{"id":219225,"date":"2025-05-25T20:34:18","date_gmt":"2025-05-25T20:34:18","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219225"},"modified":"2025-05-25T20:34:20","modified_gmt":"2025-05-25T20:34:20","slug":"identify-the-function-represented-by-the-following-power-series-sigma-1kxk-3k-click-the-icon-to-view-a-table-of-taylor-series-for-common-functions-fx-4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/25\/identify-the-function-represented-by-the-following-power-series-sigma-1kxk-3k-click-the-icon-to-view-a-table-of-taylor-series-for-common-functions-fx-4\/","title":{"rendered":"Identify the function represented by the following power series Sigma (-1)kxk\/3k Click the icon to view a table of Taylor series for common functions F(x) ="},"content":{"rendered":"\n

Identify the function represented by the following power series Sigma (-1)kxk\/3k Click the icon to view a table of Taylor series for common functions F(x) =<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The given power series is: \u2211k=0\u221e(\u22121)kxk3k\\sum_{k=0}^{\\infty} \\frac{(-1)^k x^k}{3^k}<\/p>\n\n\n\n

This can be rewritten as: \u2211k=0\u221e(\u2212x3)k\\sum_{k=0}^{\\infty} \\left(\\frac{-x}{3}\\right)^k<\/p>\n\n\n\n

This is a geometric series<\/strong> of the form: \u2211k=0\u221erk=11\u2212r,for \u2223r\u2223<1\\sum_{k=0}^{\\infty} r^k = \\frac{1}{1 – r}, \\quad \\text{for } |r| < 1<\/p>\n\n\n\n

Step-by-step Identification:<\/h3>\n\n\n\n

We recognize the form: \u2211k=0\u221e(\u2212x3)k\\sum_{k=0}^{\\infty} \\left(\\frac{-x}{3}\\right)^k<\/p>\n\n\n\n

This means the common ratio<\/strong> r=\u2212x3r = \\frac{-x}{3}. Applying the geometric series formula: F(x)=11\u2212(\u2212x\/3)=11+x\/3F(x) = \\frac{1}{1 – (-x\/3)} = \\frac{1}{1 + x\/3}<\/p>\n\n\n\n

Now simplify: F(x)=13+x3=33+xF(x) = \\frac{1}{\\frac{3 + x}{3}} = \\frac{3}{3 + x}<\/p>\n\n\n\n

\u2705 Final Answer:<\/h3>\n\n\n\n

F(x)=33+x\\boxed{F(x) = \\frac{3}{3 + x}}<\/p>\n\n\n\n

\n\n\n\n

\u270d\ufe0f Explanation <\/h3>\n\n\n\n

The given series is: \u2211k=0\u221e(\u22121)kxk3k\\sum_{k=0}^{\\infty} \\frac{(-1)^k x^k}{3^k}<\/p>\n\n\n\n

To understand what function this series represents, we look for patterns that match known Taylor or power series. This series is in the form of a geometric series<\/strong>, which is one of the most common and easily recognizable types. A geometric series has the general form: \u2211k=0\u221erk=11\u2212r\\sum_{k=0}^{\\infty} r^k = \\frac{1}{1 – r}<\/p>\n\n\n\n

provided that the absolute value of the common ratio, \u2223r\u2223|r|, is less than 1 (ensuring convergence).<\/p>\n\n\n\n

In our case, we can rewrite the series: \u2211k=0\u221e(\u2212x3)k\\sum_{k=0}^{\\infty} \\left(\\frac{-x}{3}\\right)^k<\/p>\n\n\n\n

Here, the common ratio r=\u2212x\/3r = -x\/3. Because this is a geometric series, we can apply the formula for the sum of a geometric series: \u2211k=0\u221erk=11\u2212r\\sum_{k=0}^{\\infty} r^k = \\frac{1}{1 – r}<\/p>\n\n\n\n

Plugging in r=\u2212x\/3r = -x\/3: F(x)=11\u2212(\u2212x\/3)=11+x\/3F(x) = \\frac{1}{1 – (-x\/3)} = \\frac{1}{1 + x\/3}<\/p>\n\n\n\n

Simplifying this expression to a single rational function: F(x)=33+xF(x) = \\frac{3}{3 + x}<\/p>\n\n\n\n

This is a well-defined function for all x\u2260\u22123x \\neq -3, and the power series converges for \u2223x\u2223<3|x| < 3. Hence, the function represented by the original power series is: F(x)=33+x\\boxed{F(x) = \\frac{3}{3 + x}}<\/p>\n\n\n\n

\"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

Identify the function represented by the following power series Sigma (-1)kxk\/3k Click the icon to view a table of Taylor series for common functions F(x) = The Correct Answer and Explanation is: The given power series is: \u2211k=0\u221e(\u22121)kxk3k\\sum_{k=0}^{\\infty} \\frac{(-1)^k x^k}{3^k} This can be rewritten as: \u2211k=0\u221e(\u2212x3)k\\sum_{k=0}^{\\infty} \\left(\\frac{-x}{3}\\right)^k This is a geometric series of the form: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219225","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219225","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219225"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219225\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219225"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219225"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219225"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}