{"id":220102,"date":"2025-05-27T13:40:01","date_gmt":"2025-05-27T13:40:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=220102"},"modified":"2025-05-27T13:40:04","modified_gmt":"2025-05-27T13:40:04","slug":"give-the-ground-state-electron-configuration-for-se","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/27\/give-the-ground-state-electron-configuration-for-se\/","title":{"rendered":"Give the ground state electron configuration for Se."},"content":{"rendered":"\n<p>Give the ground state electron configuration for Se.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/image-460.png\" alt=\"\" class=\"wp-image-220103\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer to question 9, which asks for the ground state electron configuration of selenium (Se), is:<\/p>\n\n\n\n<p><strong>C) [Ar]4s\u00b23d\u00b9\u20704p\u2074<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>Selenium (Se) is a non-metal element in Group 16 and Period 4 of the periodic table, with an atomic number of <strong>34<\/strong>. This means selenium has <strong>34 electrons<\/strong> in its neutral ground state.<\/p>\n\n\n\n<p>To write its electron configuration, we follow the <strong>Aufbau principle<\/strong>, which states that electrons fill orbitals in order of increasing energy levels. We also follow <strong>Hund\u2019s rule<\/strong> and the <strong>Pauli exclusion principle<\/strong> to properly fill and pair electrons in orbitals.<\/p>\n\n\n\n<p>Here\u2019s the step-by-step electron filling until we reach 34 electrons:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>1s\u00b2<\/strong> \u2192 2 electrons<\/li>\n\n\n\n<li><strong>2s\u00b2<\/strong> \u2192 2 electrons<\/li>\n\n\n\n<li><strong>2p\u2076<\/strong> \u2192 6 electrons<\/li>\n\n\n\n<li><strong>3s\u00b2<\/strong> \u2192 2 electrons<\/li>\n\n\n\n<li><strong>3p\u2076<\/strong> \u2192 6 electrons<\/li>\n\n\n\n<li><strong>4s\u00b2<\/strong> \u2192 2 electrons<\/li>\n\n\n\n<li><strong>3d\u00b9\u2070<\/strong> \u2192 10 electrons<\/li>\n\n\n\n<li><strong>4p\u2074<\/strong> \u2192 4 electrons<\/li>\n<\/ol>\n\n\n\n<p>Total:<br>2 + 2 + 6 + 2 + 6 + 2 + 10 + 4 = <strong>34 electrons<\/strong><\/p>\n\n\n\n<p>To simplify, we use the noble gas <strong>argon (Ar)<\/strong> to represent the electron configuration of the first 18 electrons:<\/p>\n\n\n\n<p><strong>[Ar] = 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076<\/strong><\/p>\n\n\n\n<p>So the full configuration becomes:<\/p>\n\n\n\n<p><strong>[Ar] 4s\u00b2 3d\u00b9\u2070 4p\u2074<\/strong><\/p>\n\n\n\n<p>This matches <strong>option C<\/strong>.<\/p>\n\n\n\n<p><strong>Why the others are incorrect:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A)<\/strong> ends too early (missing electrons)<\/li>\n\n\n\n<li><strong>B)<\/strong> misplaces 3d and 4s order (4s fills before 3d)<\/li>\n\n\n\n<li><strong>D)<\/strong> has only 2 electrons in 4p instead of 4, indicating atomic number 32 (which is Ge, not Se)<\/li>\n\n\n\n<li><strong>E)<\/strong> is a repeat of D<\/li>\n<\/ul>\n\n\n\n<p>Thus, <strong>C is the correct configuration for Se<\/strong>, accurately reflecting the energy filling order and total number o<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner9-36.jpeg\" alt=\"\" class=\"wp-image-220104\"\/><\/figure>\n\n\n\n<p>f electrons.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Give the ground state electron configuration for Se. The Correct Answer and Explanation is: The correct answer to question 9, which asks for the ground state electron configuration of selenium (Se), is: C) [Ar]4s\u00b23d\u00b9\u20704p\u2074 Explanation Selenium (Se) is a non-metal element in Group 16 and Period 4 of the periodic table, with an atomic number [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220102","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220102","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220102"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220102\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220102"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220102"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220102"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}