{"id":213020,"date":"2025-05-09T07:02:01","date_gmt":"2025-05-09T07:02:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=213020"},"modified":"2025-05-09T07:02:04","modified_gmt":"2025-05-09T07:02:04","slug":"methane-ch4-has-the-ideal-tetrahedral-angle-109-5-and-is-a-nonpolar-molecule-while-nh3-and-h2o-show-a-deviation-from-the-ideal-bond-angle","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/09\/methane-ch4-has-the-ideal-tetrahedral-angle-109-5-and-is-a-nonpolar-molecule-while-nh3-and-h2o-show-a-deviation-from-the-ideal-bond-angle\/","title":{"rendered":"Methane, CH4, has the ideal tetrahedral angle (109.5\u00b0) and is a nonpolar molecule, while NH3 and H2O show a deviation from the ideal bond angle."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Methane, CH4, has the ideal tetrahedral angle (109.5\u00b0) and is a nonpolar molecule, while NH3 and H2O show a deviation from the ideal bond angle. Explain the cause and why water has a greater deviation than ammonia.Methane, CH4, has the ideal tetrahedral angle (109.5\u00b0) and is a nonpolar molecule, while NH3 and H2O show a deviation from the ideal bond angle. Explain the cause and why water has a greater deviation than ammonia.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answer:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The deviation from the ideal tetrahedral bond angle in NH\u2083 and H\u2082O is due to the presence of lone pairs of electrons on the central atom. Lone pairs occupy more space than bonding pairs, causing greater repulsion and compressing the bond angles between atoms. Water (H\u2082O) has two lone pairs, while ammonia (NH\u2083) has only one, leading to a greater deviation in water.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Detailed Explanation (300+ words):<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Methane (CH\u2084) has a central carbon atom bonded to four hydrogen atoms with no lone pairs on the carbon. According to Valence Shell Electron Pair Repulsion (VSEPR) theory, electron pairs (bonding and lone pairs) around a central atom repel each other and will arrange themselves as far apart as possible. In CH\u2084, all four electron domains are bonding pairs, which adopt a <strong>tetrahedral geometry<\/strong> with ideal bond angles of <strong>109.5\u00b0<\/strong>. Since the molecule is symmetrical and all outer atoms are the same, CH\u2084 is <strong>nonpolar<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ammonia (NH\u2083), in contrast, has a nitrogen atom with <strong>three bonding pairs<\/strong> and <strong>one lone pair<\/strong>. This gives it a total of four electron domains, like CH\u2084, and it retains a tetrahedral electron geometry. However, because a lone pair occupies more space than a bonding pair (due to its higher electron density and absence of nuclear attraction from a second nucleus), it <strong>pushes the bonding pairs closer together<\/strong>. This causes the H\u2013N\u2013H bond angle in ammonia to decrease from 109.5\u00b0 to about <strong>107\u00b0<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Water (H\u2082O) shows an even greater deviation. The oxygen atom in H\u2082O has <strong>two bonding pairs<\/strong> and <strong>two lone pairs<\/strong>, still a total of four electron domains and thus a tetrahedral electron geometry. However, the <strong>two lone pairs exert even more repulsion<\/strong> on the bonding pairs than the single lone pair in NH\u2083. As a result, the H\u2013O\u2013H bond angle in water is reduced further to about <strong>104.5\u00b0<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In summary, the bond angle deviation increases with the number of lone pairs due to increased lone pair\u2013bond pair repulsion. Therefore, <strong>water has a greater deviation<\/strong> from the ideal tetrahedral angle than ammonia because it has <strong>two lone pairs<\/strong> instead of one.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Methane, CH4, has the ideal tetrahedral angle (109.5\u00b0) and is a nonpolar molecule, while NH3 and H2O show a deviation from the ideal bond angle. Explain the cause and why water has a greater deviation than ammonia.Methane, CH4, has the ideal tetrahedral angle (109.5\u00b0) and is a nonpolar molecule, while NH3 and H2O show a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-213020","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/213020","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=213020"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/213020\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=213020"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=213020"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=213020"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}