{"id":212250,"date":"2025-05-06T09:43:04","date_gmt":"2025-05-06T09:43:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=212250"},"modified":"2025-05-06T09:43:06","modified_gmt":"2025-05-06T09:43:06","slug":"balance-6-13-if-4-25-g-of-aluminum-reacts-with-16-3-g-of-chlorine-gas-to-produce-aluminum-chloride-according-to-the-following-unbalanced-equation-2-al-3cl2-2-aic","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/06\/balance-6-13-if-4-25-g-of-aluminum-reacts-with-16-3-g-of-chlorine-gas-to-produce-aluminum-chloride-according-to-the-following-unbalanced-equation-2-al-3cl2-2-aic\/","title":{"rendered":"Balance (6) 13. If 4.25 g of aluminum reacts with 16.3 g of chlorine gas to produce aluminum chloride according to the following unbalanced equation, 2 Al + 3Cl2 2 AIC"},"content":{"rendered":"\n

Balance (6) 13. If 4.25 g of aluminum reacts with 16.3 g of chlorine gas to produce aluminum chloride according to the following unbalanced equation, 2 Al + 3Cl2 2 AICI: a. Which chemical is the limiting reactant? (Show your calculations) Al-26.98×2 = 53.96 = 1.63% a-35.45 x6 = 212.3 = 6.11% 266.60 Al is the limiting rencant because it 4.25 will un act ofter 4 asg. Its the chemical 1621 with the smallest amung b. What is the theoretical yield (in grams) of aluminum chloride?<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To solve this problem, we\u2019ll go through it step-by-step and calculate:<\/p>\n\n\n\n

Given Reaction (balanced):<\/strong><\/p>\n\n\n\n

2Al+3Cl2\u21922AlCl3\\text{2Al} + 3Cl_2 \\rightarrow 2AlCl_3<\/p>\n\n\n\n

a. Identify the Limiting Reactant<\/strong><\/h3>\n\n\n\n

Step 1: Find molar masses<\/strong><\/p>\n\n\n\n

    \n
  • Molar mass of Al = 26.98 g\/mol<\/li>\n\n\n\n
  • Molar mass of Cl\u2082 = 70.90 g\/mol (35.45 \u00d7 2)<\/li>\n\n\n\n
  • Molar mass of AlCl\u2083 = 133.33 g\/mol (26.98 + 35.45\u00d73)<\/li>\n<\/ul>\n\n\n\n

    Step 2: Convert masses to moles<\/strong><\/p>\n\n\n\n

      \n
    • Moles of Al = 4.25\u00a0g26.98\u00a0g\/mol\u22480.1575\u00a0mol\\frac{4.25\\ g}{26.98\\ g\/mol} \\approx 0.1575\\ mol<\/li>\n\n\n\n
    • Moles of Cl\u2082 = 16.3\u00a0g70.90\u00a0g\/mol\u22480.2299\u00a0mol\\frac{16.3\\ g}{70.90\\ g\/mol} \\approx 0.2299\\ mol<\/li>\n<\/ul>\n\n\n\n

      Step 3: Use mole ratios from balanced equation<\/strong>
      From the equation:
      2 mol Al : 3 mol Cl\u2082<\/p>\n\n\n\n

      Determine how many moles of Cl\u2082 are needed for 0.1575 mol Al: Required Cl\u2082=0.1575 mol Al\u00d73 mol Cl\u20822 mol Al=0.2363 mol Cl2\\text{Required Cl\u2082} = 0.1575 \\text{ mol Al} \\times \\frac{3 \\text{ mol Cl\u2082}}{2 \\text{ mol Al}} = 0.2363\\ mol\\ Cl\u2082<\/p>\n\n\n\n

      We only have 0.2299 mol Cl\u2082, which is slightly less than the required 0.2363 mol.
      Thus, Cl\u2082 is the limiting reactant<\/strong> (not Al).<\/p>\n\n\n\n

      \u2705 Correct Answer: Chlorine gas (Cl\u2082) is the limiting reactant.<\/strong><\/p>\n\n\n\n

