{"id":213342,"date":"2025-05-10T10:21:52","date_gmt":"2025-05-10T10:21:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=213342"},"modified":"2025-05-10T10:21:55","modified_gmt":"2025-05-10T10:21:55","slug":"draw-lewis-structures-for-the-acetonitrile-molecule-ch3cn-the-methylamine-molecule-ch3nh2-and-the-methanimine-molecule-ch2nh-and-then-answer-the-questions-that-follow","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/10\/draw-lewis-structures-for-the-acetonitrile-molecule-ch3cn-the-methylamine-molecule-ch3nh2-and-the-methanimine-molecule-ch2nh-and-then-answer-the-questions-that-follow\/","title":{"rendered":"Draw Lewis structures for the acetonitrile molecule (CH3CN), the methylamine molecule (CH3NH2), and the methanimine molecule (CH2NH), and then answer the questions that follow."},"content":{"rendered":"\n<p>Draw Lewis structures for the acetonitrile molecule (CH3CN), the methylamine molecule (CH3NH2), and the methanimine molecule (CH2NH), and then answer the questions that follow.<\/p>\n\n\n\n<p>(Draw one structure per sketcher box, and separate added sketcher boxes with the + sign. Do not include overall ion charges or formal charges in your drawing. Do not draw double bonds to oxygen unless they are needed in order for the central atom to obey the octet rule.)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s analyze and draw the Lewis structures for the three given molecules: <strong>acetonitrile (CH\u2083CN), methylamine (CH\u2083NH\u2082), and methanimine (CH\u2082NH)<\/strong>. Below is a detailed explanation and the corresponding structures.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Acetonitrile (CH\u2083CN)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H   H   H\n \\  |  \/\n  C \u2014 C \u2261 N\n     |\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon 1 (C in CH\u2083)<\/strong> is bonded to three hydrogens and one carbon.<\/li>\n\n\n\n<li><strong>Carbon 2 (C in CN)<\/strong> is triple bonded to nitrogen and single bonded to the CH\u2083 group.<\/li>\n\n\n\n<li><strong>Nitrogen<\/strong> has one lone pair and is triple bonded to the second carbon.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Methylamine (CH\u2083NH\u2082)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H   H   H\n \\  |  \/\n  C \u2014 N \u2014 H\n     |\n     H\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon (C)<\/strong> is bonded to three hydrogens and one nitrogen.<\/li>\n\n\n\n<li><strong>Nitrogen (N)<\/strong> is bonded to the carbon and two hydrogens and has one lone pair.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. Methanimine (CH\u2082NH)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H   H\n \\  \/\n  C = N \u2014 H\n     |\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon<\/strong> is bonded to two hydrogens and double bonded to nitrogen.<\/li>\n\n\n\n<li><strong>Nitrogen<\/strong> is bonded to carbon and one hydrogen and has one lone pair.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">\ud83e\uddea Explanation (300+ words):<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Valence Electron Considerations:<\/strong><\/h3>\n\n\n\n<p>To draw Lewis structures, you need to:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count valence electrons<\/strong> for each atom.<\/li>\n\n\n\n<li><strong>Satisfy the octet rule<\/strong> (or duet for hydrogen).<\/li>\n\n\n\n<li><strong>Connect atoms logically<\/strong> (least electronegative at the center, typically carbon).<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. CH\u2083CN \u2013 Acetonitrile<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Total valence electrons:\n<ul class=\"wp-block-list\">\n<li>C (4) \u00d7 2 + H (1) \u00d7 3 + N (5) = 16 electrons<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Carbon in CH\u2083 forms three C-H bonds and one C-C bond.<\/li>\n\n\n\n<li>The second carbon (connected to nitrogen) forms a triple bond with nitrogen to satisfy both their octets.<\/li>\n\n\n\n<li>Nitrogen ends with one lone pair.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. CH\u2083NH\u2082 \u2013 Methylamine<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Total valence electrons:\n<ul class=\"wp-block-list\">\n<li>C (4) + N (5) + H (1) \u00d7 5 = 14 electrons<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Carbon bonds to three H and one N.<\/li>\n\n\n\n<li>Nitrogen bonds to carbon and two Hs, and has one lone pair.<\/li>\n\n\n\n<li>All atoms satisfy the octet (or duet for H).<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. CH\u2082NH \u2013 Methanimine<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Total valence electrons:\n<ul class=\"wp-block-list\">\n<li>C (4) + N (5) + H (1) \u00d7 3 = 12 electrons<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Carbon forms two bonds with H and a double bond with N.<\/li>\n\n\n\n<li>Nitrogen forms a double bond with C and one bond with H, with one lone pair.<\/li>\n\n\n\n<li>Octets\/duets are satisfied.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<p>These structures show the diversity of bonding in organic molecules:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CH\u2083CN<\/strong> includes a triple bond (C\u2261N),<\/li>\n\n\n\n<li><strong>CH\u2083NH\u2082<\/strong> is a saturated amine,<\/li>\n\n\n\n<li><strong>CH\u2082NH<\/strong> has a C=N double bond (an imine).<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Draw Lewis structures for the acetonitrile molecule (CH3CN), the methylamine molecule (CH3NH2), and the methanimine molecule (CH2NH), and then answer the questions that follow. (Draw one structure per sketcher box, and separate added sketcher boxes with the + sign. Do not include overall ion charges or formal charges in your drawing. Do not draw double [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-213342","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/213342","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=213342"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/213342\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=213342"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=213342"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=213342"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}