{"id":219589,"date":"2025-05-26T11:29:51","date_gmt":"2025-05-26T11:29:51","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219589"},"modified":"2025-05-26T11:29:53","modified_gmt":"2025-05-26T11:29:53","slug":"if-you-add-sucrose-to-catalase-when-testing-for-reactivity-do-you-expect-to-see-a-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/26\/if-you-add-sucrose-to-catalase-when-testing-for-reactivity-do-you-expect-to-see-a-reaction\/","title":{"rendered":"If you add sucrose to catalase when testing for reactivity, do you expect to see a reaction"},"content":{"rendered":"\n<p>If you add sucrose to catalase when testing for reactivity, do you expect to see a reaction?<\/p>\n\n\n\n<p>Multiple Choice<\/p>\n\n\n\n<p>Yes, because catalase binds all chemicals<br>Yes, because catalase is an enzyme that increases any reaction rate.<br>No, because catalase is specific to sucrose<br>No, because catalase is specific to hydrogen peroxide.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><br><strong>No, because catalase is specific to hydrogen peroxide.<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Explanation<\/strong><\/p>\n\n\n\n<p>Catalase is a highly specific enzyme that catalyzes the decomposition of <strong>hydrogen peroxide (H\u2082O\u2082)<\/strong> into <strong>water (H\u2082O)<\/strong> and <strong>oxygen gas (O\u2082)<\/strong>. The reaction it facilitates is:<\/p>\n\n\n\n<p>2H2O2\u21922H2O+O22H_2O_2 \\rightarrow 2H_2O + O_2<\/p>\n\n\n\n<p>This specificity arises from the unique structure of catalase&#8217;s active site, which is shaped precisely to bind hydrogen peroxide molecules. Enzymes are not general-purpose catalysts\u2014they are <strong>substrate-specific<\/strong>, meaning they only catalyze reactions involving certain molecules that fit their active site. The principle behind this is often compared to a &#8220;lock and key&#8221; mechanism, where only the right key (substrate) fits the lock (enzyme).<\/p>\n\n\n\n<p>Sucrose, on the other hand, is a disaccharide sugar composed of glucose and fructose. It does not resemble hydrogen peroxide in structure or chemical properties. Since sucrose does not fit the active site of catalase, the enzyme cannot bind to or act on sucrose. Therefore, <strong>no reaction would occur<\/strong> if sucrose were added to catalase in the absence of hydrogen peroxide.<\/p>\n\n\n\n<p>If a reaction were expected with sucrose, it would require a different enzyme altogether\u2014<strong>sucrase<\/strong> (also known as <strong>invertase<\/strong>)\u2014which specifically breaks down sucrose into its component monosaccharides.<\/p>\n\n\n\n<p>The other options in the multiple-choice question are incorrect because:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>&#8220;Yes, because catalase binds all chemicals&#8221;<\/strong> is false\u2014enzymes do not bind all chemicals.<\/li>\n\n\n\n<li><strong>&#8220;Yes, because catalase is an enzyme that increases any reaction rate&#8221;<\/strong> is incorrect\u2014enzymes are highly specific to particular reactions.<\/li>\n\n\n\n<li><strong>&#8220;No, because catalase is specific to sucrose&#8221;<\/strong> is incorrect\u2014catalase is not specific to sucrose; it is specific to hydrogen peroxide.<\/li>\n<\/ul>\n\n\n\n<p>In conclusion, <strong>catalase only reacts with hydrogen peroxide<\/strong>, and adding sucrose will not trigger any enzymatic reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner8-23.jpeg\" alt=\"\" class=\"wp-image-219590\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>If you add sucrose to catalase when testing for reactivity, do you expect to see a reaction? Multiple Choice Yes, because catalase binds all chemicalsYes, because catalase is an enzyme that increases any reaction rate.No, because catalase is specific to sucroseNo, because catalase is specific to hydrogen peroxide. The Correct Answer and Explanation is: Correct [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219589","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219589","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219589"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219589\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219589"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219589"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219589"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}