{"id":212206,"date":"2025-05-06T09:12:34","date_gmt":"2025-05-06T09:12:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=212206"},"modified":"2025-05-06T09:12:36","modified_gmt":"2025-05-06T09:12:36","slug":"in-the-correct-lewis-structure-for-nbr3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/06\/in-the-correct-lewis-structure-for-nbr3\/","title":{"rendered":"In the correct Lewis Structure for NBr3"},"content":{"rendered":"\n<p>In the correct Lewis Structure for NBr3, how many lone pairs (unshared pairs) are on the central atom? Give all atoms zero formal charge, N in middle surrounded by Br&#8217;s<br>1<br>2<br>3<br>4<br>5<br>6<br>7<br>8<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>In the Lewis structure of <strong>NBr\u2083<\/strong> (Nitrogen Trbromide), the central nitrogen atom will have <strong>1 lone pair<\/strong> of electrons. Here\u2019s a step-by-step explanation of how to arrive at this conclusion:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Count the total number of valence electrons:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen (N) is in Group 15 of the periodic table, so it has 5 valence electrons.<\/li>\n\n\n\n<li>Bromine (Br) is in Group 17, so each bromine atom has 7 valence electrons.<\/li>\n\n\n\n<li>For NBr\u2083, there are 3 bromine atoms, so the total valence electrons from bromine are $3 \\times 7 = 21$.<\/li>\n\n\n\n<li>Total number of valence electrons in NBr\u2083 = 5 (from nitrogen) + 21 (from bromine) = <strong>26 electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Determine the bonding arrangement:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen is the central atom because it is less electronegative than bromine.<\/li>\n\n\n\n<li>Each bromine atom will form a single bond with nitrogen, using 2 electrons per bond.<\/li>\n\n\n\n<li>There are 3 bromine atoms, so 3 single bonds are formed with nitrogen, using up 3 \u00d7 2 = 6 electrons.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Distribute the remaining electrons:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>After forming the bonds, there are 26 total valence electrons \u2212 6 electrons used in bonding = 20 electrons remaining.<\/li>\n\n\n\n<li>These remaining 20 electrons will be placed as lone pairs on the bromine atoms, because bromine can accommodate up to 3 lone pairs.<\/li>\n\n\n\n<li>Each bromine will get 3 lone pairs, using up 18 electrons (3 \u00d7 6 = 18).<\/li>\n\n\n\n<li>The remaining 2 electrons will be placed as a lone pair on nitrogen.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">4. <strong>Check formal charges:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen typically follows the octet rule and has 8 electrons around it in total (3 bonds and 1 lone pair), which gives it a formal charge of zero.<\/li>\n\n\n\n<li>Each bromine also has 8 electrons around it (1 bond and 3 lone pairs), resulting in a formal charge of zero for each bromine atom.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Final structure:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen (N) has 1 lone pair.<\/li>\n\n\n\n<li>Each Bromine (Br) has 3 lone pairs.<\/li>\n<\/ul>\n\n\n\n<p>Thus, in the Lewis structure of NBr\u2083, <strong>the central nitrogen atom has 1 lone pair<\/strong> of electrons.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answer: <strong>1 lone pair<\/strong><\/h3>\n\n\n\n<p>This arrangement minimizes formal charges and follows the octet rule, ensuring stability for the molecule.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In the correct Lewis Structure for NBr3, how many lone pairs (unshared pairs) are on the central atom? Give all atoms zero formal charge, N in middle surrounded by Br&#8217;s12345678 The correct answer and explanation is : In the Lewis structure of NBr\u2083 (Nitrogen Trbromide), the central nitrogen atom will have 1 lone pair of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-212206","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212206","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=212206"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212206\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=212206"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=212206"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=212206"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}