{"id":219103,"date":"2025-05-25T15:37:45","date_gmt":"2025-05-25T15:37:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219103"},"modified":"2025-05-25T15:37:47","modified_gmt":"2025-05-25T15:37:47","slug":"choose-the-compound-below-that-contains-at-least-one-polar-covalent-bond-but-is-nonpolar","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/25\/choose-the-compound-below-that-contains-at-least-one-polar-covalent-bond-but-is-nonpolar\/","title":{"rendered":"Choose the compound below that contains at least one polar covalent bond, but is nonpolar."},"content":{"rendered":"\n<p>Choose the compound below that contains at least one polar covalent bond, but is nonpolar.<\/p>\n\n\n\n<p>SCl2<br>CH2Cl2<br>AsCl5<br>GeH2Br2<br>All of the above are nonpolar and contain a polar covalent bond.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is: <strong>AsCl\u2085 (Arsenic pentachloride)<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>To answer this question, we must evaluate each compound for two criteria:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Presence of polar covalent bonds<\/strong>: These occur between atoms with different electronegativities.<\/li>\n\n\n\n<li><strong>Overall molecular polarity<\/strong>: A molecule is <strong>nonpolar<\/strong> if the bond dipoles cancel out due to its symmetrical geometry.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>SCl\u2082 (Sulfur dichloride)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Polar bonds<\/strong>: Yes, due to difference in electronegativity between S and Cl.<\/li>\n\n\n\n<li><strong>Molecular shape<\/strong>: Bent (due to two lone pairs on S).<\/li>\n\n\n\n<li><strong>Net dipole<\/strong>: Yes.<br><strong>Result<\/strong>: Polar molecule.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>CH\u2082Cl\u2082 (Dichloromethane)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Polar bonds<\/strong>: Yes, especially C\u2013Cl bonds.<\/li>\n\n\n\n<li><strong>Molecular shape<\/strong>: Tetrahedral, but asymmetrical.<\/li>\n\n\n\n<li><strong>Net dipole<\/strong>: Yes.<br><strong>Result<\/strong>: Polar molecule.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>AsCl\u2085 (Arsenic pentachloride)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Polar bonds<\/strong>: Yes, As\u2013Cl bonds are polar.<\/li>\n\n\n\n<li><strong>Molecular shape<\/strong>: Trigonal bipyramidal (symmetrical).<\/li>\n\n\n\n<li><strong>Net dipole<\/strong>: No; the individual bond dipoles cancel out.<br><strong>Result<\/strong>: <strong>Nonpolar molecule with polar bonds<\/strong><\/li>\n\n\n\n<li><br>\u2705 <strong>Correct Answer<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">4. <strong>GeH\u2082Br\u2082 (Germanium dibromide)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Polar bonds<\/strong>: Yes (Ge\u2013Br especially).<\/li>\n\n\n\n<li><strong>Molecular shape<\/strong>: Tetrahedral but asymmetrical if the Br and H are not symmetrically arranged.<\/li>\n\n\n\n<li><strong>Net dipole<\/strong>: Yes.<br><strong>Result<\/strong>: Polar molecule.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>All the compounds contain <strong>polar covalent bonds<\/strong>, but <strong>only AsCl\u2085<\/strong> is <strong>nonpolar overall<\/strong> due to its <strong>symmetrical geometry<\/strong> that allows dipole cancellation. The others have asymmetrical shapes leading to molecular polarity. Thus, the compound that satisfies both criteria (having at least one polar covalent bond and being nonpolar) is <strong>AsCl\u2085<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner7-2.jpeg\" alt=\"\" class=\"wp-image-219104\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Choose the compound below that contains at least one polar covalent bond, but is nonpolar. SCl2CH2Cl2AsCl5GeH2Br2All of the above are nonpolar and contain a polar covalent bond. The Correct Answer and Explanation is: The correct answer is: AsCl\u2085 (Arsenic pentachloride) Explanation To answer this question, we must evaluate each compound for two criteria: 1. SCl\u2082 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219103","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219103","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219103"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219103\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219103"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219103"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219103"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}