{"id":216842,"date":"2025-05-20T13:31:58","date_gmt":"2025-05-20T13:31:58","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=216842"},"modified":"2025-05-20T13:32:00","modified_gmt":"2025-05-20T13:32:00","slug":"draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-18","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/20\/draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-18\/","title":{"rendered":"Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide."},"content":{"rendered":"\n<p>Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To solve this problem, we must <strong>determine the structure of the original alkene<\/strong> that, upon <strong>ozonolysis<\/strong> followed by <strong>reduction with dimethyl sulfide (DMS)<\/strong>, produces <strong>only one specific compound<\/strong> \u2014 typically a <strong>single carbonyl compound<\/strong> (like an aldehyde or ketone). Since the product is not specified in the question, let&#8217;s assume we are to find a general case where ozonolysis of a specific <strong>eight-carbon alkene<\/strong> produces a <strong>single product<\/strong> and <strong>no mixture<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answer (Structure):<\/strong><\/h3>\n\n\n\n<p>The correct eight-carbon alkene is:<\/p>\n\n\n\n<p><strong>4-octene (symmetrical, trans or cis)<\/strong><\/p>\n\n\n\n<p><strong>Structure of 4-octene:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>CH3-CH2-CH=CH-CH=CH-CH2-CH3  \u274c (not this; this is a diene)\n\nCH3-CH2-CH2-CH=CH-CH2-CH2-CH3  \u2705 (this is 4-octene)\n       |\n   This is symmetrical<\/code><\/pre>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300+ words):<\/strong><\/h3>\n\n\n\n<p><strong>Ozonolysis<\/strong> is a chemical reaction where an <strong>alkene is cleaved<\/strong> at the <strong>carbon-carbon double bond (C=C)<\/strong> using <strong>ozone (O\u2083)<\/strong>. When followed by reduction (commonly with <strong>dimethyl sulfide, DMS<\/strong>), it produces <strong>aldehydes and\/or ketones<\/strong>, depending on the groups attached to the double bond.<\/p>\n\n\n\n<p>In this question, we&#8217;re told that <strong>ozonolysis yields only one compound<\/strong>. This implies the original alkene must be <strong>symmetrical<\/strong> \u2014 because symmetrical alkenes give <strong>identical cleavage products<\/strong> on both sides of the double bond.<\/p>\n\n\n\n<p>Let\u2019s examine <strong>4-octene<\/strong>:<\/p>\n\n\n\n<p><strong>Structure of 4-octene<\/strong>:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>CH3\u2013CH2\u2013CH2\u2013CH=CH\u2013CH2\u2013CH2\u2013CH3\n       (double bond between C4 and C5)<\/code><\/pre>\n\n\n\n<p>Upon ozonolysis and reduction:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The double bond between carbon 4 and carbon 5 is broken.<\/li>\n\n\n\n<li>Each side becomes a <strong>carbonyl compound<\/strong> (specifically, <strong>butanal<\/strong> or <strong>butanone<\/strong>, depending on the substitution pattern).<\/li>\n<\/ul>\n\n\n\n<p>Because 4-octene is <strong>symmetrical<\/strong>, both sides of the double bond are identical:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Left side: CH3\u2013CH2\u2013CH2\u2013 (C4)<\/li>\n\n\n\n<li>Right side: \u2013CH2\u2013CH2\u2013CH3 (C5)<\/li>\n<\/ul>\n\n\n\n<p>This results in the formation of <strong>two identical molecules<\/strong> of the <strong>same aldehyde or ketone<\/strong>. There\u2019s <strong>no mixture<\/strong>, only <strong>one compound<\/strong> is formed.<\/p>\n\n\n\n<p>In contrast, if you used <strong>1-octene, 2-octene, or 3-octene<\/strong>, the two sides of the double bond would be <strong>asymmetrical<\/strong>, leading to the formation of <strong>two different products<\/strong> upon ozonolysis, violating the condition of the question.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<p>\u2705 The correct structure is <strong>4-octene<\/strong>:<br><strong>CH\u2083\u2013CH\u2082\u2013CH\u2082\u2013CH=CH\u2013CH\u2082\u2013CH\u2082\u2013CH\u2083<\/strong><\/p>\n\n\n\n<p>It is the <strong>only eight-carbon alkene<\/strong> that is <strong>symmetrical<\/strong>, and upon ozonolysis with dimethyl sulfide, yields <strong>one and only one product<\/strong> \u2014 satisfying the conditions of the question.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide. The Correct Answer and Explanation is: To solve this problem, we must determine the structure of the original alkene that, upon ozonolysis followed by reduction with dimethyl sulfide (DMS), produces only [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-216842","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/216842","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=216842"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/216842\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=216842"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=216842"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=216842"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}