{"id":221324,"date":"2025-05-29T12:05:36","date_gmt":"2025-05-29T12:05:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221324"},"modified":"2025-05-29T12:05:38","modified_gmt":"2025-05-29T12:05:38","slug":"determine-the-point-group-of-sf5cl","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/29\/determine-the-point-group-of-sf5cl\/","title":{"rendered":"Determine the point group of SF5Cl."},"content":{"rendered":"\n<p>Determine the point group of SF5Cl.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The point group of <strong>SF\u2085Cl<\/strong> is <strong>C\u2084v<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To determine the point group of <strong>SF\u2085Cl<\/strong> (sulfur pentafluoride chloride), we begin by analyzing its <strong>molecular geometry<\/strong> and <strong>symmetry elements<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Molecular Geometry:<\/strong><\/h4>\n\n\n\n<p>SF\u2085Cl is a derivative of SF\u2086 (sulfur hexafluoride), which has an <strong>octahedral<\/strong> geometry. In SF\u2085Cl, one of the six fluorine atoms in SF\u2086 is replaced with a chlorine atom. This still results in an <strong>octahedral arrangement<\/strong> of six ligands around the central sulfur atom. However, because chlorine is different from fluorine, the molecule is <strong>no longer symmetric in all directions<\/strong> like SF\u2086.<\/p>\n\n\n\n<p>To minimize repulsion (as chlorine is larger than fluorine), the Cl atom preferentially occupies an <strong>axial<\/strong> position. So the structure has a square pyramidal shape with:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Four fluorine atoms in the <strong>equatorial plane<\/strong>,<\/li>\n\n\n\n<li>One axial fluorine above,<\/li>\n\n\n\n<li>One axial chlorine below the sulfur atom.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Symmetry Elements in SF\u2085Cl:<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>C\u2084 axis<\/strong>: A fourfold rotation axis through the sulfur atom and perpendicular to the equatorial plane (passes through the axial F and Cl atoms).<\/li>\n\n\n\n<li><strong>\u03c3\u1d65 planes (vertical mirror planes)<\/strong>: Four mirror planes exist\u2014two that pass through opposite equatorial F atoms and the axial atoms (F and Cl), and two that bisect the angles between equatorial F atoms.<\/li>\n\n\n\n<li><strong>No center of inversion<\/strong> (i), because replacing one F with Cl breaks that symmetry.<\/li>\n\n\n\n<li><strong>No horizontal mirror plane (\u03c3h)<\/strong>, again due to the Cl substitution.<\/li>\n<\/ul>\n\n\n\n<p>With a <strong>C\u2084 principal axis<\/strong> and <strong>four \u03c3\u1d65 planes<\/strong>, this matches the <strong>C\u2084v<\/strong> point group.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Why Not Other Groups?<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Oh<\/strong>: SF\u2086 has this, but SF\u2085Cl lacks the full symmetry.<\/li>\n\n\n\n<li><strong>C\u2084h, D\u2084h<\/strong>: These require \u03c3h planes or inversion centers, which SF\u2085Cl lacks.<\/li>\n\n\n\n<li><strong>C\u2084<\/strong>: Lacks the mirror planes present in SF\u2085Cl.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><strong>Point group of SF\u2085Cl = C\u2084v<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner4-101.jpeg\" alt=\"\" class=\"wp-image-221326\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Determine the point group of SF5Cl. The Correct Answer and Explanation is: The point group of SF\u2085Cl is C\u2084v. Explanation To determine the point group of SF\u2085Cl (sulfur pentafluoride chloride), we begin by analyzing its molecular geometry and symmetry elements. 1. Molecular Geometry: SF\u2085Cl is a derivative of SF\u2086 (sulfur hexafluoride), which has an octahedral [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221324","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221324","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221324"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221324\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221324"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221324"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221324"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}