{"id":219717,"date":"2025-05-26T15:35:12","date_gmt":"2025-05-26T15:35:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219717"},"modified":"2025-05-26T15:35:14","modified_gmt":"2025-05-26T15:35:14","slug":"the-formula-for-the-conjugate-acid-of-s2-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/26\/the-formula-for-the-conjugate-acid-of-s2-is\/","title":{"rendered":"The formula for the conjugate acid of s2- is"},"content":{"rendered":"\n<p>The formula for the conjugate acid of s2- is<\/p>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li>The formula for the conjugate base of HPO ?- is<\/li>\n<\/ol>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answers:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>The formula for the conjugate acid of S\u00b2\u207b is<\/strong>: <strong>HS\u207b<\/strong><\/li>\n\n\n\n<li><strong>The formula for the conjugate base of HPO\u2084\u00b2\u207b is<\/strong>: <strong>PO\u2084\u00b3\u207b<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>In acid-base chemistry, the concept of <strong>conjugate acids and bases<\/strong> comes from the <strong>Br\u00f8nsted-Lowry theory<\/strong>, which defines acids as <strong>proton (H\u207a) donors<\/strong> and bases as <strong>proton acceptors<\/strong>. When a base gains a proton, it becomes its <strong>conjugate acid<\/strong>. Conversely, when an acid loses a proton, it becomes its <strong>conjugate base<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Conjugate Acid of S\u00b2\u207b (Sulfide Ion)<\/strong>:<\/h4>\n\n\n\n<p>The sulfide ion (S\u00b2\u207b) is a strong <strong>Br\u00f8nsted-Lowry base<\/strong> because it can accept protons (H\u207a). When it accepts <strong>one proton<\/strong>, it forms <strong>HS\u207b (hydrosulfide ion)<\/strong>. Therefore: S2\u2212+H+\u2192HS\u2212\\text{S}^{2-} + \\text{H}^+ \\rightarrow \\text{HS}^-<\/p>\n\n\n\n<p>HS\u207b is the <strong>conjugate acid<\/strong> of S\u00b2\u207b. If HS\u207b gains another proton, it would become H\u2082S (hydrogen sulfide), a weak diprotic acid.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Conjugate Base of HPO\u2084\u00b2\u207b (Hydrogen Phosphate Ion)<\/strong>:<\/h4>\n\n\n\n<p>HPO\u2084\u00b2\u207b is a weak acid that can donate a proton. When it <strong>loses one proton<\/strong>, it forms <strong>PO\u2084\u00b3\u207b (phosphate ion)<\/strong>. This is the <strong>conjugate base<\/strong> of HPO\u2084\u00b2\u207b. The reaction is: HPO42\u2212\u2192PO43\u2212+H+\\text{HPO}_4^{2-} \\rightarrow \\text{PO}_4^{3-} + \\text{H}^+<\/p>\n\n\n\n<p>So, PO\u2084\u00b3\u207b is the species that remains after HPO\u2084\u00b2\u207b donates a hydrogen ion, making it the conjugate base.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Conjugate acid of S\u00b2\u207b<\/strong> = <strong>HS\u207b<\/strong><\/li>\n\n\n\n<li><strong>Conjugate base of HPO\u2084\u00b2\u207b<\/strong> = <strong>PO\u2084\u00b3\u207b<\/strong><\/li>\n<\/ul>\n\n\n\n<p>These relationships are crucial for understanding chemical equilibria, buffer systems, and acid-base reactions in both inorganic and biological systems.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner7-28.jpeg\" alt=\"\" class=\"wp-image-219718\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The formula for the conjugate acid of s2- is The Correct Answer and Explanation is: Answers: Explanation In acid-base chemistry, the concept of conjugate acids and bases comes from the Br\u00f8nsted-Lowry theory, which defines acids as proton (H\u207a) donors and bases as proton acceptors. When a base gains a proton, it becomes its conjugate acid. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219717","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219717","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219717"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219717\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219717"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219717"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219717"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}