Correct Answer:<\/strong> In organic chemistry, reduction<\/strong> refers to a process in which a molecule gains electrons. This often translates structurally into either an increase in carbon-hydrogen (C\u2013H) bonds<\/strong> or a decrease in carbon-heteroatom bonds (C\u2013Z),<\/strong> where Z is typically a more electronegative atom such as oxygen, nitrogen, or a halogen.<\/p>\n\n\n\n When a compound is reduced, it often gains hydrogen atoms. In organic molecules, this means more hydrogen atoms become bonded to carbon<\/strong>, increasing the number of C\u2013H bonds<\/strong>. For example, the reduction of a carbonyl group (C=O) in an aldehyde or ketone to an alcohol adds hydrogen and converts the double bond to a single bond with an added hydrogen on the carbon. This is commonly seen in the reduction of aldehydes to primary alcohols or ketones to secondary alcohols using reducing agents like NaBH\u2084<\/strong> or LiAlH\u2084<\/strong>.<\/p>\n\n\n\n At the same time, reduction can also involve the removal of bonds between carbon and electronegative atoms<\/strong>. These C\u2013Z bonds are usually polar due to the difference in electronegativity, making them susceptible to reduction. For instance, the reduction of a nitro group (\u2013NO\u2082) to an amine (\u2013NH\u2082) involves breaking N\u2013O bonds. Similarly, the dehalogenation of an alkyl halide (removal of a halogen) reduces the number of C\u2013Z bonds.<\/p>\n\n\n\n Therefore, a reduction process in organic chemistry typically results in both an increase in C\u2013H bonds and a decrease in C\u2013Z bonds<\/strong>. Recognizing these changes is key to identifying whether a reaction is oxidative or reductive. That\u2019s why \u201cBoth increased number of C-H bonds and fewer C-Z bonds\u201d<\/strong> is the correct answer.<\/p>\n\n\n\n If a compound is reduced, what is the result? Fewer C-H bondsIncreased number of C-H bondsFewer C-Z bondsBoth increased number of C-H bonds and fewer C-Z bonds The Correct Answer and Explanation is: Correct Answer:Both increased number of C-H bonds and fewer C-Z bonds Explanation In organic chemistry, reduction refers to a process in which […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-219916","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219916","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=219916"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/219916\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=219916"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=219916"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=219916"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Both increased number of C-H bonds and fewer C-Z bonds<\/strong><\/p>\n\n\n\n
\n\n\n\nExplanation <\/h3>\n\n\n\n
1. Increased number of C\u2013H bonds:<\/strong><\/h4>\n\n\n\n
2. Fewer C\u2013Z bonds:<\/strong><\/h4>\n\n\n\n
Conclusion:<\/h4>\n\n\n\n
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