{"id":215297,"date":"2025-05-16T17:07:01","date_gmt":"2025-05-16T17:07:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=215297"},"modified":"2025-05-16T17:07:04","modified_gmt":"2025-05-16T17:07:04","slug":"question-2-1-pts-determine-the-number-of-valence-electrons-for-ch2cl2-and-draw","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/16\/question-2-1-pts-determine-the-number-of-valence-electrons-for-ch2cl2-and-draw\/","title":{"rendered":"Question 2 1 Pts Determine The Number Of Valence Electrons For CH2Cl2 And Draw"},"content":{"rendered":"\n<p>Question 2 1 Pts Determine The Number Of Valence Electrons For CH2Cl2 And Draw The Lewis Structure. Based On Your Structure, The Electron Geometry Of This Molecule Is Select) The Molecular Geometry Is Select] Bond Angles Are [Select And The Hybridization At The Centralis Sp3<\/p>\n\n\n\n<p><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To answer this question about <strong>CH\u2082Cl\u2082 (dichloromethane)<\/strong>, we need to:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Determine the number of valence electrons:<\/strong><\/h3>\n\n\n\n<p>We sum the valence electrons of each atom:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 4 valence electrons<\/li>\n\n\n\n<li>Hydrogen (H): 1 valence electron \u00d7 2 = 2<\/li>\n\n\n\n<li>Chlorine (Cl): 7 valence electrons \u00d7 2 = 14<\/li>\n<\/ul>\n\n\n\n<p><strong>Total = 4 (C) + 2 (H) + 14 (Cl) = 20 valence electrons<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Draw the Lewis structure:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon (C)<\/strong> is the <strong>central atom<\/strong> because it can form 4 bonds.<\/li>\n\n\n\n<li>Attach <strong>two H atoms<\/strong> and <strong>two Cl atoms<\/strong> to the central C with single bonds.<\/li>\n\n\n\n<li>This uses <strong>4 bonds \u00d7 2 electrons = 8 electrons<\/strong>.<\/li>\n\n\n\n<li>Remaining <strong>20 &#8211; 8 = 12 electrons<\/strong> go on the Cl atoms to complete their octets (6 electrons per Cl atom as lone pairs).<\/li>\n\n\n\n<li>Hydrogen atoms already have 2 electrons each, so no lone pairs are needed.<\/li>\n<\/ul>\n\n\n\n<p><strong>Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>        H\n        |\n    Cl\u2013C\u2013H\n        |\n       Cl\n<\/code><\/pre>\n\n\n\n<p>Carbon has four single bonds \u2014 two to hydrogen and two to chlorine.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. Electron Geometry:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central carbon has <strong>four regions of electron density (4 single bonds)<\/strong>.<\/li>\n\n\n\n<li>According to <strong>VSEPR theory<\/strong>, four bonding groups with no lone pairs form a <strong>tetrahedral electron geometry<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>4. Molecular Geometry:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since all four regions are bonding pairs (no lone pairs), the <strong>molecular geometry is also tetrahedral<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>5. Bond Angles:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>In a tetrahedral geometry, the bond angles are approximately <strong>109.5\u00b0<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>6. Hybridization:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon forms four sigma (\u03c3) bonds \u2192 it uses <strong>sp\u00b3 hybrid orbitals<\/strong>.<\/li>\n\n\n\n<li>So, <strong>the hybridization at the central atom (C) is sp\u00b3<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answers:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Valence electrons<\/strong>: 20<\/li>\n\n\n\n<li><strong>Electron geometry<\/strong>: <strong>Tetrahedral<\/strong><\/li>\n\n\n\n<li><strong>Molecular geometry<\/strong>: <strong>Tetrahedral<\/strong><\/li>\n\n\n\n<li><strong>Bond angles<\/strong>: <strong>109.5\u00b0<\/strong><\/li>\n\n\n\n<li><strong>Hybridization<\/strong>: <strong>sp\u00b3<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>This analysis follows the <strong>VSEPR model<\/strong>, ensuring correct geometry and hybridization. CH\u2082Cl\u2082 is a polar molecule due to the difference in electronegativity between hydrogen and chlorine, and the asymmetrical shape leads to a net dipole moment.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Question 2 1 Pts Determine The Number Of Valence Electrons For CH2Cl2 And Draw The Lewis Structure. Based On Your Structure, The Electron Geometry Of This Molecule Is Select) The Molecular Geometry Is Select] Bond Angles Are [Select And The Hybridization At The Centralis Sp3 The Correct Answer and Explanation is: To answer this question [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-215297","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/215297","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=215297"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/215297\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=215297"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=215297"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=215297"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}