Attach an even-parity bit to each of the ASCII codes for Problem 2-24, and give the results in hex.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n To answer this question, we’ll first clarify the steps involved in solving Problem 2-24<\/strong>, which typically involves computing ASCII codes and attaching an even-parity bit<\/strong>. Although the actual content of Problem 2-24<\/strong> isn’t provided here, it usually includes a set of characters whose ASCII codes are to be used.<\/p>\n\n\n\n Let\u2019s assume Problem 2-24 gives you a string of characters like:<\/p>\n\n\n\n “DOG”<\/strong><\/p>\n\n\n\n We will compute the 7-bit ASCII codes for each character, attach an even parity bit<\/strong> to the left (as the most significant bit), and present the 8-bit results in hexadecimal.<\/p>\n\n\n\n Even parity means the total number of 1s (including the parity bit) must be even.<\/p>\n\n\n\n The concept of parity bits is foundational in digital communication and error detection. A parity bit<\/strong> is a single binary digit added to a binary string to ensure the number of bits with the value \u201c1\u201d is even (even parity<\/strong>) or odd (odd parity<\/strong>). In this question, we focus on even parity<\/strong>.<\/p>\n\n\n\n ASCII characters are typically represented using 7 bits. When adding a parity bit, we extend this to 8 bits. For even parity, if the original 7 bits contain an odd number of ones, we set the parity bit to 1 to make the total count even. If the 7 bits already have an even number of ones, we set the parity bit to 0.<\/p>\n\n\n\n In our example, we processed the string “DOG”, found the binary ASCII representations, and calculated the parity bit for each. The parity bit was prepended (placed at the most significant bit position), converting each 7-bit code to an 8-bit value. We then converted each of these 8-bit binary strings to hexadecimal for compactness.<\/p>\n\n\n\n Even parity is widely used in communication protocols like RS-232 and in memory systems where simple error checking is adequate. While not foolproof (it can\u2019t detect even-numbered bit errors), it adds a basic level of integrity checking with minimal overhead.<\/p>\n","protected":false},"excerpt":{"rendered":" Attach an even-parity bit to each of the ASCII codes for Problem 2-24, and give the results in hex. The correct answer and explanation is : To answer this question, we’ll first clarify the steps involved in solving Problem 2-24, which typically involves computing ASCII codes and attaching an even-parity bit. Although the actual content […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-212012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=212012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=212012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=212012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=212012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep-by-step:<\/h3>\n\n\n\n
1. Get ASCII codes (7-bit binary):<\/h4>\n\n\n\n
\n
2. Compute even parity bit:<\/h4>\n\n\n\n
\n
\u2192 Final 8 bits<\/strong>: 01000100 \u2192 Hex: 0x44<\/strong><\/li>\n\n\n\n
\u2192 Final 8 bits<\/strong>: 11001111 \u2192 Hex: 0xCF<\/strong><\/li>\n\n\n\n
\u2192 Final 8 bits<\/strong>: 01000111 \u2192 Hex: 0x47<\/strong><\/li>\n<\/ul>\n\n\n\n
\n\n\n\nFinal Results with Even Parity Bits (in Hex):<\/h3>\n\n\n\n
\n
0x44<\/code><\/li>\n\n\n\n0xCF<\/code><\/li>\n\n\n\n0x47<\/code><\/li>\n<\/ul>\n\n\n\n
\n\n\n\nExplanation (Approx. 300 words):<\/h3>\n\n\n\n