The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n Reaction 1:<\/strong> Reaction 2:<\/strong> Reaction 3:<\/strong> These reactions are examples of Br\u00f8nsted-Lowry acid-base theory<\/strong>, which defines acids as proton (H\u207a) donors and bases as proton acceptors.<\/p>\n\n\n\n In Reaction 1<\/strong>, the cyanide ion (CN\u207b) accepts a proton from water, forming hydrogen cyanide (HCN) and hydroxide ion (OH\u207b). Here, CN\u207b acts as a base and H\u2082O acts as an acid. The products show the conjugate acid-base pair: HCN (conjugate acid of CN\u207b) and OH\u207b (conjugate base of H\u2082O). This reaction shows that CN\u207b is a weak base.<\/p>\n\n\n\n Reaction 2<\/strong> shows nitrous acid (HNO\u2082) donating a proton to water, forming nitrite (NO\u2082\u207b) and the hydronium ion (H\u2083O\u207a). HNO\u2082 is the acid and H\u2082O is the base. The resulting species\u2014NO\u2082\u207b and H\u2083O\u207a\u2014are the conjugate base and conjugate acid, respectively. This reaction is typical of a weak acid dissolving in water.<\/p>\n\n\n\n In Reaction 3<\/strong>, ammonia (NH\u2083) accepts a proton from water, resulting in ammonium ion (NH\u2084\u207a) and hydroxide ion (OH\u207b). NH\u2083 acts as a base, and H\u2082O is the acid. NH\u2084\u207a is the conjugate acid of NH\u2083, and OH\u207b is the conjugate base of water. This demonstrates NH\u2083\u2019s property as a weak base.<\/p>\n\n\n\n Each of these reactions is an equilibrium, indicating that the acid and base are weak\u2014they don\u2019t completely dissociate or react in water. Understanding these acid-base pairs helps predict the direction of reactions and the pH of solutions, which is essential in chemistry, biology, and environmental science.<\/p>\n\n\n\n Identify the acids and bases in each of the following reactions. 1. CN- + H2O \u00c3\u00a2\u00e2\u20ac\u00a1\u00c5\u2019 HCN + OH- 2. HNO2(aq) + H2O(l) \u00c3\u00a2\u00e2\u20ac\u00a1\u00c5\u2019 NO2-(aq) + H3O+(aq) 3. NH3(aq) + H2O(l) \u00c3\u00a2\u00e2\u20ac\u00a1\u00c5\u2019 NH4+(aq) + OH-(aq)Identify the acids and bases in each of the following reactions. The Correct Answer and Explanation is: Identifying Acids and Bases […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220018","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220018","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220018"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220018\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220018"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220018"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220018"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Identifying Acids and Bases in the Reactions<\/h3>\n\n\n\n
CN\u2212+H2O\u21ccHCN+OH\u2212\\text{CN}^- + \\text{H}_2\\text{O} \\rightleftharpoons \\text{HCN} + \\text{OH}^-<\/p>\n\n\n\n\n
HNO2(aq)+H2O(l)\u21ccNO2\u2212(aq)+H3O+(aq)\\text{HNO}_2(aq) + \\text{H}_2\\text{O}(l) \\rightleftharpoons \\text{NO}_2^-(aq) + \\text{H}_3\\text{O}^+(aq)<\/p>\n\n\n\n\n
NH3(aq)+H2O(l)\u21ccNH4+(aq)+OH\u2212(aq)\\text{NH}_3(aq) + \\text{H}_2\\text{O}(l) \\rightleftharpoons \\text{NH}_4^+(aq) + \\text{OH}^-(aq)<\/p>\n\n\n\n\n
\n\n\n\nExplanation<\/h3>\n\n\n\n
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<\/figure>\n","protected":false},"excerpt":{"rendered":"