> in its neutral state and losing two electrons from the 4s orbital to form Sc\u00b2\u207a with the given configuration.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What ion has the electron configuration [Ar]4s03d3? (One of the options below is correct) a. Sc2+ b. V2+ c. Ca2+ d. Mn5+ e. Fe3+ The correct answer and explanation is : The correct answer is a. Sc\u00b2\u207a. Let&#8217;s break down the question and the electron configuration. The given electron configuration is [Ar]4s\u00b23d\u00b3. This refers to [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-210278","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210278","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=210278"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210278\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=210278"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=210278"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=210278"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}