Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.250 M Ba(OH)2 solution. Explain briefly.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n To determine the concentration of each ion in a 0.250 M Ba(OH)\u2082 solution, it’s essential to recognize the dissociation process of Ba(OH)\u2082 in water.<\/p>\n\n\n\n Barium hydroxide (Ba(OH)\u2082) is a strong electrolyte, meaning it dissociates completely in water. The dissociation equation for Ba(OH)\u2082 is as follows:<\/p>\n\n\n\n [ \\text{Ba(OH)}_2 \\rightarrow \\text{Ba}^{2+} + 2\\text{OH}^- ]<\/p>\n\n\n\n This equation shows that one formula unit of Ba(OH)\u2082 dissociates into one Ba\u00b2\u207a ion and two OH\u207b ions.<\/p>\n\n\n\n The concentration of Ba(OH)\u2082 is given as 0.250 M. Since one Ba(OH)\u2082 molecule dissociates into one Ba\u00b2\u207a ion, the concentration of Ba\u00b2\u207a ions will be equal to the concentration of Ba(OH)\u2082. Thus, the concentration of Ba\u00b2\u207a is:<\/p>\n\n\n\n [ [\\text{Ba}^{2+}] = 0.250 \\, \\text{M} ]<\/p>\n\n\n\n From the dissociation equation, we can see that for every 1 mole of Ba(OH)\u2082 that dissociates, 2 moles of OH\u207b ions are produced. Therefore, the concentration of OH\u207b ions will be twice the concentration of Ba(OH)\u2082:<\/p>\n\n\n\n [ [\\text{OH}^-] = 2 \\times [\\text{Ba(OH)}_2] = 2 \\times 0.250 \\, \\text{M} = 0.500 \\, \\text{M} ]<\/p>\n\n\n\n The strong electrolyte nature of Ba(OH)\u2082 means it dissociates completely in water, releasing ions in a 1:2 ratio of Ba\u00b2\u207a to OH\u207b. The concentration of Ba\u00b2\u207a is directly equal to the initial concentration of Ba(OH)\u2082, while the concentration of OH\u207b is twice that value, because each formula unit of Ba(OH)\u2082 produces two OH\u207b ions.<\/p>\n","protected":false},"excerpt":{"rendered":" Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.250 M Ba(OH)2 solution. Explain briefly. The correct answer and explanation is : To determine the concentration of each ion in a 0.250 M Ba(OH)\u2082 solution, it’s essential to recognize the dissociation process of Ba(OH)\u2082 in water. Step 1: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-210762","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210762","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=210762"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/210762\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=210762"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=210762"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=210762"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Write the Dissociation Equation<\/h3>\n\n\n\n
Step 2: Concentration of Ba\u00b2\u207a Ions<\/h3>\n\n\n\n
Step 3: Concentration of OH\u207b Ions<\/h3>\n\n\n\n
Final Answer:<\/h3>\n\n\n\n
\n
Explanation:<\/h3>\n\n\n\n