{"id":220055,"date":"2025-05-27T11:36:19","date_gmt":"2025-05-27T11:36:19","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=220055"},"modified":"2025-05-27T11:36:21","modified_gmt":"2025-05-27T11:36:21","slug":"the-molecular-formula-of-allicin-the-compound-responsible-for-the-characteristic-smell-of-garlic-is-c6h10os2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/27\/the-molecular-formula-of-allicin-the-compound-responsible-for-the-characteristic-smell-of-garlic-is-c6h10os2\/","title":{"rendered":"The molecular formula of allicin, the compound responsible for the characteristic smell of garlic, is C6H10OS2."},"content":{"rendered":"\n<p>The molecular formula of allicin, the compound responsible for the characteristic smell of garlic, is C6H10OS2.<\/p>\n\n\n\n<p>(a) What is the molar mass of allicin?<br><em>__<\/em> g\/mol<\/p>\n\n\n\n<p>(b) How many moles of allicin are present in 6.60 mg of this substance?<br><em>__<\/em> mol<\/p>\n\n\n\n<p>(c) How many molecules of allicin are in 6.60 mg of this substance?<br><em>__<\/em> allicin molecules<\/p>\n\n\n\n<p>(d) How many H atoms are present in 6.60 mg of allicin?<br><em>__<\/em> H atoms<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To solve this problem, we will go through each part step by step, using the molecular formula of allicin: <strong>C\u2086H\u2081\u2080OS\u2082<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(a) Molar Mass of Allicin<\/strong><\/h3>\n\n\n\n<p>To calculate the molar mass, sum the atomic masses of each element in the formula:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 12.01 g\/mol \u00d7 6 = 72.06 g\/mol<\/li>\n\n\n\n<li>Hydrogen (H): 1.008 g\/mol \u00d7 10 = 10.08 g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 16.00 g\/mol \u00d7 1 = 16.00 g\/mol<\/li>\n\n\n\n<li>Sulfur (S): 32.07 g\/mol \u00d7 2 = 64.14 g\/mol<\/li>\n<\/ul>\n\n\n\n<p><strong>Total molar mass = 72.06 + 10.08 + 16.00 + 64.14 = 162.28 g\/mol<\/strong><\/p>\n\n\n\n<p>\u2705 <strong>Answer (a): 162.28 g\/mol<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(b) Moles of Allicin in 6.60 mg<\/strong><\/h3>\n\n\n\n<p>Convert mg to grams:<br>6.60 mg = 0.00660 g<\/p>\n\n\n\n<p>Use the formula:<br><strong>moles = mass \/ molar mass<\/strong> moles=0.00660&nbsp;g162.28&nbsp;g\/mol=4.07\u00d710\u22125&nbsp;mol\\text{moles} = \\frac{0.00660\\ \\text{g}}{162.28\\ \\text{g\/mol}} = 4.07 \\times 10^{-5}\\ \\text{mol}<\/p>\n\n\n\n<p>\u2705 <strong>Answer (b): 4.07 \u00d7 10\u207b\u2075 mol<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(c) Molecules of Allicin in 6.60 mg<\/strong><\/h3>\n\n\n\n<p>Use <strong>Avogadro\u2019s number<\/strong>:<br>1 mol = 6.022 \u00d7 10\u00b2\u00b3 molecules molecules=4.07\u00d710\u22125&nbsp;mol\u00d76.022\u00d71023&nbsp;molecules\/mol=2.45\u00d71019&nbsp;molecules\\text{molecules} = 4.07 \\times 10^{-5}\\ \\text{mol} \\times 6.022 \\times 10^{23}\\ \\text{molecules\/mol} = 2.45 \\times 10^{19}\\ \\text{molecules}<\/p>\n\n\n\n<p>\u2705 <strong>Answer (c): 2.45 \u00d7 10\u00b9\u2079 allicin molecules<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(d) Hydrogen Atoms in 6.60 mg of Allicin<\/strong><\/h3>\n\n\n\n<p>Each <strong>molecule of allicin<\/strong> contains <strong>10 hydrogen atoms<\/strong>. H&nbsp;atoms=2.45\u00d71019&nbsp;molecules\u00d710=2.45\u00d71020&nbsp;H&nbsp;atoms\\text{H atoms} = 2.45 \\times 10^{19}\\ \\text{molecules} \\times 10 = 2.45 \\times 10^{20}\\ \\text{H atoms}<\/p>\n\n\n\n<p>\u2705 <strong>Answer (d): 2.45 \u00d7 10\u00b2\u2070 H atoms<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Summary &amp; Explanation<\/strong><\/h3>\n\n\n\n<p>Allicin (C\u2086H\u2081\u2080OS\u2082) is an organosulfur compound that gives garlic its characteristic aroma. Understanding the molecular composition allows chemists to calculate various quantitative properties, such as mass, moles, and atomic content.<\/p>\n\n\n\n<p>First, we calculate the molar mass by summing the atomic masses of the atoms in the molecular formula: carbon (C), hydrogen (H), oxygen (O), and sulfur (S). Each element\u2019s contribution is multiplied by the number of atoms in the molecule. The result is a molar mass of <strong>162.28 g\/mol<\/strong>, which tells us the mass of one mole of allicin molecules.<\/p>\n\n\n\n<p>Next, to find the number of moles in <strong>6.60 mg (0.00660 g)<\/strong>, we divide the mass by the molar mass. This gives <strong>4.07 \u00d7 10\u207b\u2075 mol<\/strong>, a small amount, typical for laboratory-scale samples.<\/p>\n\n\n\n<p>To determine how many <strong>individual molecules<\/strong> this amount represents, we multiply the number of moles by <strong>Avogadro\u2019s number<\/strong> (6.022 \u00d7 10\u00b2\u00b3), the number of particles in one mole. The result, <strong>2.45 \u00d7 10\u00b9\u2079 molecules<\/strong>, shows the enormous number of molecules even in tiny masses.<\/p>\n\n\n\n<p>Finally, each allicin molecule contains <strong>10 hydrogen atoms<\/strong>, so the total number of hydrogen atoms is the number of molecules multiplied by 10, giving <strong>2.45 \u00d7 10\u00b2\u2070 H atoms<\/strong>.<\/p>\n\n\n\n<p>These calculations are essential in chemistry and biochemistry for understanding reactivity, dosage, and molecular interactions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner8-37.jpeg\" alt=\"\" class=\"wp-image-220056\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The molecular formula of allicin, the compound responsible for the characteristic smell of garlic, is C6H10OS2. (a) What is the molar mass of allicin?__ g\/mol (b) How many moles of allicin are present in 6.60 mg of this substance?__ mol (c) How many molecules of allicin are in 6.60 mg of this substance?__ allicin molecules [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220055","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220055","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220055"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220055\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220055"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220055"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220055"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}