{"id":214282,"date":"2025-05-14T04:09:18","date_gmt":"2025-05-14T04:09:18","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=214282"},"modified":"2025-05-14T04:09:20","modified_gmt":"2025-05-14T04:09:20","slug":"draw-a-six-carbon-alkyne-that-can-exist-as-diastereomers-7","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/14\/draw-a-six-carbon-alkyne-that-can-exist-as-diastereomers-7\/","title":{"rendered":"Draw a six-carbon alkyne that can exist as diastereomers"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Draw a six-carbon alkyne that can exist as diastereomers. You do not need to specify wedge or dashed bonds. Select Draw Rings More Erase \/ MICH 5 3 2 o<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To answer this question, let&#8217;s break it down:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answer:<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3-Hexyne with two different groups on carbons 2 and 4, such as 2-chloro-3-hexyne-4-methyl<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">So, the structure is:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>CH3\u2013CH(Cl)\u2013C\u2261C\u2013C(CH3)H\u2013CH3\n<\/code><\/pre>\n\n\n\n<p class=\"wp-block-paragraph\">This molecule can exist as <strong>diastereomers<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>300-Word Explanation:<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To find a six-carbon alkyne that can exist as <strong>diastereomers<\/strong>, we need to understand a few key concepts:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Alkyne Definition:<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">An alkyne is a hydrocarbon that contains at least one <strong>carbon-carbon triple bond<\/strong>. A <strong>six-carbon alkyne<\/strong> can have many structural isomers (different ways to arrange the atoms).<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Diastereomers:<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">Diastereomers are a type of stereoisomer that are <strong>not mirror images<\/strong> of each other and <strong>not superimposable<\/strong>. Unlike enantiomers (which are always pairs), diastereomers can have multiple stereoisomers.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To have <strong>diastereomers<\/strong>, a molecule must have <strong>two or more chiral centers<\/strong> but <strong>not be a mirror image<\/strong> across all centers.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Strategy:<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">We start by placing a triple bond somewhere in the six-carbon chain (e.g., between carbon 3 and carbon 4 to form 3-hexyne).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Then, we introduce <strong>substituents<\/strong> on adjacent carbons\u2014preferably carbon 2 and carbon 5\u2014so that <strong>two chiral centers<\/strong> are created.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">For example:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On carbon 2: add a <strong>chlorine (Cl)<\/strong> and a <strong>hydrogen (H)<\/strong><\/li>\n\n\n\n<li>On carbon 5: add a <strong>methyl group (CH\u2083)<\/strong> and a <strong>hydrogen (H)<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Now we have two chiral centers (at carbons 2 and 5). This molecule can exist in <strong>four stereoisomers<\/strong> (RR, SS, RS, SR), <strong>two pairs of enantiomers<\/strong>, and <strong>multiple diastereomers<\/strong> (e.g., RR vs RS).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Because they are <strong>not mirror images<\/strong>, these satisfy the condition of <strong>diastereomers<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Therefore, this substituted alkyne\u2014a <strong>3-hexyne derivative with two chiral centers<\/strong>\u2014fits the requirement. The molecule must be <strong>asymmetric at both centers<\/strong>, and different configurations at one center but not the other result in diastereomers.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw a six-carbon alkyne that can exist as diastereomers. You do not need to specify wedge or dashed bonds. Select Draw Rings More Erase \/ MICH 5 3 2 o The Correct Answer and Explanation is: To answer this question, let&#8217;s break it down: Correct Answer: 3-Hexyne with two different groups on carbons 2 and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-214282","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/214282","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=214282"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/214282\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=214282"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=214282"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=214282"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}