{"id":212033,"date":"2025-05-05T14:25:57","date_gmt":"2025-05-05T14:25:57","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=212033"},"modified":"2025-05-05T14:25:59","modified_gmt":"2025-05-05T14:25:59","slug":"the-chemical-formula-for-ironii-nitrate-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/05\/the-chemical-formula-for-ironii-nitrate-is\/","title":{"rendered":"The chemical formula for iron(II) nitrate is"},"content":{"rendered":"\n<p>The chemical formula for iron(II) nitrate is<br>a. Fe2(NO3)3<br>b. Ir(NO2)2<br>c. Fe2N3<br>d. Fe(NO3)2<br>e. Fe(NO2)2<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is:<br><strong>d. Fe(NO\u2083)\u2082<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p><strong>Iron(II) nitrate<\/strong> is an <strong>ionic compound<\/strong> consisting of the <strong>Iron(II) ion (Fe\u00b2\u207a)<\/strong> and the <strong>nitrate ion (NO\u2083\u207b)<\/strong>. To determine the correct formula, it\u2019s important to understand both the <strong>charge balance<\/strong> and the <strong>nomenclature rules<\/strong> for ionic compounds.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understand the Ions Involved<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Iron(II)<\/strong> refers to the iron ion with a <strong>+2 charge<\/strong>, or <strong>Fe\u00b2\u207a<\/strong>.<br>The Roman numeral <strong>(II)<\/strong> in the name indicates this oxidation state.<\/li>\n\n\n\n<li><strong>Nitrate<\/strong> is a <strong>polyatomic ion<\/strong> with the formula <strong>NO\u2083\u207b<\/strong> and carries a <strong>-1 charge<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Determine the Correct Ratio<\/h3>\n\n\n\n<p>Since <strong>Fe\u00b2\u207a<\/strong> has a +2 charge and <strong>NO\u2083\u207b<\/strong> has a -1 charge, we need <strong>two nitrate ions<\/strong> to balance the charge of one iron(II) ion:<\/p>\n\n\n\n<p>$$<br>\\text{Fe}^{2+} + 2(\\text{NO}_3^-) \\rightarrow \\text{Fe(NO}_3)_2<br>$$<\/p>\n\n\n\n<p>This ensures the compound is <strong>electrically neutral<\/strong>, which is a requirement for all stable ionic compounds.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Analyze the Incorrect Options<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>a. Fe\u2082(NO\u2083)\u2083<\/strong>: This is the formula for <strong>iron(III) nitrate<\/strong>, which contains Fe\u00b3\u207a ions, not Fe\u00b2\u207a.<\/li>\n\n\n\n<li><strong>b. Ir(NO\u2082)\u2082<\/strong>: This uses <strong>Iridium (Ir)<\/strong> and <strong>nitrite (NO\u2082\u207b)<\/strong>, not iron or nitrate.<\/li>\n\n\n\n<li><strong>c. Fe\u2082N\u2083<\/strong>: This suggests a compound of iron and nitrogen, not nitrate.<\/li>\n\n\n\n<li><strong>e. Fe(NO\u2082)\u2082<\/strong>: This is <strong>iron(II) nitrite<\/strong>, which contains nitrite (NO\u2082\u207b), not nitrate (NO\u2083\u207b).<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>The correct formula, <strong>Fe(NO\u2083)\u2082<\/strong>, reflects:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>Fe\u00b2\u207a<\/strong> ion (Iron(II))<\/li>\n\n\n\n<li>The <strong>NO\u2083\u207b<\/strong> ion (nitrate)<\/li>\n\n\n\n<li>The proper charge balance: <strong>+2 from iron<\/strong> and <strong>2 \u00d7 -1 from two nitrate ions<\/strong><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>The chemical formula for iron(II) nitrate isa. Fe2(NO3)3b. Ir(NO2)2c. Fe2N3d. Fe(NO3)2e. Fe(NO2)2 The Correct Answer and Explanation is: The correct answer is:d. Fe(NO\u2083)\u2082 Explanation: Iron(II) nitrate is an ionic compound consisting of the Iron(II) ion (Fe\u00b2\u207a) and the nitrate ion (NO\u2083\u207b). To determine the correct formula, it\u2019s important to understand both the charge balance and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-212033","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212033","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=212033"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212033\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=212033"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=212033"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=212033"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}