{"id":217525,"date":"2025-05-22T04:51:49","date_gmt":"2025-05-22T04:51:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=217525"},"modified":"2025-05-22T04:51:51","modified_gmt":"2025-05-22T04:51:51","slug":"ironii-iodate-express-your-answer-as-a-chemical-formula","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/22\/ironii-iodate-express-your-answer-as-a-chemical-formula\/","title":{"rendered":"Iron(II) iodate Express your answer as a chemical formula."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Iron(II) iodate Express your answer as a chemical formula.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answer: Fe(IO\u2083)\u2082<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (Approx. 300 Words):<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the chemical formula of <strong>iron(II) iodate<\/strong>, we need to understand the charges of the ions involved and how they combine to form a neutral compound.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Identify the Ions<\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Iron(II)<\/strong>:<br>The Roman numeral &#8220;II&#8221; indicates the oxidation state of the iron ion.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Iron(II) means <strong>Fe\u00b2\u207a<\/strong>, which is a <strong>cation<\/strong> (positively charged ion).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Iodate<\/strong>:<br>Iodate is a <strong>polyatomic anion<\/strong>.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Its formula is <strong>IO\u2083\u207b<\/strong> and it carries a <strong>-1 charge<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Balance the Charges<\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">In an ionic compound, the total positive and negative charges must balance (equal zero overall charge).<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>One Fe\u00b2\u207a ion has a <strong>+2 charge<\/strong>.<\/li>\n\n\n\n<li>One IO\u2083\u207b ion has a <strong>-1 charge<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">To balance:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>We need <strong>two IO\u2083\u207b<\/strong> ions (each -1) to balance one Fe\u00b2\u207a ion (+2).<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Mathematically:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(+2) + 2\u00d7(-1) = 0<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 3: Write the Formula<\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">Since we need:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1 Fe\u00b2\u207a<\/strong> ion<\/li>\n\n\n\n<li><strong>2 IO\u2083\u207b<\/strong> ions<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">We write the formula as:<br><strong>Fe(IO\u2083)\u2082<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Parentheses are used around the <strong>IO\u2083<\/strong> because there are <strong>two of them<\/strong>, and IO\u2083 is a <strong>polyatomic ion<\/strong>.<\/li>\n\n\n\n<li>The subscript &#8220;2&#8221; outside the parentheses indicates two iodate ions are present.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Summary<\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">The compound <strong>iron(II) iodate<\/strong> consists of one iron(II) cation (<strong>Fe\u00b2\u207a<\/strong>) and two iodate anions (<strong>IO\u2083\u207b<\/strong>), resulting in the chemical formula <strong>Fe(IO\u2083)\u2082<\/strong>. This compound is ionic, meaning it is held together by the electrostatic attraction between the positively charged iron ion and the negatively charged iodate ions. Understanding oxidation states and polyatomic ions is essential for correctly writing formulas for such compounds.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Iron(II) iodate Express your answer as a chemical formula. The Correct Answer and Explanation is: Correct Answer: Fe(IO\u2083)\u2082 Explanation (Approx. 300 Words): To determine the chemical formula of iron(II) iodate, we need to understand the charges of the ions involved and how they combine to form a neutral compound. Step 1: Identify the Ions Step [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-217525","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217525","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=217525"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217525\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=217525"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=217525"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=217525"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}