{"id":220829,"date":"2025-05-28T20:12:49","date_gmt":"2025-05-28T20:12:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=220829"},"modified":"2025-05-28T20:12:52","modified_gmt":"2025-05-28T20:12:52","slug":"what-is-the-difference-between-amphoteric-and-amphiprotic-substances","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/28\/what-is-the-difference-between-amphoteric-and-amphiprotic-substances\/","title":{"rendered":"What is the difference between amphoteric and amphiprotic substances"},"content":{"rendered":"\n<p>What is the difference between amphoteric and amphiprotic substances? O Both can act as both acids and bases according to the Bronsted-Lowry definition of acids and bases, but for a substance to be amphiprotic it must be able to donate multiple protons. Both can act as both acids and bases according to the Bronsted-Lowry definition of acids and bases, but for a substance to be amphoteric it must be able to both accept and donate protons. O Both can act as both acids and bases according to the Bronsted-Lowry definition of acids and bases, but for a substance to be amphiprotic it must be able to both accept and donate protons. There is no difference. A potentiometric acid-base titration produced the following result. What can you say about the experimental conditions? pH 14 13 12 11 10 9 8 7 6 5 4 3 2 1 ONA O 0 25 5 75 10 12.5 15 17.5 20 225 25 27.5 30 Volume Added (mL) O Strong base was added from the burette to a flask containing strong acid O Strong acid was added from the burette to a flask containing weak base O Weak base was added from the burette to a flask containing strong acid O Weak acid was added from the burette to a flask containing weak base Which of the following acids could be used to make a buffer of pH 7.0 by adding to the acid a molar excess of its conjugate base in the form of a salt? O hydrogen citrate (pK, = 6.40) and carbonic acid (pk, = 6.37) O hydrogen sulfite (pkg = 7.19) and dihydrogen phosphate (pk = 72) hydrogen citrate (pka = 6.40) and hydrogen sulphite (pk, = 719) ammonium (pk. = 9.25) and pyridinium (pka = 5.25) To make up a buffer of pH 7 from equimolar solutions of sodium dihydrogen phosphate (NaH,PO, PK, of H,PO4 = 7.2) and sodium hydrogen phosphate (Na2HPO4, PK, of HPO42- = 12.38). A larger volume of sodium hydrogen phosphate solution would be required Equal volumes of each solution would be required A larger volume of sodium dihydrogen phosphate solution would be required It&#8217;s impossible to say what relative volumes of each solution would be required based on the information supplied Which of the following is a valid conjugate acid\/base pair? OH3071 H2O\/H20 O HO\/H20<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the correct answers followed by a detailed 300-word explanation:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answers<\/strong>:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Amphoteric vs. Amphiprotic:<\/strong>\n<ul class=\"wp-block-list\">\n<li>\u2705 <strong>Both can act as both acids and bases according to the Br\u00f8nsted\u2013Lowry definition of acids and bases, but for a substance to be amphiprotic it must be able to both accept and donate protons.<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Titration Analysis:<\/strong>\n<ul class=\"wp-block-list\">\n<li>\u2705 <strong>Strong base was added from the burette to a flask containing strong acid.<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Buffer at pH 7.0:<\/strong>\n<ul class=\"wp-block-list\">\n<li>\u2705 <strong>Hydrogen sulfite (pKa = 7.19) and dihydrogen phosphate (pKa = 7.2).<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Buffer from phosphate salts (pH 7):<\/strong>\n<ul class=\"wp-block-list\">\n<li>\u2705 <strong>A larger volume of sodium dihydrogen phosphate solution would be required.<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Valid conjugate acid\/base pair:<\/strong>\n<ul class=\"wp-block-list\">\n<li>\u2705 <strong>H\u2082O\/OH\u207b<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p><strong>Amphoteric vs. Amphiprotic:<\/strong><br>An <strong>amphoteric<\/strong> substance can act as either an acid or a base but is not necessarily limited to the Br\u00f8nsted\u2013Lowry definition (e.g., ZnO can act as both an acid and a base in Lewis theory). An <strong>amphiprotic<\/strong> substance specifically donates and accepts protons (H\u207a) under the Br\u00f8nsted\u2013Lowry framework. Therefore, <strong>all amphiprotic substances are amphoteric<\/strong>, but not all amphoteric substances are amphiprotic.<\/p>\n\n\n\n<p><strong>Titration Curve Analysis:<\/strong><br>The titration curve shows a rapid pH rise from very low (~2) to very high (~12), centered around pH 7. This sharp equivalence point indicates a <strong>strong acid reacting with a strong base<\/strong>. Since the base is being added (increasing pH), the <strong>strong base is in the burette<\/strong>, and <strong>strong acid is in the flask<\/strong>.<\/p>\n\n\n\n<p><strong>Buffer for pH 7.0:<\/strong><br>Buffers are most effective when the <strong>pKa is close to the desired pH<\/strong>. Both <strong>hydrogen sulfite (pKa 7.19)<\/strong> and <strong>dihydrogen phosphate (pKa 7.2)<\/strong> are near pH 7, making them suitable. Others are too far in pKa.<\/p>\n\n\n\n<p><strong>Buffer with Phosphates:<\/strong><br>For pH 7, which is lower than the pKa of HPO\u2084\u00b2\u207b (12.38), we need <strong>more acid form (NaH\u2082PO\u2084)<\/strong> than base form to maintain the buffer at pH 7. So, <strong>a larger volume of NaH\u2082PO\u2084 is required<\/strong>.<\/p>\n\n\n\n<p><strong>Valid Conjugate Pair:<\/strong><br><strong>H\u2082O\/OH\u207b<\/strong> is a valid conjugate acid\/base pair: water can donate a proton to become OH\u207b (base). Pairs like \u201cOH3071\u201d or \u201cH\u2082O\/H\u2082O\u201d are invalid or nonsensical.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner7-76.jpeg\" alt=\"\" class=\"wp-image-220830\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the difference between amphoteric and amphiprotic substances? O Both can act as both acids and bases according to the Bronsted-Lowry definition of acids and bases, but for a substance to be amphiprotic it must be able to donate multiple protons. Both can act as both acids and bases according to the Bronsted-Lowry definition [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220829","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220829","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220829"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220829\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220829"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220829"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220829"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}