      \n\n\n\n

      b. Theoretical Yield of AlCl\u2083<\/strong><\/h3>\n\n\n\n

      Step 1: Use mole ratio between Cl\u2082 and AlCl\u2083<\/strong><\/p>\n\n\n\n

      From the balanced equation:
      3 mol Cl\u2082 \u2192 2 mol AlCl\u2083<\/p>\n\n\n\n

      So, Moles of AlCl\u2083=0.2299 mol Cl2\u00d72 mol AlCl33 mol Cl2=0.1533 mol AlCl3\\text{Moles of AlCl\u2083} = 0.2299\\ mol\\ Cl\u2082 \\times \\frac{2\\ mol\\ AlCl\u2083}{3\\ mol\\ Cl\u2082} = 0.1533\\ mol\\ AlCl\u2083<\/p>\n\n\n\n

      Step 2: Convert moles of AlCl\u2083 to grams<\/strong> Mass of AlCl\u2083=0.1533 mol\u00d7133.33 g\/mol=20.44 g\\text{Mass of AlCl\u2083} = 0.1533\\ mol \\times 133.33\\ g\/mol = \\boxed{20.44\\ g}<\/p>\n\n\n\n

      \u2705 Correct Answer: The theoretical yield is 20.44 grams of aluminum chloride.<\/strong><\/p>\n\n\n\n

      \n\n\n\n

      \ud83d\udcd8 Explanation (300+ Words)<\/h3>\n\n\n\n

      In a chemical reaction, the limiting reactant<\/strong> is the substance that is completely consumed first, thereby limiting the amount of product formed. This problem presents a reaction between aluminum (Al) and chlorine gas (Cl\u2082) to form aluminum chloride (AlCl\u2083).<\/p>\n\n\n\n

      The first step is to ensure that the chemical equation is balanced<\/strong>. The balanced equation is: 2Al+3Cl2\u21922AlCl32Al + 3Cl_2 \\rightarrow 2AlCl_3<\/p>\n\n\n\n

      This means that 2 moles of aluminum react with 3 moles of chlorine gas to form 2 moles of aluminum chloride.<\/p>\n\n\n\n

      Next, we convert the given masses into moles. Aluminum has a molar mass of 26.98 g\/mol. Thus, 4.25 g of Al equals approximately 0.1575 mol. Chlorine gas (Cl\u2082) has a molar mass of 70.90 g\/mol, so 16.3 g Cl\u2082 equals about 0.2299 mol.<\/p>\n\n\n\n

      Now we apply mole ratios to determine which reactant will be used up first. To completely react with 0.1575 mol of Al, we would need 0.2363 mol of Cl\u2082. However, we only have 0.2299 mol of Cl\u2082. Therefore, Cl\u2082 is not enough and is the limiting reactant<\/strong>.<\/p>\n\n\n\n

      To find the theoretical yield<\/strong> of AlCl\u2083, we start with the amount of limiting reactant. Using the balanced equation, 3 mol of Cl\u2082 yields 2 mol of AlCl\u2083. So, 0.2299 mol Cl\u2082 will yield: 0.2299\u00d723=0.1533 mol AlCl30.2299 \\times \\frac{2}{3} = 0.1533\\ mol\\ AlCl_3<\/p>\n\n\n\n

      Multiplying by the molar mass of AlCl\u2083 (133.33 g\/mol) gives: 0.1533\u00d7133.33=20.44 g0.1533 \\times 133.33 = 20.44\\ g<\/p>\n\n\n\n

      Therefore, the maximum amount of AlCl\u2083 that can be formed (the theoretical yield<\/strong>) is 20.44 grams<\/strong>, assuming perfect reaction conditions.<\/p>\n","protected":false},"excerpt":{"rendered":"

      Balance (6) 13. If 4.25 g of aluminum reacts with 16.3 g of chlorine gas to produce aluminum chloride according to the following unbalanced equation, 2 Al + 3Cl2 2 AICI: a. Which chemical is the limiting reactant? (Show your calculations) Al-26.98×2 = 53.96 = 1.63% a-35.45 x6 = 212.3 = 6.11% 266.60 Al is […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-212250","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212250","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=212250"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/212250\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=212250"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=212250"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=212250"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}