{"id":219210,"date":"2025-05-25T20:05:05","date_gmt":"2025-05-25T20:05:05","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219210"},"modified":"2025-05-25T20:05:08","modified_gmt":"2025-05-25T20:05:08","slug":"identify-the-function-represented-by-the-following-power-series-sigma-1kxk-3k-click-the-icon-to-view-a-table-of-taylor-series-for-common-functions-fx-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/25\/identify-the-function-represented-by-the-following-power-series-sigma-1kxk-3k-click-the-icon-to-view-a-table-of-taylor-series-for-common-functions-fx-3\/","title":{"rendered":"Identify the function represented by the following power series Sigma (-1)kxk\/3k\u00a0Click the icon to view a table of Taylor series for common functions F(x) ="},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Identify the function represented by the following power series Sigma (-1)<sup>k<\/sup>x<sup>k<\/sup>\/3<sup>k<\/sup>&nbsp;Click the icon to view a table of Taylor series for common functions F(x) =<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To identify the function represented by the power series \u2211k=0\u221e(\u22121)kxk3k\\sum_{k=0}^{\\infty} \\frac{(-1)^k x^k}{3^k}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">we begin by analyzing its structure.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Recognize the Form of the Power Series<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The given series is: \u2211k=0\u221e(\u2212x3)k=1\u2212x3+x29\u2212x327+\u22ef\\sum_{k=0}^{\\infty} \\left(\\frac{-x}{3}\\right)^k = 1 &#8211; \\frac{x}{3} + \\frac{x^2}{9} &#8211; \\frac{x^3}{27} + \\cdots<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This is a geometric series of the form: \u2211k=0\u221erk=11\u2212r,for&nbsp;\u2223r\u2223&lt;1\\sum_{k=0}^{\\infty} r^k = \\frac{1}{1 &#8211; r}, \\quad \\text{for } |r| &lt; 1<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Here, the common ratio is r=\u2212x3r = -\\frac{x}{3}. Therefore, the sum of the series is: 11\u2212(\u2212x3)=11+x3=13+x3=3x+3\\frac{1}{1 &#8211; \\left(-\\frac{x}{3}\\right)} = \\frac{1}{1 + \\frac{x}{3}} = \\frac{1}{\\frac{3 + x}{3}} = \\frac{3}{x + 3}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">F(x)=3x+3F(x) = \\frac{3}{x + 3}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"> Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The given power series \u2211k=0\u221e(\u22121)kxk3k\\sum_{k=0}^{\\infty} \\frac{(-1)^k x^k}{3^k}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">can be simplified by recognizing it as a geometric series. A geometric series is one of the most fundamental and recognizable types of series in mathematics. It has the general form: \u2211k=0\u221erk=11\u2212r\\sum_{k=0}^{\\infty} r^k = \\frac{1}{1 &#8211; r}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">provided the absolute value of the common ratio \u2223r\u2223&lt;1|r| &lt; 1.<br>In our case, each term of the series is (\u2212x3)k\\left(-\\frac{x}{3}\\right)^k<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This means the series is geometric with a common ratio of r=\u2212x3r = -\\frac{x}{3}. So long as \u2223x\u2223&lt;3|x| &lt; 3, the series converges.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Using the formula for the sum of an infinite geometric series: \u2211k=0\u221e(\u2212x3)k=11+x3\\sum_{k=0}^{\\infty} \\left(-\\frac{x}{3}\\right)^k = \\frac{1}{1 + \\frac{x}{3}}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To simplify, multiply both numerator and denominator by 3: 11+x3=3x+3\\frac{1}{1 + \\frac{x}{3}} = \\frac{3}{x + 3}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, this power series represents the function F(x)=3x+3F(x) = \\frac{3}{x + 3}, valid for \u2223x\u2223&lt;3|x| &lt; 3. Recognizing power series as geometric series helps in identifying functions they represent, which is particularly useful in calculus and mathematical modeling.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner5-6.jpeg\" alt=\"\" class=\"wp-image-219211\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Identify the function represented by the following power series Sigma (-1)kxk\/3k&nbsp;Click the icon to view a table of Taylor series for common functions F(x) = The Correct Answer and Explanation is: To identify the function represented by the power series \u2211k=0\u221e(\u22121)kxk3k\\sum_{k=0}^{\\infty} \\frac{(-1)^k x^k}{3^k} we begin by analyzing its structure. Step 1: Recognize the Form of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219210","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219210","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219210"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219210\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219210"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219210"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219210"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}