{"id":219366,"date":"2025-05-26T04:45:47","date_gmt":"2025-05-26T04:45:47","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219366"},"modified":"2025-05-26T04:45:49","modified_gmt":"2025-05-26T04:45:49","slug":"imagine-that-you-conducted-the-reduction-of-benzophenone-in-class-and-proceeded-to-take-the-ir-of-your-materials","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/26\/imagine-that-you-conducted-the-reduction-of-benzophenone-in-class-and-proceeded-to-take-the-ir-of-your-materials\/","title":{"rendered":"Imagine that you conducted the reduction of benzophenone in class and proceeded to take the IR of your materials."},"content":{"rendered":"\n<p>Imagine that you conducted the reduction of benzophenone in class and proceeded to take the IR of your materials. You know that you can observe the success of a reaction by using Infrared Spectroscopy (IR) and comparing the spectra of the starting material and the final product. Attached is the IR spectra of benzophenone (starting material) and diphenylmethanol (final product) that you collected for your experiment. Please analyze the spectra and indicate the peaks or changes in peaks to which you, as a chemist, would look for in order to show the success of this experiment. Based on these spectra and the peaks you indicated as relevant, was your experiment successful?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here is the chirality status of each molecule:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>3,3-dimethylheptane<\/strong> \u2013 <strong>Not chiral<\/strong><\/li>\n\n\n\n<li><strong>2,3-dimethylheptane<\/strong> \u2013 <strong>Chiral<\/strong><\/li>\n\n\n\n<li><strong>2-methylheptane<\/strong> \u2013 <strong>Not chiral<\/strong><\/li>\n\n\n\n<li><strong>3-methylheptane<\/strong> \u2013 <strong>Not chiral<\/strong><\/li>\n\n\n\n<li><strong>4-methylheptane<\/strong> \u2013 <strong>Not chiral<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>Chirality in organic molecules occurs when a carbon atom is bonded to four different groups, creating a stereocenter (also called a chiral center). A molecule with at least one chiral center and no internal plane of symmetry is considered chiral\u2014it cannot be superimposed on its mirror image.<\/p>\n\n\n\n<p>Let\u2019s analyze each compound:<\/p>\n\n\n\n<p><strong>1. 3,3-Dimethylheptane:<\/strong><br>The carbon at position 3 has two identical methyl groups (\u2013CH\u2083), so it <strong>cannot<\/strong> be a chiral center because it lacks four different groups. The rest of the molecule also lacks any carbon with four different substituents. Therefore, it is <strong>not chiral<\/strong>.<\/p>\n\n\n\n<p><strong>2. 2,3-Dimethylheptane:<\/strong><br>This molecule can have a <strong>chiral center<\/strong> at carbon 3, which is bonded to:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A hydrogen,<\/li>\n\n\n\n<li>A methyl group,<\/li>\n\n\n\n<li>An ethyl chain (from carbon 2 and back to carbon 1),<\/li>\n\n\n\n<li>A longer alkyl chain (from carbon 4 onward).<\/li>\n<\/ul>\n\n\n\n<p>Since carbon 3 has four different groups, it is a stereocenter. Therefore, <strong>2,3-dimethylheptane is chiral<\/strong>.<\/p>\n\n\n\n<p><strong>3. 2-Methylheptane:<\/strong><br>Here, carbon 2 is attached to:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A methyl group,<\/li>\n\n\n\n<li>A hydrogen,<\/li>\n\n\n\n<li>An ethyl chain (toward carbon 1),<\/li>\n\n\n\n<li>A longer alkyl chain (toward carbon 3\u20137).<\/li>\n<\/ul>\n\n\n\n<p>It may seem chiral, but the two chains are not different enough\u2014upon closer analysis, the molecule is <strong>not chiral<\/strong> due to symmetry or lack of a true stereocenter.<\/p>\n\n\n\n<p><strong>4. 3-Methylheptane:<\/strong><br>Carbon 3 appears similar to 2-methylheptane\u2019s situation\u2014when analyzing the attached groups, they are not all distinct. Therefore, this molecule is <strong>not chiral<\/strong>.<\/p>\n\n\n\n<p><strong>5. 4-Methylheptane:<\/strong><br>Likewise, carbon 4 is not bonded to four different groups, so there\u2019s <strong>no chiral center<\/strong>. It is <strong>not chiral<\/strong>.<\/p>\n\n\n\n<p>In summary, <strong>only 2,3-dimethylheptane<\/strong> is chiral because it has a carbon with four distinct substituents.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner6-17.jpeg\" alt=\"\" class=\"wp-image-219367\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Imagine that you conducted the reduction of benzophenone in class and proceeded to take the IR of your materials. You know that you can observe the success of a reaction by using Infrared Spectroscopy (IR) and comparing the spectra of the starting material and the final product. Attached is the IR spectra of benzophenone (starting [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219366","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219366","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219366"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219366\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219366"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219366"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219366"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}