{"id":219667,"date":"2025-05-26T13:51:08","date_gmt":"2025-05-26T13:51:08","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219667"},"modified":"2025-05-26T13:51:10","modified_gmt":"2025-05-26T13:51:10","slug":"what-is-the-atomic-mass-of-copper","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/26\/what-is-the-atomic-mass-of-copper\/","title":{"rendered":"What is the atomic mass of copper"},"content":{"rendered":"\n<p><a href=\"https:\/\/www.google.co.ke\/intl\/en\/about\/products?tab=wh\" target=\"_blank\" rel=\"noopener\"><\/a><\/p>\n\n\n\n<p>What is the atomic mass of copper, Cu? 2. How many grams are there in 36.34 moles of Cu? 3. How many moles are there in 3.7 \u00d7 105 grams of Cu? 4. How many copper atoms are there in 92.56 moles of Cu? 5. How many copper atoms are there in 0.104 grams of Cu<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation\u00a0is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Answers:<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Atomic mass of copper (Cu):<\/strong><br><strong>63.55 g\/mol<\/strong><\/li>\n\n\n\n<li><strong>Mass in grams for 36.34 moles of Cu:<\/strong><br>Mass=Moles\u00d7Atomic\u00a0Mass\\text{Mass} = \\text{Moles} \\times \\text{Atomic Mass}<br>=36.34\u2009mol\u00d763.55\u2009g\/mol=2,311.65\u2009g= 36.34 \\, \\text{mol} \\times 63.55 \\, \\text{g\/mol} = \\boxed{2,311.65 \\, \\text{g}}<\/li>\n\n\n\n<li><strong>Moles in 3.7 \u00d7 10\u2075 grams of Cu:<\/strong><br>Moles=MassAtomic\u00a0Mass\\text{Moles} = \\frac{\\text{Mass}}{\\text{Atomic Mass}}<br>=3.7\u00d710563.55\u22485,823.86\u2009mol= \\frac{3.7 \\times 10^5}{63.55} \\approx \\boxed{5,823.86 \\, \\text{mol}}<\/li>\n\n\n\n<li><strong>Atoms in 92.56 moles of Cu:<\/strong><br>Atoms=Moles\u00d7Avogadro\u2019s\u00a0Number\\text{Atoms} = \\text{Moles} \\times \\text{Avogadro&#8217;s Number}<br>=92.56\u00d76.022\u00d71023\u22485.574\u00d71025\u2009atoms= 92.56 \\times 6.022 \\times 10^{23} \\approx \\boxed{5.574 \\times 10^{25} \\, \\text{atoms}}<\/li>\n\n\n\n<li><strong>Atoms in 0.104 grams of Cu:<\/strong><br>Step 1: Find moles<br>Moles=0.10463.55\u22480.001637\u2009mol\\text{Moles} = \\frac{0.104}{63.55} \\approx 0.001637 \\, \\text{mol}<br>Step 2: Multiply by Avogadro&#8217;s Number<br>Atoms=0.001637\u00d76.022\u00d71023\u22489.86\u00d71020\u2009atoms\\text{Atoms} = 0.001637 \\times 6.022 \\times 10^{23} \\approx \\boxed{9.86 \\times 10^{20} \\, \\text{atoms}}<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>Copper (Cu) is a metallic element with an <strong>atomic mass of 63.55 grams per mole<\/strong>, which means that one mole of copper atoms weighs 63.55 grams. In chemistry, the <strong>mole<\/strong> is a fundamental unit that measures the amount of substance. One mole always contains <strong>Avogadro\u2019s number<\/strong> of particles, which is approximately <strong>6.022 \u00d7 10\u00b2\u00b3 atoms\/molecules<\/strong>.<\/p>\n\n\n\n<p>To determine how many grams are in a given number of moles (like in question 2), we multiply the number of moles by copper\u2019s atomic mass. This gives us the total mass in grams. Similarly, if we know the mass in grams (question 3), we divide by the atomic mass to find the number of moles.<\/p>\n\n\n\n<p>When dealing with atoms (questions 4 and 5), we need to connect moles to atoms. Since each mole contains Avogadro\u2019s number of atoms, multiplying the number of moles by 6.022\u00d710236.022 \\times 10^{23} gives the total number of atoms.<\/p>\n\n\n\n<p>In question 5, since we start with grams, we first convert to moles and then to atoms, using the same process in two steps. This method allows us to calculate the atomic-level quantity from a macroscopic mass.<\/p>\n\n\n\n<p>Understanding these conversions is vital in chemistry, especially when working with chemical reactions and compositions. It bridges the gap between the <strong>microscopic world of atoms<\/strong> and the <strong>macroscopic quantities<\/strong> we measure in laboratories. Copper, as a common element used in wiring and coins, provides a practical example to apply these calculations.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner4-25.jpeg\" alt=\"\" class=\"wp-image-219668\"\/><\/figure>\n\n\n\n<p><a href=\"https:\/\/labs.google.com\/search?source=srp\" target=\"_blank\" rel=\"noopener\"><\/a><\/p>\n\n\n\n<p><a href=\"https:\/\/www.google.co.ke\/intl\/en\/about\/products?tab=wh\" target=\"_blank\" rel=\"noopener\"><\/a><\/p>\n\n\n\n<p><a href=\"https:\/\/labs.google.com\/search?source=srp\" target=\"_blank\" rel=\"noopener\"><\/a><\/p>\n\n\n\n<p><a href=\"https:\/\/www.google.co.ke\/intl\/en\/about\/products?tab=wh\" target=\"_blank\" rel=\"noopener\"><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the atomic mass of copper, Cu? 2. How many grams are there in 36.34 moles of Cu? 3. How many moles are there in 3.7 \u00d7 105 grams of Cu? 4. How many copper atoms are there in 92.56 moles of Cu? 5. How many copper atoms are there in 0.104 grams of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219667","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219667","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219667"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219667\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219667"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219667"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219667"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}