{"id":213900,"date":"2025-05-12T20:54:10","date_gmt":"2025-05-12T20:54:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=213900"},"modified":"2025-05-12T20:54:13","modified_gmt":"2025-05-12T20:54:13","slug":"natural-selection-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/12\/natural-selection-2\/","title":{"rendered":"NATURAL SELECTION"},"content":{"rendered":"\n<p>NATURAL SELECTION. NATURAL SELECTION IN INSECTS INTRODUCTION LABORATORY SIMULATION A Lab Data Total 1000 474 513 606 731 1050<\/p>\n\n\n\n<p>Phenotype Frequency<\/p>\n\n\n\n<p>Color<br>Initial Frequency<br>Frequency GS (Round to 2 decimal places)<br>0.81 White<br>0.25 Black<br>0.75 Typical<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To correctly calculate the <strong>frequency after natural selection<\/strong> (Generation Survival, or GS) of each phenotype in the simulated population of insects, we need to first understand the context and apply basic population genetics formulas.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Understand Initial Phenotype Frequencies<\/strong><\/h3>\n\n\n\n<p>You are given these initial phenotype frequencies:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>White<\/strong> = 0.81<\/li>\n\n\n\n<li><strong>Black<\/strong> = 0.25<\/li>\n\n\n\n<li><strong>Typical<\/strong> = 0.75<\/li>\n<\/ul>\n\n\n\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\">\n<p>\u26a0\ufe0f However, these values <strong>do not sum up to 1<\/strong>, which is a requirement for valid frequencies. Therefore, these might represent <strong>survival counts<\/strong> or pre-simulation frequencies, not normalized values.<\/p>\n<\/blockquote>\n\n\n\n<p>Let\u2019s assume the \u201cTotal\u201d row represents the population <strong>after natural selection<\/strong> (Generation Survival), with values recorded as:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Trial<\/th><th>Count<\/th><\/tr><\/thead><tbody><tr><td>A<\/td><td>1000<\/td><\/tr><tr><td>B<\/td><td>474<\/td><\/tr><tr><td>C<\/td><td>513<\/td><\/tr><tr><td>D<\/td><td>606<\/td><\/tr><tr><td>E<\/td><td>731<\/td><\/tr><tr><td>F<\/td><td>1050<\/td><\/tr><tr><td><strong>Total<\/strong><\/td><td><strong>4374<\/strong><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>Now, if we are calculating <strong>frequency GS (Generation Survival)<\/strong> for each color phenotype, we need:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The number of insects of each phenotype that survived.<\/li>\n\n\n\n<li>Then divide each by the total to get the <strong>relative frequency<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Assumed Breakdown by Color (Hypothetical Example)<\/strong><\/h3>\n\n\n\n<p>Let\u2019s assume:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>White<\/strong> = 1000 (from Trial A)<\/li>\n\n\n\n<li><strong>Black<\/strong> = 474 (from Trial B)<\/li>\n\n\n\n<li><strong>Typical<\/strong> = 513 (from Trial C)<br>(And maybe D-F are mixed or repeats)<\/li>\n<\/ul>\n\n\n\n<p>But the question seems to want frequency values <strong>rounded to 2 decimal places<\/strong> for three phenotypes, based on some total.<\/p>\n\n\n\n<p>If we assume:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>White = 1000<\/li>\n\n\n\n<li>Black = 474<\/li>\n\n\n\n<li>Typical = 513<\/li>\n<\/ul>\n\n\n\n<p>Then:<\/p>\n\n\n\n<p><strong>Total = 1000 + 474 + 513 = 1987<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Calculate Phenotype Frequencies (GS)<\/strong><\/h3>\n\n\n\n<p>Now divide each phenotype count by total (1987):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>White<\/strong> = 1000 \/ 1987 = <strong>0.50<\/strong><\/li>\n\n\n\n<li><strong>Black<\/strong> = 474 \/ 1987 \u2248 <strong>0.24<\/strong><\/li>\n\n\n\n<li><strong>Typical<\/strong> = 513 \/ 1987 \u2248 <strong>0.26<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer (Rounded to 2 Decimal Places)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>White:<\/strong> 0.50<\/li>\n\n\n\n<li><strong>Black:<\/strong> 0.24<\/li>\n\n\n\n<li><strong>Typical:<\/strong> 0.26<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83e\uddec 300-Word Explanation:<\/h3>\n\n\n\n<p>Natural selection is a process through which certain traits become more or less common in a population due to their influence on the survival and reproduction of organisms. In this laboratory simulation, you are examining how natural selection affects the frequencies of different insect color phenotypes\u2014White, Black, and Typical\u2014after exposure to environmental pressures.<\/p>\n\n\n\n<p>The term <strong>\u201cfrequency GS\u201d<\/strong> refers to the proportion of each phenotype that survives after selection, relative to the total number of survivors. To determine these frequencies, we divide the number of surviving individuals of each phenotype by the total number of survivors across all phenotypes.<\/p>\n\n\n\n<p>From the data, if we assume that the number of White insects that survived was 1000, Black was 474, and Typical was 513, then the total number of survivors is 1987. By dividing the number of survivors in each phenotype category by this total, we get the post-selection frequency for each group.<\/p>\n\n\n\n<p>For White: 1000 \u00f7 1987 \u2248 0.50<br>For Black: 474 \u00f7 1987 \u2248 0.24<br>For Typical: 513 \u00f7 1987 \u2248 0.26<\/p>\n\n\n\n<p>These numbers indicate that White insects had the highest survival rate in this environment. This suggests that their coloration may offer better camouflage or other advantages in the given conditions, making them more likely to survive and reproduce. Over successive generations, if the same selective pressure remains, we would expect the White phenotype to increase in frequency, illustrating the principle of natural selection.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NATURAL SELECTION. NATURAL SELECTION IN INSECTS INTRODUCTION LABORATORY SIMULATION A Lab Data Total 1000 474 513 606 731 1050 Phenotype Frequency ColorInitial FrequencyFrequency GS (Round to 2 decimal places)0.81 White0.25 Black0.75 Typical The Correct Answer and Explanation is: To correctly calculate the frequency after natural selection (Generation Survival, or GS) of each phenotype in the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-213900","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/213900","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=213900"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/213900\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=213900"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=213900"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=213900"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}