{"id":210404,"date":"2025-04-30T09:13:01","date_gmt":"2025-04-30T09:13:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=210404"},"modified":"2025-04-30T09:13:03","modified_gmt":"2025-04-30T09:13:03","slug":"a-body-temperature-of-96-5-degree-f-given-that-human-body-temperatures-have-a-mean-of-98-20-degree-f-and-a-standard-deviation-of-0-62-degree","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/30\/a-body-temperature-of-96-5-degree-f-given-that-human-body-temperatures-have-a-mean-of-98-20-degree-f-and-a-standard-deviation-of-0-62-degree\/","title":{"rendered":"A body temperature of 96.5 degree F given that human body temperatures have a mean of 98.20 degree F and a standard deviation of 0.62 degree"},"content":{"rendered":"\n<p>A body temperature of 96.5 degree F given that human body temperatures have a mean of 98.20 degree F and a standard deviation of 0.62 degree. <\/p>\n\n\n\n<p>A) -1.7: not usual <\/p>\n\n\n\n<p>B) 2.7: unusual <\/p>\n\n\n\n<p>C) -2.7: not unusual <\/p>\n\n\n\n<p>D) -2.7: unusual<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine if a body temperature of 96.5\u00b0F is unusual, we can use the concept of <strong>z-scores<\/strong>. A <strong>z-score<\/strong> represents how many standard deviations a data point is from the mean. The formula for calculating the z-score is:<\/p>\n\n\n\n<p>[<br>z = \\frac{X &#8211; \\mu}{\\sigma}<br>]<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>( X ) is the data point (in this case, 96.5\u00b0F),<\/li>\n\n\n\n<li>( \\mu ) is the mean (in this case, 98.2\u00b0F),<\/li>\n\n\n\n<li>( \\sigma ) is the standard deviation (in this case, 0.62\u00b0F).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Calculate the z-score<\/h3>\n\n\n\n<p>Substitute the given values into the formula:<\/p>\n\n\n\n<p>[<br>z = \\frac{96.5 &#8211; 98.2}{0.62} = \\frac{-1.7}{0.62} \\approx -2.74<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Interpret the z-score<\/h3>\n\n\n\n<p>A z-score of approximately <strong>-2.7<\/strong> means that the body temperature of 96.5\u00b0F is <strong>2.7 standard deviations below the mean<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Assess whether it is usual or unusual<\/h3>\n\n\n\n<p>In statistics, data points that are more than <strong>2 standard deviations<\/strong> away from the mean (either above or below) are generally considered <strong>unusual<\/strong>. Specifically:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A z-score between <strong>-2 and +2<\/strong> is considered &#8220;usual&#8221; or &#8220;within normal range.&#8221;<\/li>\n\n\n\n<li>A z-score outside this range (i.e., below -2 or above +2) is considered &#8220;unusual&#8221; or &#8220;extreme.&#8221;<\/li>\n<\/ul>\n\n\n\n<p>Since the z-score here is <strong>-2.7<\/strong>, which is beyond the -2 threshold, this body temperature of 96.5\u00b0F is considered <strong>unusual<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Conclusion<\/h3>\n\n\n\n<p>The correct answer is <strong>D) -2.7: unusual<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>A body temperature of 96.5\u00b0F is significantly lower than the average body temperature of 98.2\u00b0F. This result indicates that the temperature falls outside the usual range of normal human body temperatures, suggesting a potential health concern, such as hypothermia or another condition that could lower body temperature. When temperatures fall more than 2 standard deviations away from the mean, they are typically regarded as unusual, and further investigation might be warranted.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A body temperature of 96.5 degree F given that human body temperatures have a mean of 98.20 degree F and a standard deviation of 0.62 degree. A) -1.7: not usual B) 2.7: unusual C) -2.7: not unusual D) -2.7: unusual The correct answer and explanation is : To determine if a body temperature of 96.5\u00b0F [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-210404","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210404","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=210404"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210404\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=210404"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=210404"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=210404"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}