{"id":215270,"date":"2025-05-16T16:08:16","date_gmt":"2025-05-16T16:08:16","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=215270"},"modified":"2025-05-16T16:08:18","modified_gmt":"2025-05-16T16:08:18","slug":"ck_oi-diamonds-red-spades-black-and-clubs-black","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/16\/ck_oi-diamonds-red-spades-black-and-clubs-black\/","title":{"rendered":"CK_OI diamonds (red), spades (black) and clubs (black)"},"content":{"rendered":"\n<p>CK_OI diamonds (red), spades (black) and clubs (black). a) How many cards must be selected from a standard deck of cards to guarantee that at least 3 cards of the same suit are selected? Explain your answer. How many ways are there to select a pair of cards from a standard deck of cards such that one of the cards is red and the other one is black? Your answer can contain factorial or power expressions. Explain your answer. How many ways are there to divide a standard deck of cards over 4 players? Your answer can contain factorial or power expressions. Explain your answer. None<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s tackle each part of the question one by one, with clear answers and detailed explanations.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>a) How many cards must be selected from a standard deck to guarantee at least 3 cards of the same suit are selected?<\/strong><\/h3>\n\n\n\n<p><strong>Answer: 9 cards<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>A standard deck has 4 suits: hearts \u2665\ufe0f, diamonds \u2666\ufe0f (both red), and clubs \u2663\ufe0f, spades \u2660\ufe0f (both black). Each suit has 13 cards.<\/p>\n\n\n\n<p>To <strong>guarantee<\/strong> that at least 3 cards of the same suit are selected, we apply the <strong>Pigeonhole Principle<\/strong>. This principle tells us how items (cards) can be distributed into containers (suits) before a particular condition must occur.<\/p>\n\n\n\n<p>Worst-case scenario:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 cards of each suit (2 hearts, 2 diamonds, 2 spades, 2 clubs) = 8 cards<\/li>\n\n\n\n<li>No suit yet has 3 cards.<\/li>\n<\/ul>\n\n\n\n<p>Now, on drawing the <strong>9th card<\/strong>, <strong>at least one suit will have 3 cards<\/strong>, no matter which suit it is.<\/p>\n\n\n\n<p>\u2705 Therefore, <strong>9 cards are needed to guarantee 3 of the same suit<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>b) How many ways are there to select a pair of cards from a standard deck such that one is red and one is black?<\/strong><\/h3>\n\n\n\n<p><strong>Answer: 26 \u00d7 26 = 676 ways<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>There are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>26 red cards (13 hearts + 13 diamonds)<\/li>\n\n\n\n<li>26 black cards (13 spades + 13 clubs)<\/li>\n<\/ul>\n\n\n\n<p>To form a pair with one red and one black card:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Choose <strong>1 red card<\/strong> in 26 ways<\/li>\n\n\n\n<li>Choose <strong>1 black card<\/strong> in 26 ways<\/li>\n<\/ul>\n\n\n\n<p>Total ways = <strong>26 \u00d7 26 = 676<\/strong><\/p>\n\n\n\n<p>Alternatively, expressed in factorials: (261)\u00d7(261)=26\u00d726\\binom{26}{1} \\times \\binom{26}{1} = 26 \\times 26<\/p>\n\n\n\n<p>\u2705 Hence, there are <strong>676 distinct red-black card pairs<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>c) How many ways are there to divide a standard deck of cards over 4 players?<\/strong><\/h3>\n\n\n\n<p><strong>Answer:<\/strong> 52!(13!)4\\frac{52!}{(13!)^4}<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>We are dividing <strong>52 cards<\/strong> into <strong>4 hands of 13 cards each<\/strong>, with each hand going to one player.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>First, count all ways to arrange 52 cards: <strong>52!<\/strong><\/li>\n\n\n\n<li>But within each player&#8217;s hand, the order of cards doesn\u2019t matter: divide by <strong>13!<\/strong> for each hand.<\/li>\n\n\n\n<li>Also, since players are distinct (say Player A, B, C, D), the division is unique per player.<\/li>\n<\/ul>\n\n\n\n<p>So the number of ways is: 52!13!\u00d713!\u00d713!\u00d713!=52!(13!)4\\frac{52!}{13! \\times 13! \\times 13! \\times 13!} = \\frac{52!}{(13!)^4}<\/p>\n\n\n\n<p>\u2705 Thus, there are <strong>52!(13!)4\\frac{52!}{(13!)^4}<\/strong> ways to deal 52 cards evenly to 4 players.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>CK_OI diamonds (red), spades (black) and clubs (black). a) How many cards must be selected from a standard deck of cards to guarantee that at least 3 cards of the same suit are selected? Explain your answer. How many ways are there to select a pair of cards from a standard deck of cards such [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-215270","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/215270","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=215270"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/215270\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=215270"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=215270"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=215270"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}