{"id":211954,"date":"2025-05-05T12:38:42","date_gmt":"2025-05-05T12:38:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=211954"},"modified":"2025-05-05T12:38:44","modified_gmt":"2025-05-05T12:38:44","slug":"the-electron-configuration-of-a-ground-state-ag-atom-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/05\/the-electron-configuration-of-a-ground-state-ag-atom-is\/","title":{"rendered":"The electron configuration of a ground-state Ag atom is"},"content":{"rendered":"\n<p>The electron configuration of a ground-state Ag atom is<br>A) [Ar]4s24d9<br>B) [Kr]5s14d10<br>C) [Ar]4s14d10<br>D) [Kr]5s23d9<br>E) [Kr]5s24d10<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is <strong>A) [Ar]4s\u00b24d\u2079<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Silver (Ag) has an atomic number of <strong>47<\/strong>, which means it has <strong>47 electrons<\/strong> in its ground-state configuration. To determine the correct electron configuration, we can follow the Aufbau principle, Hund&#8217;s rule, and the Pauli exclusion principle.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Starting from the core configuration:<\/strong><br>Silver belongs to period 5 of the periodic table, and the preceding noble gas in its period is <strong>Argon (Ar)<\/strong>, which has an atomic number of 18. So, the electron configuration of silver will start with the configuration of Argon:<br><strong>[Ar]<\/strong>.<\/li>\n\n\n\n<li><strong>Next, we fill the remaining electrons:<\/strong><br>After Argon, we begin filling the next available orbitals, which are in the 4th and 5th shells. The sequence of orbitals to fill is 4s, 4p, 4d, and 5s.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>First, we fill the <strong>4s orbital<\/strong>. Since the 4s orbital can hold up to two electrons, we place <strong>2 electrons<\/strong> in the 4s orbital.<\/li>\n\n\n\n<li>Then, we move to the <strong>4d orbital<\/strong>. The 4d orbital can hold up to 10 electrons, but in the case of silver, it only needs <strong>9 electrons<\/strong> to complete its electron configuration.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Final Configuration:<\/strong><br>Combining the noble gas core configuration and the remaining electrons in the 4s and 4d orbitals, the electron configuration of a ground-state silver atom is:<br><strong>[Ar] 4s\u00b2 4d\u2079<\/strong>.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Why not the other options?<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>B) [Kr]5s\u00b94d\u00b9\u2070:<\/strong> This configuration corresponds to the electron arrangement for <strong>palladium (Pd)<\/strong>, not silver. Palladium has atomic number 46, and its 4d subshell is fully filled with 10 electrons (5s\u00b94d\u00b9\u2070).<\/li>\n\n\n\n<li><strong>C) [Ar]4s\u00b94d\u00b9\u2070:<\/strong> This configuration doesn&#8217;t represent silver in its ground state. If the electron were in the 4s\u00b9 orbital, it would imply the atom is in an excited state, not a ground state.<\/li>\n\n\n\n<li><strong>D) [Kr]5s\u00b23d\u2079:<\/strong> This is the electron configuration for <strong>copper (Cu)<\/strong>, which has an atomic number of 29. Copper&#8217;s configuration is [Ar] 4s\u00b9 3d\u00b9\u2070, not this.<\/li>\n\n\n\n<li><strong>E) [Kr]5s\u00b24d\u00b9\u2070:<\/strong> This configuration corresponds to <strong>cadmium (Cd)<\/strong>, which has an atomic number of 48, and would be incorrect for silver.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the correct electron configuration for a ground-state silver atom is <strong>[Ar] 4s\u00b2 4d\u2079<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The electron configuration of a ground-state Ag atom isA) [Ar]4s24d9B) [Kr]5s14d10C) [Ar]4s14d10D) [Kr]5s23d9E) [Kr]5s24d10 The correct answer and explanation is : The correct answer is A) [Ar]4s\u00b24d\u2079. Explanation: Silver (Ag) has an atomic number of 47, which means it has 47 electrons in its ground-state configuration. To determine the correct electron configuration, we can follow [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-211954","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211954","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=211954"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/211954\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=211954"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=211954"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=211954"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}