We can draw three inequivalent Lewis structures for the bromate ion, BrO3-. The concepts of formal charge and electronegativity can help us choose the structure that is the best representation. 1. Assign formal charges to the elements in each of the structures below. Note: Count oxygen atoms starting from the left for each structure.<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n To determine the best Lewis structure for the bromate ion (BrO\u2083\u207b)<\/strong>, we analyze three possible resonance structures using formal charges<\/strong> and electronegativity<\/strong>. Here\u2019s how we determine the formal charges<\/strong> for each atom and then identify the best representation.<\/p>\n\n\n\n We\u2019ll analyze three inequivalent<\/strong> Lewis structures that differ in the placement of double bonds and lone pairs.<\/p>\n\n\n\n (Starting from the left: O1 = double bonded; O2 & O3 = single bonded)<\/p>\n\n\n\n \u27a1\ufe0f Formal Charges<\/strong>: (Left to right: O1 & O2 = double bonded; O3 = single bonded)<\/p>\n\n\n\n \u27a1\ufe0f Formal Charges<\/strong>: Each oxygen has a full octet, and Br has an expanded octet.<\/p>\n\n\n\n \u27a1\ufe0f Formal Charges<\/strong>: Because formal charges are minimized<\/strong> in Structure B, and negative charges reside on the more electronegative oxygen atoms<\/strong> rather than bromine, Structure B<\/strong> is the best Lewis structure<\/strong>.<\/p>\n\n\n\n Using formal charge analysis<\/strong> and the concept of electronegativity<\/strong>, Structure B<\/strong> is the most stable and best represents the BrO\u2083\u207b ion. It maintains the correct number of valence electrons, places the negative charge on the more electronegative oxygen, and keeps formal charges close to zero.<\/p>\n","protected":false},"excerpt":{"rendered":" We can draw three inequivalent Lewis structures for the bromate ion, BrO3-. The concepts of formal charge and electronegativity can help us choose the structure that is the best representation. 1. Assign formal charges to the elements in each of the structures below. Note: Count oxygen atoms starting from the left for each structure. The […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-214236","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/214236","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=214236"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/214236\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=214236"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=214236"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=214236"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep 1: Determine Total Valence Electrons<\/strong><\/h3>\n\n\n\n
\n
\n\n\n\nPossible Structures and Formal Charges<\/strong><\/h3>\n\n\n\n
Structure A<\/strong>: One Br=O double bond, two Br\u2013O single bonds<\/h4>\n\n\n\n
\n
Br = +1
O1 = 0
O2 = \u20131
O3 = \u20131<\/p>\n\n\n\n
\n\n\n\nStructure B<\/strong>: Two Br=O double bonds, one Br\u2013O single bond<\/h4>\n\n\n\n
\n
Br = 0
O1 = 0
O2 = 0
O3 = \u20131<\/p>\n\n\n\n
\n\n\n\nStructure C<\/strong>: All Br\u2013O single bonds<\/h4>\n\n\n\n
\n
Br = +3
Each O = \u20131<\/p>\n\n\n\n
\n\n\n\nBest Structure? Structure B<\/strong><\/h3>\n\n\n\n
\n
\n\n\n\nConclusion<\/strong><\/h3>\n\n\n\n