{"id":211663,"date":"2025-05-05T00:22:55","date_gmt":"2025-05-05T00:22:55","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=211663"},"modified":"2025-05-05T00:22:57","modified_gmt":"2025-05-05T00:22:57","slug":"what-is-the-molecular-shape-of-c2hcl-and-is-it-polar-or-nonpolar","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/05\/what-is-the-molecular-shape-of-c2hcl-and-is-it-polar-or-nonpolar\/","title":{"rendered":"What is the molecular shape of c2hcl and is it polar or nonpolar"},"content":{"rendered":"\n<p>What is the molecular shape of c2hcl and is it polar or nonpolar?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molecular Shape of C\u2082HCl<\/strong>: <strong>Trigonal planar (around the central atoms)<\/strong><\/li>\n\n\n\n<li><strong>Polarity<\/strong>: <strong>Polar<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation (\u2248300 words):<\/h3>\n\n\n\n<p><strong>C\u2082HCl<\/strong>, also known as <strong>chloroethyne<\/strong>, is a compound with the molecular formula: <strong>HC\u2261C\u2013Cl<\/strong>. It is derived from ethyne (acetylene), where one hydrogen atom is replaced with a chlorine atom. To understand its <strong>molecular shape and polarity<\/strong>, we need to examine its <strong>structure, geometry, and electronegativity differences<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Lewis Structure and Bonding:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The molecule consists of two carbon atoms connected by a <strong>triple bond<\/strong>.<\/li>\n\n\n\n<li>One hydrogen atom is bonded to the first carbon (C1).<\/li>\n\n\n\n<li>The second carbon (C2) is bonded to a chlorine atom.<\/li>\n<\/ul>\n\n\n\n<p>Structure:<br><strong>H\u2013C\u2261C\u2013Cl<\/strong><\/p>\n\n\n\n<p>Each carbon makes four bonds:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>C1: One single bond to H and a triple bond to C2.<\/li>\n\n\n\n<li>C2: A triple bond to C1 and a single bond to Cl.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Molecular Shape (Geometry):<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Around each carbon atom, the electron geometry is <strong>linear<\/strong> due to the triple bond (sp hybridization).<\/li>\n\n\n\n<li>So, the entire molecule <strong>H\u2013C\u2261C\u2013Cl<\/strong> is <strong>linear<\/strong> in shape.<\/li>\n\n\n\n<li>There are no lone pairs on the carbon atoms to distort the geometry.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. Polarity:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>To determine polarity, we examine the <strong>electronegativity<\/strong> of the atoms:\n<ul class=\"wp-block-list\">\n<li>H (2.1), C (2.5), Cl (3.0)<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>The <strong>C\u2013Cl bond<\/strong> is <strong>polar<\/strong> due to the difference in electronegativity between C and Cl.<\/li>\n\n\n\n<li>The <strong>C\u2013H bond<\/strong> is considered weakly polar, but in this case, its effect is negligible compared to C\u2013Cl.<\/li>\n<\/ul>\n\n\n\n<p>Because of the <strong>asymmetric distribution of electrons<\/strong> (Cl is more electronegative and pulls electron density), the molecule has a <strong>net dipole moment<\/strong>, making <strong>C\u2082HCl a polar molecule<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>shape<\/strong> of C\u2082HCl is <strong>linear<\/strong>.<\/li>\n\n\n\n<li>The molecule is <strong>polar<\/strong> due to the unequal electron sharing between carbon and chlorine, resulting in a <strong>net dipole moment<\/strong>.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>What is the molecular shape of c2hcl and is it polar or nonpolar? The Correct Answer and Explanation is: Correct Answer: Detailed Explanation (\u2248300 words): C\u2082HCl, also known as chloroethyne, is a compound with the molecular formula: HC\u2261C\u2013Cl. It is derived from ethyne (acetylene), where one hydrogen atom is replaced with a chlorine atom. To [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-211663","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211663","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=211663"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211663\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=211663"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=211663"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=211663"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}