{"id":215105,"date":"2025-05-16T09:35:49","date_gmt":"2025-05-16T09:35:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=215105"},"modified":"2025-05-16T09:35:51","modified_gmt":"2025-05-16T09:35:51","slug":"which-is-the-correct-formula-for-strontium-cyanide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/16\/which-is-the-correct-formula-for-strontium-cyanide\/","title":{"rendered":"Which is the correct formula for strontium cyanide"},"content":{"rendered":"\n<p>Which is the correct formula for strontium cyanide? SrCN Sr3(CN)2 Sr2(CN)3 SrCN2 Sr(CN)2<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct formula for <strong>strontium cyanide<\/strong> is:<\/p>\n\n\n\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\">\n<p>\u2705 <strong>Sr(CN)\u2082<\/strong><\/p>\n<\/blockquote>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300+ words):<\/strong><\/h3>\n\n\n\n<p>To determine the correct formula for <strong>strontium cyanide<\/strong>, we need to understand how to form <strong>ionic compounds<\/strong> between a <strong>metal<\/strong> (strontium) and a <strong>polyatomic ion<\/strong> (cyanide).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Understand the Ions<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Strontium (Sr)<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Strontium is an <strong>alkaline earth metal<\/strong>, found in Group 2 of the periodic table.<\/li>\n\n\n\n<li>Group 2 metals typically form <strong>+2 cations<\/strong>.<\/li>\n\n\n\n<li>So, strontium forms the ion <strong>Sr\u00b2\u207a<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cyanide (CN)<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Cyanide is a <strong>polyatomic ion<\/strong> composed of one carbon atom and one nitrogen atom.<\/li>\n\n\n\n<li>Its formula is <strong>CN\u207b<\/strong>, and it carries a <strong>-1 charge<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Balance the Charges<\/strong><\/h3>\n\n\n\n<p>To write the correct chemical formula, the total positive charge must balance the total negative charge.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sr\u00b2\u207a<\/strong> provides <strong>+2<\/strong> charge.<\/li>\n\n\n\n<li><strong>CN\u207b<\/strong> provides <strong>-1<\/strong> charge <strong>per ion<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>To balance the +2 from Sr\u00b2\u207a, you need <strong>2 cyanide ions<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sr\u00b2\u207a + 2 \u00d7 CN\u207b \u2192 Sr(CN)\u2082<\/li>\n<\/ul>\n\n\n\n<p>This gives us a <strong>neutral compound<\/strong>, where the charges cancel out:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(+2) + (2 \u00d7 -1) = 0<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Use Parentheses for Polyatomic Ions<\/strong><\/h3>\n\n\n\n<p>Since cyanide is a <strong>polyatomic ion<\/strong> and you need <strong>more than one<\/strong> of them, you must <strong>enclose it in parentheses<\/strong> and add a subscript outside:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Correct format: <strong>Sr(CN)\u2082<\/strong><\/li>\n\n\n\n<li>Incorrect: SrCN\u2082 (suggests 1 Sr, 1 C, 2 N \u2013 not valid)<\/li>\n\n\n\n<li>Incorrect: Sr3(CN)\u2082 (implies 3 Sr\u00b2\u207a and 2 CN\u207b \u2192 charges don&#8217;t balance)<\/li>\n\n\n\n<li>Incorrect: Sr2(CN)3 (implies 2 Sr\u00b2\u207a = +4, 3 CN\u207b = -3 \u2192 not neutral)<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer:<\/h3>\n\n\n\n<p><strong>Sr(CN)\u2082<\/strong> is the correct formula for <strong>strontium cyanide<\/strong>, representing one Sr\u00b2\u207a ion and two CN\u207b ions, forming a neutral ionic compound.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which is the correct formula for strontium cyanide? SrCN Sr3(CN)2 Sr2(CN)3 SrCN2 Sr(CN)2 The Correct Answer and Explanation is: The correct formula for strontium cyanide is: \u2705 Sr(CN)\u2082 Explanation (300+ words): To determine the correct formula for strontium cyanide, we need to understand how to form ionic compounds between a metal (strontium) and a polyatomic [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-215105","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/215105","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=215105"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/215105\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=215105"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=215105"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=215105"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}