{"id":220813,"date":"2025-05-28T19:57:41","date_gmt":"2025-05-28T19:57:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=220813"},"modified":"2025-05-28T19:57:43","modified_gmt":"2025-05-28T19:57:43","slug":"which-of-the-following-compounds-will-be-most-soluble-in-pentane-c5h12","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/28\/which-of-the-following-compounds-will-be-most-soluble-in-pentane-c5h12\/","title":{"rendered":"Which of the following compounds will be most soluble in pentane (C5H12)"},"content":{"rendered":"\n<p>Which of the following compounds will be most soluble in pentane (C5H12)? Explain your choice. A) pentanol (CH3CH2CH2CH2CH2OH) B) benzene (C6H6) C) acetic acid (CH3CO2H) D) ethyl methyl ketone (CH3CH2COCH3)<br>Which of the following compounds will be most soluble in pentane (C5H12)? Explain your choice.<\/p>\n\n\n\n<p>A) pentanol (CH3CH2CH2CH2CH2OH)<\/p>\n\n\n\n<p>B) benzene (C6H6)<\/p>\n\n\n\n<p>C) acetic acid (CH3CO2H)<\/p>\n\n\n\n<p>D) ethyl methyl ketone (CH3CH2COCH3)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The compound <strong>most soluble in pentane (C\u2085H\u2081\u2082)<\/strong> is:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B) Benzene (C\u2086H\u2086)<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>Solubility depends on the principle of <strong>&#8220;like dissolves like&#8221;<\/strong>\u2014substances with similar intermolecular forces are more likely to be miscible or soluble in each other.<\/p>\n\n\n\n<p>Pentane (C\u2085H\u2081\u2082) is a <strong>nonpolar hydrocarbon<\/strong> with only weak <strong>London dispersion forces<\/strong>. Therefore, compounds that are also nonpolar or have minimal polarity will dissolve better in pentane. Let\u2019s analyze each option:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>A) Pentanol (CH\u2083CH\u2082CH\u2082CH\u2082CH\u2082OH):<\/strong><br>Although pentanol has a long nonpolar hydrocarbon chain (similar to pentane), it contains a <strong>polar hydroxyl group (\u2013OH)<\/strong>, which forms hydrogen bonds with water. This makes pentanol <strong>partially polar<\/strong>, so while it has some solubility in pentane due to its nonpolar chain, the \u2013OH group reduces its compatibility with nonpolar solvents like pentane. Solubility is moderate, but not the highest among the options.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>B) Benzene (C\u2086H\u2086):<\/strong><br>Benzene is a <strong>nonpolar aromatic hydrocarbon<\/strong> with <strong>only London dispersion forces<\/strong>. Its molecular structure and lack of polarity make it highly compatible with other nonpolar solvents like pentane. Therefore, it is <strong>very soluble in pentane<\/strong> due to the similarity in intermolecular forces.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>C) Acetic acid (CH\u2083CO\u2082H):<\/strong><br>Acetic acid is <strong>highly polar<\/strong> and capable of <strong>hydrogen bonding<\/strong> due to its carboxylic acid group. It is much more soluble in <strong>polar solvents like water<\/strong> than in nonpolar solvents like pentane. Thus, its solubility in pentane is very low.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>D) Ethyl methyl ketone (CH\u2083CH\u2082COCH\u2083):<\/strong><br>This compound (also called butanone) contains a <strong>polar carbonyl group (C=O)<\/strong>, making it <strong>moderately polar<\/strong>. Although it may have limited solubility in pentane due to its hydrocarbon chain, its polarity is not well-matched with pentane\u2019s nonpolarity.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<p><strong>Benzene<\/strong> is the most soluble in <strong>pentane<\/strong> because both are <strong>nonpolar hydrocarbons<\/strong>, and their intermolecular forces (London dispersion) are similar.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner5-95.jpeg\" alt=\"\" class=\"wp-image-220814\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which of the following compounds will be most soluble in pentane (C5H12)? Explain your choice. A) pentanol (CH3CH2CH2CH2CH2OH) B) benzene (C6H6) C) acetic acid (CH3CO2H) D) ethyl methyl ketone (CH3CH2COCH3)Which of the following compounds will be most soluble in pentane (C5H12)? Explain your choice. A) pentanol (CH3CH2CH2CH2CH2OH) B) benzene (C6H6) C) acetic acid (CH3CO2H) D) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220813","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220813","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220813"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220813\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220813"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220813"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220813"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}