{"id":216629,"date":"2025-05-19T17:36:28","date_gmt":"2025-05-19T17:36:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=216629"},"modified":"2025-05-19T17:36:30","modified_gmt":"2025-05-19T17:36:30","slug":"draw-a-six-carbon-alkyne-that-can-exist-as-diastereomers-9","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/19\/draw-a-six-carbon-alkyne-that-can-exist-as-diastereomers-9\/","title":{"rendered":"Draw a six-carbon alkyne that can exist as diastereomers."},"content":{"rendered":"\n<p>Draw a six-carbon alkyne that can exist as diastereomers. You do not need to specify wedge or dashed bonds. Select Draw Rings More Erase \/ MICH 5 3 2 o<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To answer this question, we are tasked with <strong>drawing a six-carbon alkyne that can exist as diastereomers<\/strong> and explaining <strong>why diastereomerism is possible<\/strong> in this compound.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Correct Structure:<\/strong><\/h3>\n\n\n\n<p>The correct structure is:<br><strong>3-Hexyne with two different substituents on carbons 2 and 4<\/strong> \u2014 specifically:<br><strong>2-bromo-4-chloro-3-hexyne<\/strong><br>Structure:<br><strong>CH\u2083\u2013CH(Br)\u2013C\u2261C\u2013CH(Cl)\u2013CH\u2083<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u270f\ufe0f <strong>Explanation (Approx. 300 words):<\/strong><\/h3>\n\n\n\n<p>A <strong>diastereomer<\/strong> is a type of stereoisomer that is <strong>not a mirror image<\/strong> of another molecule and differs in the spatial arrangement of atoms across <strong>two or more chiral centers<\/strong>. In contrast to <strong>enantiomers<\/strong>, which are non-superimposable mirror images, <strong>diastereomers are non-mirror-image stereoisomers<\/strong>.<\/p>\n\n\n\n<p>To have diastereomers, we need:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>At least two stereocenters<\/strong>, and<\/li>\n\n\n\n<li><strong>Not all stereocenters are mirrored between the isomers<\/strong> (which would make them enantiomers).<\/li>\n<\/ul>\n\n\n\n<p>Now, let\u2019s consider the compound:<\/p>\n\n\n\n<p>\ud83d\udc49 <strong>2-bromo-4-chloro-3-hexyne (CH\u2083\u2013CH(Br)\u2013C\u2261C\u2013CH(Cl)\u2013CH\u2083)<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This is a <strong>six-carbon alkyne<\/strong> (satisfying the &#8220;six-carbon alkyne&#8221; requirement).<\/li>\n\n\n\n<li>The <strong>alkyne is at position 3<\/strong>, forming a linear, sp-hybridized carbon-carbon triple bond between C3 and C4.<\/li>\n\n\n\n<li>On <strong>C2 and C5<\/strong>, each has a carbon attached to <strong>a halogen (Br or Cl)<\/strong> and <strong>a hydrogen<\/strong>, plus different groups (methyl on one side and the alkyne group on the other), making them <strong>chiral centers<\/strong>.<\/li>\n\n\n\n<li>Because there are <strong>two chiral centers<\/strong> (on C2 and C5), this molecule can have <strong>multiple stereoisomers<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Let\u2019s look at the stereoisomers:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>RR and SS<\/strong> would be <strong>enantiomers<\/strong> (mirror images).<\/li>\n\n\n\n<li><strong>RS and SR<\/strong> are their own <strong>enantiomeric pair<\/strong>.<\/li>\n\n\n\n<li><strong>RR vs RS<\/strong>, for example, are <strong>diastereomers<\/strong> \u2014 not mirror images, and not superimposable.<\/li>\n<\/ul>\n\n\n\n<p>So, this compound has <strong>diastereomers<\/strong> due to the <strong>presence of two stereocenters<\/strong> that are <strong>not symmetrical<\/strong> and a fixed geometry around the <strong>alkyne bond<\/strong>, which does not allow free rotation.<\/p>\n\n\n\n<p>Thus, <strong>2-bromo-4-chloro-3-hexyne<\/strong> is a valid six-carbon alkyne that can exist as <strong>diastereomers<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw a six-carbon alkyne that can exist as diastereomers. You do not need to specify wedge or dashed bonds. Select Draw Rings More Erase \/ MICH 5 3 2 o The Correct Answer and Explanation is: To answer this question, we are tasked with drawing a six-carbon alkyne that can exist as diastereomers and explaining [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-216629","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/216629","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=216629"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/216629\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=216629"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=216629"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=216629"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}