{"id":220261,"date":"2025-05-28T05:05:04","date_gmt":"2025-05-28T05:05:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=220261"},"modified":"2025-05-28T05:05:07","modified_gmt":"2025-05-28T05:05:07","slug":"give-the-number-of-protons-the-number-of-neutrons-and-the-neutron-to-proton-ratio-for-each-of-the-isotope-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/28\/give-the-number-of-protons-the-number-of-neutrons-and-the-neutron-to-proton-ratio-for-each-of-the-isotope-below\/","title":{"rendered":"Give the number of protons, the number of neutrons, and the neutron-to-proton ratio for each of the isotope below."},"content":{"rendered":"\n<p>Give the number of protons, the number of neutrons, and the neutron-to-proton ratio for each of the isotope below. a. iron-57 b. 185W c. potassium-39 d. 131Xe 2. Write the nuclide notation for atoms with the following characteristics: a. 25 protons, 20 neutrons, 24 electrons b. 45 protons, 24 neutrons, 43 electrons c. 53 protons, 89 neutrons, 54 electrons d. 97 protons,<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">T he Correct Answer and Explanation is :<\/mark><\/strong><\/p>\n\n\n\n<p>Sure! Here&#8217;s a complete and clear answer for both parts of your question, followed by a 300-word explanation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. For each isotope, give the number of protons, neutrons, and neutron-to-proton ratio:<\/strong><\/h3>\n\n\n\n<p><strong>a. Iron-57 (\u2075\u2077Fe):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Protons:<\/strong> 26 (Iron\u2019s atomic number)<\/li>\n\n\n\n<li><strong>Neutrons:<\/strong> 57 \u2013 26 = <strong>31<\/strong><\/li>\n\n\n\n<li><strong>Neutron-to-proton ratio:<\/strong> 31 \/ 26 \u2248 <strong>1.19<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>b. Tungsten-185 (\u00b9\u2078\u2075W):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Protons:<\/strong> 74 (Tungsten\u2019s atomic number)<\/li>\n\n\n\n<li><strong>Neutrons:<\/strong> 185 \u2013 74 = <strong>111<\/strong><\/li>\n\n\n\n<li><strong>Neutron-to-proton ratio:<\/strong> 111 \/ 74 \u2248 <strong>1.50<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>c. Potassium-39 (\u00b3\u2079K):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Protons:<\/strong> 19 (Potassium\u2019s atomic number)<\/li>\n\n\n\n<li><strong>Neutrons:<\/strong> 39 \u2013 19 = <strong>20<\/strong><\/li>\n\n\n\n<li><strong>Neutron-to-proton ratio:<\/strong> 20 \/ 19 \u2248 <strong>1.05<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>d. Xenon-131 (\u00b9\u00b3\u00b9Xe):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Protons:<\/strong> 54 (Xenon\u2019s atomic number)<\/li>\n\n\n\n<li><strong>Neutrons:<\/strong> 131 \u2013 54 = <strong>77<\/strong><\/li>\n\n\n\n<li><strong>Neutron-to-proton ratio:<\/strong> 77 \/ 54 \u2248 <strong>1.43<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Write the nuclide notation:<\/strong><\/h3>\n\n\n\n<p>Nuclide notation: ZASymbolcharge_{Z}^{A}\\text{Symbol}^{\\text{charge}}<\/p>\n\n\n\n<p><strong>a. 25 protons, 20 neutrons, 24 electrons<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Element:<\/strong> Manganese (Mn)<\/li>\n\n\n\n<li><strong>Mass number (A):<\/strong> 25 + 20 = 45<\/li>\n\n\n\n<li><strong>Charge:<\/strong> 25 \u2013 24 = +1<\/li>\n\n\n\n<li><strong>Notation:<\/strong> 2545Mn+1_{25}^{45}\\text{Mn}^{+1}<\/li>\n<\/ul>\n\n\n\n<p><strong>b. 45 protons, 24 neutrons, 43 electrons<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Element:<\/strong> Rhodium (Rh)<\/li>\n\n\n\n<li><strong>Mass number:<\/strong> 45 + 24 = 69<\/li>\n\n\n\n<li><strong>Charge:<\/strong> 45 \u2013 43 = +2<\/li>\n\n\n\n<li><strong>Notation:<\/strong> 4569Rh+2_{45}^{69}\\text{Rh}^{+2}<\/li>\n<\/ul>\n\n\n\n<p><strong>c. 53 protons, 89 neutrons, 54 electrons<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Element:<\/strong> Iodine (I)<\/li>\n\n\n\n<li><strong>Mass number:<\/strong> 53 + 89 = 142<\/li>\n\n\n\n<li><strong>Charge:<\/strong> 53 \u2013 54 = \u20131<\/li>\n\n\n\n<li><strong>Notation:<\/strong> 53142I\u22121_{53}^{142}\\text{I}^{-1}<\/li>\n<\/ul>\n\n\n\n<p><strong>d. 97 protons (mass not given)<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Element:<\/strong> Berkelium (Bk)<\/li>\n\n\n\n<li><strong>Common isotope mass number:<\/strong> Assume Bk-247<\/li>\n\n\n\n<li><strong>Notation (neutral atom):<\/strong> 97247Bk_{97}^{247}\\text{Bk}<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>Atoms consist of three subatomic particles: protons, neutrons, and electrons. The number of protons determines the atomic number and the identity of the element. Neutrons contribute to the atomic mass but not the charge. Electrons are negatively charged and balance the protons in neutral atoms.<\/p>\n\n\n\n<p>In isotopes, the number of neutrons varies while the number of protons remains the same. This leads to different mass numbers (A = protons + neutrons). The neutron-to-proton ratio is important in determining the stability of a nucleus. Lighter elements (like potassium) tend to have ratios close to 1, while heavier elements (like tungsten and xenon) require more neutrons to remain stable, resulting in ratios greater than 1.<\/p>\n\n\n\n<p>Nuclide notation expresses atomic information compactly. It includes the element\u2019s symbol, atomic number (Z), mass number (A), and charge. For ions, the charge is calculated by subtracting electrons from protons. If electrons are fewer, the atom is positively charged (a cation); if more, it&#8217;s negatively charged (an anion).<\/p>\n\n\n\n<p>For example, manganese with 25 protons and 24 electrons has a +1 charge. Rhodium with 45 protons and only 43 electrons is +2. In contrast, iodine with an extra electron becomes a -1 anion. If no mass number is given, a common isotope is assumed, as with berkelium (Bk), whose common isotope has mass 247.<\/p>\n\n\n\n<p>Understanding isotopes and ion notation is critical in nuclear chemistry, radioactivity, and analytical techniques like mass spectrometry, as they help identify atoms, determine their behavior, and track chemical reactions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner5-69.jpeg\" alt=\"\" class=\"wp-image-220262\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Give the number of protons, the number of neutrons, and the neutron-to-proton ratio for each of the isotope below. a. iron-57 b. 185W c. potassium-39 d. 131Xe 2. Write the nuclide notation for atoms with the following characteristics: a. 25 protons, 20 neutrons, 24 electrons b. 45 protons, 24 neutrons, 43 electrons c. 53 protons, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220261","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220261","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220261"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220261\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220261"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220261"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220261"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}