{"id":217185,"date":"2025-05-21T06:54:42","date_gmt":"2025-05-21T06:54:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=217185"},"modified":"2025-05-21T06:54:44","modified_gmt":"2025-05-21T06:54:44","slug":"if-a-compound-is-reduced-what-is-the-result-5","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/21\/if-a-compound-is-reduced-what-is-the-result-5\/","title":{"rendered":"If a compound is reduced, what is the result"},"content":{"rendered":"\n<p>If a compound is reduced, what is the result?<\/p>\n\n\n\n<p>Fewer C-H bonds<br>Increased number of C-H bonds<br>Fewer C-Z bonds<br>Both increased number of C-H bonds and fewer C-Z bonds<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: Both increased number of C-H bonds and fewer C-Z bonds<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Explanation (300+ words):<\/strong><\/p>\n\n\n\n<p>In organic chemistry and biochemistry, <strong>reduction<\/strong> refers to the gain of electrons by a molecule, atom, or ion. When applied to organic compounds, reduction is typically characterized by changes in the number or type of bonds in a molecule. Specifically, two key indicators of reduction in organic molecules are:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>An increase in the number of carbon-hydrogen (C-H) bonds<\/strong><\/li>\n\n\n\n<li><strong>A decrease in the number of carbon-heteroatom bonds (C-Z bonds)<\/strong>, where &#8220;Z&#8221; represents a more electronegative atom like oxygen, nitrogen, or halogens.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Increased Number of C-H Bonds<\/strong><\/h3>\n\n\n\n<p>Reduction often involves the addition of hydrogen atoms to a compound. Since hydrogen has one electron, adding it can result in the molecule gaining electrons overall. In organic molecules, this typically leads to the <strong>formation of more C-H bonds<\/strong>, which is a hallmark of reduction. For instance:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The reduction of an <strong>alkene<\/strong> to an <strong>alkane<\/strong> involves the addition of hydrogen across the double bond, creating two new C-H bonds.<\/li>\n\n\n\n<li>The reduction of a <strong>carbonyl group (C=O)<\/strong> to an <strong>alcohol (C-OH)<\/strong> also involves the addition of hydrogen, forming a new C-H bond on the carbon.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Fewer C-Z Bonds<\/strong><\/h3>\n\n\n\n<p>Conversely, reduction often involves the <strong>removal of electronegative atoms or groups<\/strong> (like oxygen or halogens) bonded to carbon. These C-Z bonds are typically polar, with electrons being pulled toward the more electronegative atom. When these bonds are replaced by hydrogen (as in reductions), the molecule becomes <strong>less oxidized and more reduced<\/strong>.<\/p>\n\n\n\n<p>For example:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The reduction of a <strong>carboxylic acid (R-COOH)<\/strong> to a <strong>primary alcohol (R-CH2OH)<\/strong> results in the loss of two C-O bonds (C-Z bonds) and the gain of two C-H bonds.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<p>Thus, a compound is considered <strong>reduced<\/strong> when:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>It <strong>gains hydrogen atoms<\/strong> (increased C-H bonds)<\/li>\n\n\n\n<li>It <strong>loses electronegative atoms<\/strong> (fewer C-Z bonds)<\/li>\n<\/ul>\n\n\n\n<p>This explains why the best answer is:<br><strong>&#8220;Both increased number of C-H bonds and fewer C-Z bonds.&#8221;<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>If a compound is reduced, what is the result? Fewer C-H bondsIncreased number of C-H bondsFewer C-Z bondsBoth increased number of C-H bonds and fewer C-Z bonds The Correct Answer and Explanation is: Correct Answer: Both increased number of C-H bonds and fewer C-Z bonds Explanation (300+ words): In organic chemistry and biochemistry, reduction refers [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-217185","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217185","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=217185"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217185\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=217185"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=217185"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=217185"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}