{"id":219734,"date":"2025-05-26T18:05:46","date_gmt":"2025-05-26T18:05:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=219734"},"modified":"2025-05-26T18:05:48","modified_gmt":"2025-05-26T18:05:48","slug":"carbonic-acid-reacts-with-water-to-yield-bicarbonate-ions-and-hydronium-ions-h2co3-h2o-hco3%c2%af-h3o-identify-the-conjugate-acid-base-pairs","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/26\/carbonic-acid-reacts-with-water-to-yield-bicarbonate-ions-and-hydronium-ions-h2co3-h2o-hco3%c2%af-h3o-identify-the-conjugate-acid-base-pairs\/","title":{"rendered":"Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: H2CO3 + H2O = HCO3\u00af + H3O+ Identify the conjugate acid-base pairs."},"content":{"rendered":"\n
Part A Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: H2CO3 + H2O = HCO3\u00af + H3O+ Identify the conjugate acid-base pairs. Drag each item to the appropriate bin. \u2022 View Available Hint(s) Reset Help H2O HCO3 H2CO3 H3O+ Acid Conjugate base Base Conjugate acid None Acids and bases have been defined in different ways. Arrhenius defined an acid as a compound that dissolves in water to increase the concentration of H+, and a base as a compound that increases the concentration of OH. Later, Br\u00f8nsted and Lowry modified the definition: Acids are proton donors, and bases are proton acceptors. The Br\u00f8nsted-Lowry definition of acids and bases is represented generically by this reaction, where HA is an acid and B is a base: HA + B = A + BH+ An acid that has lost a proton is that acid’s conjugate base (A). A base that has accepted a proton is that base’s conjugate acid (BH+). For each acid-base reaction, there are two conjugate acid-base pairs. The word conjugate is related to the word conjugal, which means “having to do with marriage.” A wife is only a wife to her husband, and a husband is only a husband to his wife. Similarly, a conjugate acid is defined as “conjugate” only in relation to the base from which it is derived, and a conjugate base is so defined only in relation to the acid from which it is derived. Conjugate acid-base pairs are identified as pairs because they are defined only in relation to each other. Part A Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: Identify the conjugate acid-base pairs. \u2022 View Available Hint(s) Acid H2O Conjugate base H2CO3 + H2O = HCO3 + H3O+ HCO3 H2CO3 H3O+ Base Conjugate acid I Reset Help<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
Correct Categorization of Each Species<\/strong><\/h3>\n\n\n\n
we are observing a Br\u00f8nsted-Lowry acid-base reaction. According to this theory, acids are proton (H\u207a) donors<\/strong>, and bases are proton acceptors<\/strong>. When identifying conjugate acid-base pairs, we look at the species that donate and accept protons and how they transform after the reaction.<\/p>\n\n\n\n
Step-by-step breakdown:<\/strong><\/p>\n\n\n\n\n
H\u2082CO\u2083 (carbonic acid)<\/strong> donates a proton (H\u207a) to H\u2082O (water)<\/strong>. Since it donates a proton, H\u2082CO\u2083 acts as the acid<\/strong>.<\/li>\n\n\n\n
After losing a proton, H\u2082CO\u2083 becomes HCO\u2083\u207b (bicarbonate ion)<\/strong>. This species is now capable of accepting a proton in the reverse reaction, making it the conjugate base<\/strong> of H\u2082CO\u2083.<\/li>\n\n\n\n
H\u2082O<\/strong> accepts the proton donated by H\u2082CO\u2083, which classifies it as the base<\/strong> in this reaction.<\/li>\n\n\n\n
After gaining the proton, H\u2082O becomes H\u2083O\u207a (hydronium ion)<\/strong>, which can donate a proton in the reverse reaction. Therefore, it is the conjugate acid<\/strong> of H\u2082O.<\/li>\n<\/ol>\n\n\n\n
To summarize the conjugate acid-base pairs:<\/strong><\/p>\n\n\n\n
\n
H\u2082CO\u2083 \/ HCO\u2083\u207b<\/strong> \u2192 H\u2082CO\u2083 is the acid; HCO\u2083\u207b is its conjugate base.<\/li>\n\n\n\n
H\u2082O \/ H\u2083O\u207a<\/strong> \u2192 H\u2082O is the base; H\u2083O\u207a is its conjugate acid.<\/li>\n<\/ul>\n\n\n\n
This reaction illustrates the reversible nature of acid-base reactions, where the acid and base react to form their conjugates. Each acid has a corresponding conjugate base, and each base has a conjugate acid. Understanding these pairs helps in identifying how substances will behave in acid-base reactions, especially in buffer systems like carbonic acid in the blood.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
Part A Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: H2CO3 + H2O = HCO3\u00af + H3O+ Identify the conjugate acid-base pairs. Drag each item to the appropriate bin. \u2022 View Available Hint(s) Reset Help H2O HCO3 H2CO3 H3O+ Acid Conjugate base Base Conjugate acid None Acids and bases have been […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219734","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219734","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219734"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219734\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219734"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219734"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219734"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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