{"id":220837,"date":"2025-05-28T20:18:22","date_gmt":"2025-05-28T20:18:22","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=220837"},"modified":"2025-05-28T20:18:24","modified_gmt":"2025-05-28T20:18:24","slug":"what-kind-of-reaction-is-show-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/28\/what-kind-of-reaction-is-show-below\/","title":{"rendered":"What kind of reaction is show below"},"content":{"rendered":"\n<p>What kind of reaction is show below (between hydrogen peroxide and magnesium sulfite). a. H2O2(aq) + MgSO3(aq) \u00c3\u201a\u00c2\u00bb MGSO4(aq) + H20 Precipitation gas formation acid-base neutralization redox . Write the total ionic equation for the reaction shown in Question a. Answer: Now convert the total ionic equation in Question b into its net ionic equation.<\/p>\n\n\n\n<p><strong>Solve the problem a, b &amp; C by showing steps properly.<\/strong><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let\u2019s go through this step by step for the reaction between <strong>hydrogen peroxide (H\u2082O\u2082)<\/strong> and <strong>magnesium sulfite (MgSO\u2083)<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Problem (a): Type of Reaction<\/strong><\/h3>\n\n\n\n<p><strong>Given Reaction:<\/strong> H2O2(aq)+MgSO3(aq)\u2192MgSO4(aq)+H2O(l)\\text{H}_2\\text{O}_2(aq) + \\text{MgSO}_3(aq) \\rightarrow \\text{MgSO}_4(aq) + \\text{H}_2\\text{O}(l)<\/p>\n\n\n\n<p>This is a <strong>redox reaction<\/strong>.<br>Here\u2019s why:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Hydrogen peroxide (H\u2082O\u2082)<\/strong> is a known oxidizing and reducing agent.<\/li>\n\n\n\n<li><strong>Sulfite ion (SO\u2083\u00b2\u207b)<\/strong> is oxidized to <strong>sulfate ion (SO\u2084\u00b2\u207b)<\/strong>.<\/li>\n\n\n\n<li><strong>Hydrogen peroxide<\/strong> is reduced, breaking down into <strong>water (H\u2082O)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>So, <strong>correct answer: Redox<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Problem (b): Total Ionic Equation<\/strong><\/h3>\n\n\n\n<p>Start by writing all soluble compounds as dissociated ions:<\/p>\n\n\n\n<p><strong>Reactants:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H\u2082O\u2082 is a weak acid-like molecule; stays mostly molecular in solution.<\/li>\n\n\n\n<li>MgSO\u2083 dissociates: \u2192 Mg\u00b2\u207a (aq) + SO\u2083\u00b2\u207b (aq)<\/li>\n<\/ul>\n\n\n\n<p><strong>Products:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>MgSO\u2084 is soluble: \u2192 Mg\u00b2\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n\n\n\n<li>H\u2082O stays as liquid.<\/li>\n<\/ul>\n\n\n\n<p><strong>Total Ionic Equation:<\/strong> H2O2(aq)+Mg2+(aq)+SO32\u2212(aq)\u2192Mg2+(aq)+SO42\u2212(aq)+H2O(l)\\text{H}_2\\text{O}_2(aq) + \\text{Mg}^{2+}(aq) + \\text{SO}_3^{2-}(aq) \\rightarrow \\text{Mg}^{2+}(aq) + \\text{SO}_4^{2-}(aq) + \\text{H}_2\\text{O}(l)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Problem (c): Net Ionic Equation<\/strong><\/h3>\n\n\n\n<p>Cancel out the spectator ions. Mg\u00b2\u207a appears on both sides.<\/p>\n\n\n\n<p><strong>Net Ionic Equation:<\/strong> H2O2(aq)+SO32\u2212(aq)\u2192SO42\u2212(aq)+H2O(l)\\text{H}_2\\text{O}_2(aq) + \\text{SO}_3^{2-}(aq) \\rightarrow \\text{SO}_4^{2-}(aq) + \\text{H}_2\\text{O}(l)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>This reaction between hydrogen peroxide and magnesium sulfite is a redox reaction. In redox (oxidation-reduction) reactions, one substance loses electrons (is oxidized) and another gains electrons (is reduced). Here, the sulfite ion (SO\u2083\u00b2\u207b) is <strong>oxidized<\/strong> to sulfate (SO\u2084\u00b2\u207b), meaning it gains oxygen or increases its oxidation state. Simultaneously, hydrogen peroxide (H\u2082O\u2082) is <strong>reduced<\/strong>, breaking down into water, which is a lower oxidation state for oxygen.<\/p>\n\n\n\n<p>Magnesium ions (Mg\u00b2\u207a) from magnesium sulfite and magnesium sulfate do not participate in the redox process; they are <strong>spectator ions<\/strong>. Thus, they cancel out in the net ionic equation.<\/p>\n\n\n\n<p>Hydrogen peroxide acts as a key oxidizing agent in many redox reactions because it contains an O\u2013O bond that readily breaks, allowing oxygen atoms to react. When hydrogen peroxide reacts with the sulfite ion, oxygen is transferred to the sulfite to convert it into sulfate, and H\u2082O\u2082 itself turns into H\u2082O.<\/p>\n\n\n\n<p>The full balanced molecular reaction: H2O2(aq)+MgSO3(aq)\u2192MgSO4(aq)+H2O(l)\\text{H}_2\\text{O}_2(aq) + \\text{MgSO}_3(aq) \\rightarrow \\text{MgSO}_4(aq) + \\text{H}_2\\text{O}(l)<\/p>\n\n\n\n<p>Total ionic equation: H2O2(aq)+Mg2+(aq)+SO32\u2212(aq)\u2192Mg2+(aq)+SO42\u2212(aq)+H2O(l)\\text{H}_2\\text{O}_2(aq) + \\text{Mg}^{2+}(aq) + \\text{SO}_3^{2-}(aq) \\rightarrow \\text{Mg}^{2+}(aq) + \\text{SO}_4^{2-}(aq) + \\text{H}_2\\text{O}(l)<\/p>\n\n\n\n<p>Net ionic equation: H2O2(aq)+SO32\u2212(aq)\u2192SO42\u2212(aq)+H2O(l)\\text{H}_2\\text{O}_2(aq) + \\text{SO}_3^{2-}(aq) \\rightarrow \\text{SO}_4^{2-}(aq) + \\text{H}_2\\text{O}(l)<\/p>\n\n\n\n<p>This illustrates the role of redox chemistry in transforming compounds and is commonly seen in environmental and biological processes, including disinfection and metabolism.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner9-57.jpeg\" alt=\"\" class=\"wp-image-220838\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What kind of reaction is show below (between hydrogen peroxide and magnesium sulfite). a. H2O2(aq) + MgSO3(aq) \u00c3\u201a\u00c2\u00bb MGSO4(aq) + H20 Precipitation gas formation acid-base neutralization redox . Write the total ionic equation for the reaction shown in Question a. Answer: Now convert the total ionic equation in Question b into its net ionic equation. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-220837","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220837","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=220837"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/220837\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=220837"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=220837"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=220837"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}