{"id":210798,"date":"2025-05-02T07:37:20","date_gmt":"2025-05-02T07:37:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=210798"},"modified":"2025-05-02T07:37:22","modified_gmt":"2025-05-02T07:37:22","slug":"cross-a-homozygous-running","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/02\/cross-a-homozygous-running\/","title":{"rendered":"Cross a homozygous running"},"content":{"rendered":"\n<p>Cross a homozygous running, homozygous black mouse with a heterozygous running, brown mouse<\/p>\n\n\n\n<p>Parental genotypes <strong>_<\/strong><\/p>\n\n\n\n<p>Possible gametes <strong>_<\/strong><\/p>\n\n\n\n<p>Offspring phenotypic ratio <em>_<\/em><\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s break down the genetic scenario involving the two mice with different traits:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Parental Genotypes:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Homozygous running, homozygous black mouse<\/strong>: This mouse is <strong>RRBB<\/strong>. The capital &#8220;R&#8221; represents the dominant allele for the running trait, and the capital &#8220;B&#8221; represents the dominant allele for black fur color. Since it\u2019s homozygous, both alleles are the same.<\/li>\n\n\n\n<li><strong>Heterozygous running, brown mouse<\/strong>: This mouse is <strong>Rrbb<\/strong>. &#8220;Rr&#8221; means that it is heterozygous for the running trait (one dominant allele and one recessive allele), and &#8220;bb&#8221; means it is homozygous recessive for brown fur color.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Possible Gametes:<\/h3>\n\n\n\n<p>To find the possible gametes produced by each parent, we will use a basic Punnett square approach.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Homozygous running, black mouse (RRBB)<\/strong> can produce the following gametes: <strong>RB<\/strong>. Since both alleles are the same, the only gametes it can produce are <strong>RB<\/strong>.<\/li>\n\n\n\n<li><strong>Heterozygous running, brown mouse (Rrbb)<\/strong> can produce the following gametes: <strong>Rb<\/strong> and <strong>rb<\/strong>. Since &#8220;R&#8221; and &#8220;r&#8221; are different alleles, the possible combinations are <strong>Rb<\/strong> (dominant running trait, recessive brown fur) and <strong>rb<\/strong> (recessive for both traits).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Punnett Square:<\/h3>\n\n\n\n<p>Let\u2019s combine the gametes from both parents:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th><\/th><th><strong>RB<\/strong><\/th><th><strong>RB<\/strong><\/th><\/tr><\/thead><tbody><tr><td><strong>Rb<\/strong><\/td><td><strong>RRBb<\/strong><\/td><td><strong>RRBb<\/strong><\/td><\/tr><tr><td><strong>rb<\/strong><\/td><td><strong>RrBb<\/strong><\/td><td><strong>RrBb<\/strong><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">Offspring Phenotypic Ratio:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Running trait (R)<\/strong> is dominant over the recessive (r), so any offspring with at least one <strong>R<\/strong> will be running.<\/li>\n\n\n\n<li><strong>Fur color<\/strong>: <strong>B<\/strong> (black) is dominant over <strong>b<\/strong> (brown). So, only <strong>bb<\/strong> individuals will have brown fur, while any other combination (such as <strong>Bb<\/strong>) will result in black fur.<\/li>\n<\/ul>\n\n\n\n<p>From the Punnett square, we see:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>RRBb<\/strong> (2 offspring) = <strong>Running<\/strong>, <strong>Black<\/strong><\/li>\n\n\n\n<li><strong>RrBb<\/strong> (2 offspring) = <strong>Running<\/strong>, <strong>Black<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>Phenotypic ratio<\/strong>: All 4 offspring will be <strong>Running<\/strong>, <strong>Black<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Parental genotypes<\/strong>: RRBB \u00d7 Rrbb<\/li>\n\n\n\n<li><strong>Possible gametes<\/strong>: RB \u00d7 Rb, rb<\/li>\n\n\n\n<li><strong>Offspring phenotypic ratio<\/strong>: 100% <strong>Running, Black<\/strong><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Cross a homozygous running, homozygous black mouse with a heterozygous running, brown mouse Parental genotypes _ Possible gametes _ Offspring phenotypic ratio _ The correct answer and explanation is : Let&#8217;s break down the genetic scenario involving the two mice with different traits: Parental Genotypes: Possible Gametes: To find the possible gametes produced by each [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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