{"id":216787,"date":"2025-05-20T11:37:43","date_gmt":"2025-05-20T11:37:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=216787"},"modified":"2025-05-20T11:37:45","modified_gmt":"2025-05-20T11:37:45","slug":"you-need-to-divide-the-number-of-cars-by-the-number-of-people-to-calculate-cars-per-person-on-day-1","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/20\/you-need-to-divide-the-number-of-cars-by-the-number-of-people-to-calculate-cars-per-person-on-day-1\/","title":{"rendered":"You need to divide the number of cars by the number of people to calculate cars per person on Day 1."},"content":{"rendered":"\n<p>You need to divide the number of cars by the number of people to calculate cars per person on Day 1.<\/p>\n\n\n\n<p>Image not displaying? Which formula can you type in Cell D92 to do this?<\/p>\n\n\n\n<p>O =B92\/C92<br>O =A92\/B92<br>O =10*3<br>O =B93\/C92<br>O =31<br>Rank the compounds below from lowest to highest melting point.<\/p>\n\n\n\n<p>Identify the carbon atoms in the three amino acids.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s break this into two parts:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Part 1: Excel Formula for Cars Per Person in Cell D92<\/strong><\/h3>\n\n\n\n<p>The correct formula to calculate <strong>cars per person<\/strong> on <strong>Day 1<\/strong> using values in <strong>cells B92 (number of cars)<\/strong> and <strong>C92 (number of people)<\/strong> is:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <code>=B92\/C92<\/code><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">Explanation:<\/h4>\n\n\n\n<p>In Excel:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><code>B92<\/code> contains the number of <strong>cars<\/strong>.<\/li>\n\n\n\n<li><code>C92<\/code> contains the number of <strong>people<\/strong>.<\/li>\n\n\n\n<li>To get <strong>cars per person<\/strong>, you divide the number of cars by the number of people.<\/li>\n<\/ul>\n\n\n\n<p>This formula directly divides the number in <code>B92<\/code> by the number in <code>C92<\/code>, giving you the desired &#8220;cars per person&#8221; figure.<\/p>\n\n\n\n<p>Incorrect options:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><code>=A92\/B92<\/code>: This uses the wrong column (<code>A92<\/code>) which might not contain relevant data.<\/li>\n\n\n\n<li><code>=10*3<\/code>: This multiplies two constants; it\u2019s unrelated to your data.<\/li>\n\n\n\n<li><code>=B93\/C92<\/code>: This uses data from the wrong row (<code>B93<\/code> instead of <code>B92<\/code>).<\/li>\n\n\n\n<li><code>=31<\/code>: This is a constant, not a calculation.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Part 2: Ranking Compounds by Melting Point<\/strong><\/h3>\n\n\n\n<p>To <strong>rank compounds from lowest to highest melting point<\/strong>, we need to understand molecular structure and intermolecular forces:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">General Ranking Rule (Lowest to Highest Melting Point):<\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Nonpolar molecules<\/strong> (only London dispersion forces)<\/li>\n\n\n\n<li><strong>Polar molecules<\/strong> (dipole-dipole forces)<\/li>\n\n\n\n<li><strong>Hydrogen bonding molecules<\/strong><\/li>\n\n\n\n<li><strong>Ionic compounds<\/strong> (strongest attractions)<\/li>\n<\/ol>\n\n\n\n<p>Example ranking:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CH\u2084 (methane)<\/strong> \u2013 Nonpolar, very low melting point<\/li>\n\n\n\n<li><strong>CH\u2083OH (methanol)<\/strong> \u2013 Polar with hydrogen bonding<\/li>\n\n\n\n<li><strong>NaCl (sodium chloride)<\/strong> \u2013 Ionic, very high melting point<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Ranking: <strong>CH\u2084 &lt; CH\u2083OH &lt; NaCl<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Part 3: Identify Carbon Atoms in Three Amino Acids<\/strong><\/h3>\n\n\n\n<p>Let\u2019s take three common amino acids:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Glycine (Gly)<\/strong> \u2013 Simplest amino acid<\/li>\n\n\n\n<li><strong>Alanine (Ala)<\/strong> \u2013 Contains a methyl side chain<\/li>\n\n\n\n<li><strong>Phenylalanine (Phe)<\/strong> \u2013 Contains a benzyl side chain<\/li>\n<\/ol>\n\n\n\n<p>Each amino acid has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Alpha carbon (C\u03b1)<\/strong> \u2013 Central carbon bonded to:\n<ul class=\"wp-block-list\">\n<li>Hydrogen<\/li>\n\n\n\n<li>Carboxyl group (\u2013COOH)<\/li>\n\n\n\n<li>Amino group (\u2013NH\u2082)<\/li>\n\n\n\n<li>R group (side chain)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Carbon Atoms in Each:<\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Glycine<\/strong>: 2 carbon atoms\n<ul class=\"wp-block-list\">\n<li>1 \u03b1-carbon<\/li>\n\n\n\n<li>1 carboxyl carbon<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Alanine<\/strong>: 3 carbon atoms\n<ul class=\"wp-block-list\">\n<li>1 \u03b1-carbon<\/li>\n\n\n\n<li>1 carboxyl carbon<\/li>\n\n\n\n<li>1 methyl side chain carbon<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Phenylalanine<\/strong>: 9 carbon atoms\n<ul class=\"wp-block-list\">\n<li>1 \u03b1-carbon<\/li>\n\n\n\n<li>1 carboxyl carbon<\/li>\n\n\n\n<li>1 \u03b2-carbon (attached to phenyl ring)<\/li>\n\n\n\n<li>6 carbons in the phenyl ring<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>In conclusion:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Excel: Use <code>=B92\/C92<\/code>.<\/li>\n\n\n\n<li>Ranking melting points: Based on forces.<\/li>\n\n\n\n<li>Carbon atoms: Identified by molecular structure and side chains.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>You need to divide the number of cars by the number of people to calculate cars per person on Day 1. Image not displaying? Which formula can you type in Cell D92 to do this? O =B92\/C92O =A92\/B92O =10*3O =B93\/C92O =31Rank the compounds below from lowest to highest melting point. Identify the carbon atoms in [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-216787","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/216787","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=216787"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/216787\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=216787"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=216787"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=216787"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}