{"id":217139,"date":"2025-05-21T04:34:18","date_gmt":"2025-05-21T04:34:18","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=217139"},"modified":"2025-05-21T04:34:20","modified_gmt":"2025-05-21T04:34:20","slug":"select-the-correct-iupac-name-for-the-branched-alcohol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/21\/select-the-correct-iupac-name-for-the-branched-alcohol\/","title":{"rendered":"Select the correct IUPAC name for the branched alcohol."},"content":{"rendered":"\n<p>Select the correct IUPAC name for the branched alcohol.<\/p>\n\n\n\n<p>The IUPAC name of the alcohol is:<\/p>\n\n\n\n<p>2-ethyl-4-methyl-5-propyl-1-hexanol<br>2-ethyl-4,5-dimethyl-1-octanol<br>4,5-dimethyl-7-propyl-8-octanol<br>3-hydroxymethyl-5,6-dimethylnonane<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct IUPAC name is:<br><strong>2-ethyl-4,5-dimethyl-1-octanol<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>To determine the correct IUPAC name for a branched alcohol, we follow the IUPAC nomenclature rules:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Identify the Longest Carbon Chain Containing the OH Group<\/strong><\/h3>\n\n\n\n<p>In IUPAC nomenclature for alcohols, the longest continuous carbon chain <strong>must<\/strong> include the <strong>hydroxyl (-OH)<\/strong> group. In this case, the correct name &#8220;2-ethyl-4,5-dimethyl-1-octanol&#8221; suggests the parent chain is <strong>octane<\/strong> (8 carbon atoms) and the OH group is on <strong>carbon 1<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Number the Carbon Chain<\/strong><\/h3>\n\n\n\n<p>Number the carbon atoms in such a way that the <strong>hydroxyl group gets the lowest possible number<\/strong>. That\u2019s why the OH is at position <strong>1<\/strong> in &#8220;1-octanol&#8221;.<\/p>\n\n\n\n<p>So the main chain is:<\/p>\n\n\n\n<p><strong>CH\u2083\u2013CH(Et)\u2013CH\u2082\u2013CH(Me)\u2013CH(Me)\u2013CH\u2082\u2013CH\u2082\u2013CH\u2082OH<\/strong><\/p>\n\n\n\n<p>Which gives us the following numbering:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>\u2013OH on C1<\/li>\n\n\n\n<li>Ethyl on C2<\/li>\n\n\n\n<li>Methyl on C4 and C5<\/li>\n<\/ol>\n\n\n\n<p>This matches <strong>&#8220;2-ethyl-4,5-dimethyl-1-octanol&#8221;<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Name the Substituents and Their Positions<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ethyl group<\/strong> at carbon <strong>2<\/strong> \u2192 &#8220;2-ethyl&#8221;<\/li>\n\n\n\n<li><strong>Methyl groups<\/strong> at carbons <strong>4 and 5<\/strong> \u2192 &#8220;4,5-dimethyl&#8221;<\/li>\n\n\n\n<li><strong>OH group<\/strong> at carbon <strong>1<\/strong> \u2192 &#8220;1-octanol&#8221;<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Why the Other Options Are Incorrect:<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>2-ethyl-4-methyl-5-propyl-1-hexanol<\/strong><br>\u2192 Parent chain is only 6 carbons (hexanol), even though a longer chain exists. Violates Rule 1.<\/li>\n\n\n\n<li><strong>4,5-dimethyl-7-propyl-8-octanol<\/strong><br>\u2192 The OH group is on carbon 8, which is not the lowest possible number. Should be carbon 1.<\/li>\n\n\n\n<li><strong>3-hydroxymethyl-5,6-dimethylnonane<\/strong><br>\u2192 The \u2013OH group is not on the main chain; it&#8217;s in a substituent (hydroxymethyl). Less preferred.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<p><strong>&#8220;2-ethyl-4,5-dimethyl-1-octanol&#8221;<\/strong> correctly follows all IUPAC rules:<br>\u2714 Longest chain includes OH<br>\u2714 OH has the lowest possible number<br>\u2714 Substituents are correctly named and located<\/p>\n\n\n\n<p>Hence, it is the correct IUPAC name.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Select the correct IUPAC name for the branched alcohol. The IUPAC name of the alcohol is: 2-ethyl-4-methyl-5-propyl-1-hexanol2-ethyl-4,5-dimethyl-1-octanol4,5-dimethyl-7-propyl-8-octanol3-hydroxymethyl-5,6-dimethylnonane The Correct Answer and Explanation is: The correct IUPAC name is:2-ethyl-4,5-dimethyl-1-octanol Explanation: To determine the correct IUPAC name for a branched alcohol, we follow the IUPAC nomenclature rules: Step 1: Identify the Longest Carbon Chain Containing the OH [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-217139","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217139","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=217139"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217139\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=217139"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=217139"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=217139"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}