{"id":217528,"date":"2025-05-22T04:55:21","date_gmt":"2025-05-22T04:55:21","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=217528"},"modified":"2025-05-22T04:55:24","modified_gmt":"2025-05-22T04:55:24","slug":"draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-19","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/22\/draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-19\/","title":{"rendered":"Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To answer this question, we need to:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the product<\/strong> that results from ozonolysis followed by reductive workup (with <strong>dimethyl sulfide (DMS)<\/strong>).<\/li>\n\n\n\n<li><strong>Work backward<\/strong> to deduce the original <strong>alkene structure<\/strong>.<\/li>\n\n\n\n<li>Ensure the alkene contains <strong>eight carbon atoms<\/strong> and produces <strong>only one product<\/strong> upon ozonolysis, which means the alkene is <strong>symmetrical<\/strong> or the cleavage results in identical products.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understanding Ozonolysis<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Ozonolysis is a reaction where <strong>alkenes are cleaved at the double bond<\/strong>, and each carbon of the double bond is converted into a <strong>carbonyl group<\/strong> (either an aldehyde or ketone). When followed by <strong>dimethyl sulfide (DMS)<\/strong>, the reaction yields <strong>aldehydes or ketones<\/strong>, not carboxylic acids.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Drawing the Product<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Let\u2019s say the ozonolysis yields <strong>two molecules of butanal (CH\u2083CH\u2082CH\u2082CHO)<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">That would mean the double bond was between two <strong>butyl groups<\/strong> (CH\u2083CH\u2082CH\u2082\u2013CH=CH\u2013CH\u2082CH\u2082CH\u2083).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Reconstructing the Alkene<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Since ozonolysis cleaves the double bond and replaces each double-bonded carbon with a carbonyl oxygen, we reverse the process to find the original alkene.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Two molecules of <strong>butanal (CH\u2083CH\u2082CH\u2082CHO)<\/strong> would result from the cleavage of <strong>oct-4-ene<\/strong>, with the structure:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>CH\u2083CH\u2082CH\u2082\u2013CH=CH\u2013CH\u2082CH\u2082CH\u2083<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This is an <strong>eight-carbon (C\u2088) alkene<\/strong>. The double bond is between carbon 4 and 5, which is <strong>centrally located<\/strong>, and <strong>symmetrical<\/strong>, so ozonolysis yields <strong>only one product<\/strong>: butanal.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The correct structure is <strong>oct-4-ene<\/strong>:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>CH\u2083\u2013CH\u2082\u2013CH\u2082\u2013CH=CH\u2013CH\u2082\u2013CH\u2082\u2013CH\u2083<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary Explanation (300 words):<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">When an alkene undergoes ozonolysis followed by treatment with dimethyl sulfide (DMS), the double bond is cleaved, and each of the carbon atoms formerly involved in the double bond is converted into a carbonyl group. DMS is a reducing agent, so the carbonyl groups will be aldehydes or ketones, <strong>not carboxylic acids<\/strong> (which would form under oxidative conditions). The goal in this problem is to find an <strong>eight-carbon alkene<\/strong> that yields <strong>only one product<\/strong> after ozonolysis and reduction. This condition suggests that the molecule must be <strong>symmetrical<\/strong>, so the cleavage at the double bond produces <strong>identical fragments<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">If the ozonolysis product is <strong>butanal<\/strong> (a four-carbon aldehyde), then two identical butanal molecules would combine to form the alkene. Reversing the ozonolysis process, we determine the original alkene was formed by joining the aldehyde groups via a double bond. Thus, the original compound must have had the structure <strong>CH\u2083CH\u2082CH\u2082\u2013CH=CH\u2013CH\u2082CH\u2082CH\u2083<\/strong>, which is <strong>oct-4-ene<\/strong>. It has a total of 8 carbon atoms and a double bond at the central position (between C-4 and C-5). When cleaved by ozone, it splits into two molecules of butanal. Because of its symmetry, <strong>no other products<\/strong> form, satisfying the condition in the problem. Hence, <strong>oct-4-ene<\/strong> is the only eight-carbon alkene that will yield a single ozonolysis product under these conditions.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Let me know if you&#8217;d like to see a diagram of the molecule.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide. The Correct Answer and Explanation is: To answer this question, we need to: Step 1: Understanding Ozonolysis Ozonolysis is a reaction where alkenes are cleaved at the double bond, and each [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-217528","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217528","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=217528"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/217528\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=217528"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=217528"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=217528"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}