{"id":211743,"date":"2025-05-05T07:16:24","date_gmt":"2025-05-05T07:16:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=211743"},"modified":"2025-05-05T07:16:26","modified_gmt":"2025-05-05T07:16:26","slug":"a-string-of-christmas-lights-contains-20-lights","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/05\/a-string-of-christmas-lights-contains-20-lights\/","title":{"rendered":"A string of Christmas lights contains 20 lights"},"content":{"rendered":"\n<p>A string of Christmas lights contains 20 lights. The lights are wired in series, so that if any light fails, the whole string will go dark. Each light has probability 0.98 of working for a 3-year period. The lights fail independently of each other. Find the probability that the string of lights will remain bright for 3 years.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find the probability that the entire string of 20 Christmas lights stays lit for 3 years, we need to calculate the probability that <strong>all 20 lights work<\/strong> during that period.<\/p>\n\n\n\n<p>Each light has a <strong>0.98 probability<\/strong> of working for 3 years, and the lights are <strong>wired in series<\/strong>, meaning <strong>if any one fails, the entire string fails<\/strong>.<\/p>\n\n\n\n<p>Because the lights fail <strong>independently<\/strong>, the probability that <strong>all 20 lights work<\/strong> is the product of their individual probabilities: P(All&nbsp;20&nbsp;lights&nbsp;work)=(0.98)20P(\\text{All 20 lights work}) = (0.98)^{20} P=0.9820\u22480.6676P = 0.98^{20} \\approx 0.6676<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer: <strong>0.6676<\/strong> (or about <strong>66.76%<\/strong>)<\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udcd8 Explanation (300+ words):<\/h3>\n\n\n\n<p>This problem revolves around <strong>compound probability<\/strong> and <strong>independent events<\/strong>. Each of the 20 lights has a <strong>98% chance<\/strong> of operating without failure for a 3-year period. Because they are connected <strong>in series<\/strong>, if even <strong>one light fails<\/strong>, the entire string goes dark. This is a classic reliability issue in systems engineering.<\/p>\n\n\n\n<p>When events are <strong>independent<\/strong>, the probability of all events happening is the product of their individual probabilities. Here, we&#8217;re interested in the event that <strong>all 20 lights function properly<\/strong>, so we calculate: P=(0.98)\u00d7(0.98)\u00d7\u22ef(20&nbsp;times)=0.9820P = (0.98) \\times (0.98) \\times \\cdots \\text{(20 times)} = 0.98^{20}<\/p>\n\n\n\n<p>This results in: P=0.9820\u22480.6676P = 0.98^{20} \\approx 0.6676<\/p>\n\n\n\n<p>This means there is about a <strong>66.76% chance<\/strong> that all 20 lights will remain functional over the 3-year period. Conversely, there&#8217;s about a <strong>33.24% chance<\/strong> that <strong>at least one light<\/strong> will fail, making the whole string go dark.<\/p>\n\n\n\n<p>This type of scenario highlights a <strong>weakness of series circuits<\/strong> in real-life applications. Even though each individual component has a high reliability (98% is quite good), the overall system reliability drops significantly as more components are added. That\u2019s why modern light strings often use <strong>parallel wiring<\/strong>, where one failed bulb does not affect the others.<\/p>\n\n\n\n<p>In summary, due to the compounding effect of multiple independent failure points in a series system, even small failure probabilities can drastically reduce overall system reliability over time. This is an essential concept in both electrical design and probability theory.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A string of Christmas lights contains 20 lights. The lights are wired in series, so that if any light fails, the whole string will go dark. Each light has probability 0.98 of working for a 3-year period. The lights fail independently of each other. Find the probability that the string of lights will remain bright [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-211743","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211743","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=211743"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211743\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=211743"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=211743"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=211743"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}