Which of the following is\/are true? Select all that apply.<\/p>\n\n\n\n
SF4 is a polar molecule and has a seesaw molecular geometry
The strongest intermolecular force in KBr(aq) is ion-dipole forces
BF3 is a nonpolar molecule and has a trigonal planar molecular geometry
CH3CHO is polar; there are dipole-dipole forces and dispersion forces between two CH3CHO molecules, but no hydrogen bonding<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct statements are:<\/p>\n\n\n\n \u2705 SF\u2084 is a polar molecule and has a seesaw molecular geometry<\/strong> 1. SF\u2084 (Sulfur Tetrafluoride):<\/strong> 2. KBr(aq):<\/strong> 3. BF\u2083 (Boron Trifluoride):<\/strong> 4. CH\u2083CHO (Acetaldehyde):<\/strong> All statements are TRUE.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Which of the following is\/are true? Select all that apply. SF4 is a polar molecule and has a seesaw molecular geometryThe strongest intermolecular force in KBr(aq) is ion-dipole forcesBF3 is a nonpolar molecule and has a trigonal planar molecular geometryCH3CHO is polar; there are dipole-dipole forces and dispersion forces between two CH3CHO molecules, but no […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-211932","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211932","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=211932"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211932\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=211932"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=211932"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=211932"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\u2705 The strongest intermolecular force in KBr(aq) is ion-dipole forces<\/strong>
\u2705 BF\u2083 is a nonpolar molecule and has a trigonal planar molecular geometry<\/strong>
\u2705 CH\u2083CHO is polar; there are dipole-dipole forces and dispersion forces between two CH\u2083CHO molecules, but no hydrogen bonding<\/strong><\/p>\n\n\n\n
\n\n\n\nExplanation (\u2248300 words)<\/h3>\n\n\n\n
SF\u2084 has 5 regions of electron density (4 bonding pairs and 1 lone pair) around the sulfur atom, based on VSEPR theory. This results in a seesaw molecular geometry<\/strong>. Due to the lone pair and the asymmetrical distribution of fluorine atoms, the dipole moments do not cancel, making SF\u2084 a polar molecule<\/strong>.
\u2705 True<\/strong><\/p>\n\n\n\n
KBr is an ionic compound that dissociates into K\u207a and Br\u207b ions in aqueous solution. Water is a polar solvent, and the interactions between the K\u207a\/Br\u207b ions and the partial charges on water molecules are called ion-dipole forces<\/strong>, which are stronger than hydrogen bonding or dipole-dipole interactions in this context.
\u2705 True<\/strong><\/p>\n\n\n\n
BF\u2083 has three bonding pairs and no lone pairs on the central boron atom. This leads to a trigonal planar geometry<\/strong>, and because all three B\u2013F bonds are identical and 120\u00b0 apart, the molecule is symmetrical<\/strong>. Though each B\u2013F bond is polar, the dipole moments cancel out, making BF\u2083 a nonpolar molecule<\/strong>.
\u2705 True<\/strong><\/p>\n\n\n\n
This molecule has a polar C=O group, making the entire molecule polar<\/strong>. It can engage in dipole-dipole<\/strong> and dispersion (London dispersion) forces<\/strong>. However, hydrogen bonding does not occur<\/strong> between CH\u2083CHO molecules because although the molecule has a hydrogen, it is not bonded directly to a highly electronegative atom like N, O, or F.
\u2705 True<\/strong><\/p>\n\n\n\n
\n\n\n\nFinal Answer:<\/h3>\n\n\n\n