{"id":221122,"date":"2025-05-29T07:47:20","date_gmt":"2025-05-29T07:47:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221122"},"modified":"2025-05-29T08:41:28","modified_gmt":"2025-05-29T08:41:28","slug":"which-is-the-correct-electron-configuration-for-sb-2-in-its-ground-state","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/29\/which-is-the-correct-electron-configuration-for-sb-2-in-its-ground-state\/","title":{"rendered":"Which is the correct electron configuration for Sb 2+ in its ground state"},"content":{"rendered":"\n<p>Which is the correct electron configuration for Sb 2+ in its ground state? Key Concept: Aufbau principle. Electron configuration for ions is determined the same way as with atoms. Count up the total number of electrons in the atom and start filling orbitals from low energy to higher energy.<br>A 1s22s22p63s23p64s23d64p64d105p4<br>B 1s22s22p63s23p64s23d104p45s24d105p2<br>C 1s22s22p63s23p64s23d104p65s24d105p1<br>D 1s22s22p53s23p64s23d104p64d105p1<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is: <strong>C<\/strong><br><strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 4s\u00b2 3d\u00b9\u2070 4p\u2076 5s\u00b2 4d\u00b9\u2070 5p\u00b9<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To determine the <strong>ground-state electron configuration<\/strong> of <strong>Sb\u00b2\u207a (antimony ion with a +2 charge)<\/strong>, we need to understand the <strong>Aufbau principle<\/strong>, which states that electrons fill orbitals from <strong>lowest to highest energy<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Determine atomic number and electron configuration of neutral Sb<\/h4>\n\n\n\n<p>Antimony (Sb) has an atomic number of <strong>51<\/strong>, meaning a neutral Sb atom has <strong>51 electrons<\/strong>. The ground-state electron configuration of neutral Sb is:<\/p>\n\n\n\n<p><strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 4s\u00b2 3d\u00b9\u2070 4p\u2076 5s\u00b2 4d\u00b9\u2070 5p\u00b3<\/strong><br>(Total: 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 3 = 51 electrons)<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Remove electrons to get Sb\u00b2\u207a<\/h4>\n\n\n\n<p>When forming a <strong>2+ cation<\/strong>, <strong>two electrons are removed<\/strong>, and they are removed from the <strong>outermost orbitals<\/strong> (highest principal quantum number, <em>n<\/em>), following the Aufbau principle in reverse.<\/p>\n\n\n\n<p>The outermost electrons are in the <strong>5p<\/strong> and <strong>5s<\/strong> orbitals (n = 5). Since <strong>5p<\/strong> has 3 electrons and <strong>5s<\/strong> has 2 electrons, we remove <strong>two electrons from the 5p orbital<\/strong> (as p-electrons are higher in energy than s-electrons in the same shell).<\/p>\n\n\n\n<p>So, removing 2 electrons from <strong>5p\u00b3<\/strong> results in <strong>5p\u00b9<\/strong>, and the configuration becomes:<\/p>\n\n\n\n<p><strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 4s\u00b2 3d\u00b9\u2070 4p\u2076 5s\u00b2 4d\u00b9\u2070 5p\u00b9<\/strong><\/p>\n\n\n\n<p>This corresponds to <strong>Option C<\/strong>, which is the correct configuration for <strong>Sb\u00b2\u207a<\/strong> in its ground state.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Why Other Options Are Incorrect:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Option A<\/strong>: Incorrect orbital filling and incorrect number of electrons.<\/li>\n\n\n\n<li><strong>Option B<\/strong>: Misplaced electron configuration; 3d\u2076 instead of 3d\u00b9\u2070.<\/li>\n\n\n\n<li><strong>Option D<\/strong>: Contains errors in the 2p orbital and other inconsistencies.<\/li>\n<\/ul>\n\n\n\n<p>Thus, based on the Aufbau principle and proper electron removal for cations, <strong>Option C is correct<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner7-91.jpeg\" alt=\"\" class=\"wp-image-221123\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which is the correct electron configuration for Sb 2+ in its ground state? Key Concept: Aufbau principle. Electron configuration for ions is determined the same way as with atoms. Count up the total number of electrons in the atom and start filling orbitals from low energy to higher energy.A 1s22s22p63s23p64s23d64p64d105p4B 1s22s22p63s23p64s23d104p45s24d105p2C 1s22s22p63s23p64s23d104p65s24d105p1D 1s22s22p53s23p64s23d104p64d105p1 The Correct [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221122","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221122","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221122"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221122\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221122"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221122"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221122"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}